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10 tháng 5 2020
a, \(\frac{3}{5}+\frac{-4}{15}=\frac{9}{15}-\frac{4}{15}=\frac{5}{15}=\frac{1}{3}\)
b, \(\frac{-1}{3}+\frac{2}{5}+\frac{2}{15}=\frac{-5}{15}+\frac{6}{15}+\frac{2}{15}=\frac{3}{15}=\frac{1}{5}\)
c, \(\frac{-3}{5}+\frac{7}{21}+\frac{-4}{5}+\frac{7}{5}=\frac{-3}{5}+\frac{1}{3}+\frac{-4}{5}+\frac{7}{5}=\left(\frac{-3}{5}+\frac{-4}{5}+\frac{7}{5}\right)+\frac{1}{3}=\frac{1}{3}\)
d, \(\frac{2}{7}+\frac{1}{9}+\frac{3}{7}+\frac{5}{9}+\frac{-5}{6}=\left(\frac{2}{7}+\frac{3}{7}\right)+\left(\frac{1}{9}+\frac{5}{9}\right)+\frac{-5}{6}=\frac{5}{7}+\frac{6}{9}+\frac{-5}{6}=\frac{90}{126}+\frac{84}{126}+\frac{-105}{126}=\frac{69}{126}=\frac{23}{42}\)
e, \(\frac{-5}{7}+\frac{3}{4}+\frac{-1}{5}+\frac{-2}{7}+\frac{1}{4}=\left(\frac{-5}{7}+\frac{-2}{7}\right)+\left(\frac{3}{4}+\frac{1}{4}\right)+\frac{-1}{5}=\left(-1\right)+1+\frac{-1}{5}=\frac{-1}{5}\)
f, \(\frac{-3}{31}+\frac{-6}{17}+\frac{1}{25}+\frac{-28}{31}+\frac{-1}{17}+\frac{-1}{5}=\left(\frac{-3}{31}+\frac{-28}{31}\right)+\left(\frac{-6}{17}+\frac{-1}{17}\right)+\left(\frac{1}{25}+\frac{-1}{5}\right)=\left(-1\right)+\frac{-7}{17}+\frac{-4}{25}=\frac{-425}{425}+\frac{-175}{425}+\frac{-68}{425}=\frac{-668}{425}\)
Chúc bn học tốt
21 tháng 7 2018
a) \(\frac{x-5}{7}=\frac{5}{3}\)
\(\Rightarrow\left(x-5\right)\cdot3=7\cdot5\)
\(\Rightarrow3x-15=35\)
\(\Rightarrow3x=15+35\)
\(\Rightarrow3x=50\)
\(\Rightarrow x=\frac{50}{3}\)
b) \(\frac{x-3}{3}=\frac{12}{x-3}\)
\(\Rightarrow\left(x-3\right)\cdot\left(x-3\right)=3\cdot12\)
\(\Rightarrow\left(x-3\right)^2=36\)
\(\Rightarrow\left(x-3\right)^2=6^2\)hoặc \(\left(x-3\right)^2=\left(-6\right)^2\)
\(\Rightarrow x-3=6\) \(x-3=-6\)
\(\Rightarrow x=6+3\) \(x=-6+3\)
\(\Rightarrow x=9\) hoặc \(x=-3\)
21 tháng 7 2018
c) \(\frac{5-2x}{4}=\frac{7}{3}\)
\(\Rightarrow\left(5-2x\right)\cdot3=4\cdot7\)
\(\Rightarrow15-6x=28\)
\(\Rightarrow6x=15-28\)
\(\Rightarrow6x=-13\)
\(\Rightarrow x=-\frac{13}{6}\)
d) \(\frac{x+1}{4}=\frac{7}{3}\)
\(\Rightarrow\left(x+1\right)\cdot3=2\cdot7\)
\(\Rightarrow3x+3=28\)
\(\Rightarrow3x=28-3\)
\(\Rightarrow3x=25\)
\(\Rightarrow x=\frac{25}{3}\)
Chúc bạn học tốt !!!
LK
1
25 tháng 3 2021
a) Ta có: \(\dfrac{-3}{5}x+\dfrac{-7}{4}=\dfrac{3}{10}\)
\(\Leftrightarrow\dfrac{-3}{5}x=\dfrac{3}{10}+\dfrac{7}{4}=\dfrac{41}{20}\)
\(\Leftrightarrow x=\dfrac{41}{20}:\dfrac{-3}{5}=\dfrac{41}{20}\cdot\dfrac{-5}{3}\)
hay \(x=-\dfrac{41}{12}\)
Vậy: \(x=-\dfrac{41}{12}\)
28 tháng 2 2022
a: -3/4x12=-36/4=-9
b: \(=\dfrac{7}{15}\cdot\dfrac{10}{21}=\dfrac{7}{21}\cdot\dfrac{10}{15}=\dfrac{1}{3}\cdot\dfrac{2}{3}=\dfrac{2}{9}\)
c: \(=\dfrac{7}{18}\cdot\dfrac{12}{21}=\dfrac{12}{18}\cdot\dfrac{7}{21}=\dfrac{2}{3}\cdot\dfrac{1}{3}=\dfrac{2}{9}\)
d: \(=\dfrac{11}{15}\cdot\dfrac{5}{22}=\dfrac{11}{22}\cdot\dfrac{5}{15}=\dfrac{1}{2}\cdot\dfrac{1}{3}=\dfrac{1}{6}\)
e: \(=-\dfrac{8}{15}\cdot\dfrac{5}{4}=\dfrac{-40}{60}=\dfrac{-2}{3}\)
f: \(=-15\cdot\dfrac{3}{5}=-9\)
PV
1
21 tháng 4 2022
a, \(\dfrac{-3}{5}+\dfrac{5}{7}\)
\(=\dfrac{4}{35}\)
b, \(-5+\dfrac{1}{6}\)
= \(\dfrac{-29}{6}\)
c, \(\dfrac{1}{8}-\dfrac{1}{2}\)
= \(\dfrac{-3}{8}\)
c, \(\dfrac{5}{12}-\dfrac{-7}{6}\)
= \(\dfrac{19}{12}\)
d, \(-2.\dfrac{3}{7}\)
= \(\dfrac{-6}{7}\)
4 phần 35
\(\frac{-3}{5}+\frac{5}{7}=-\frac{21}{35}+\frac{25}{35}=\frac{4}{35}\)