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a) ( 72 - 8 x 9 ) : ( 20 + 21 + 22 + 23 + 24 + 25 )
= ( 72 - 72 ) : ( 20 + 21 + 22 + 23 + 24 + 25 )
= 0 : ( 20 + 21 + 22 + 23 + 24 + 25 )
= 0
b) ( 500 x 9 - 250 x 18 ) x ( 1 + 2 + 3 + ... + 9 )
= ( 500 x 9 - 250 x 2 x 9 ) x ( 1 + 2 + 3 + ... + 9 )
= ( 500 x 9 - 500 x 9 ) x ( 1 + 2 + 3 + ... + 9 )
= 0 x ( 1 + 2 + 3 + ... + 9 )
= 0
b) X x 3,7 + X x 6,3 = 120 |
X x ( 3,7 + 6,3 ) = 120
X x 10 = 120
X = 120 : 10
X = 12
Vậy X = 12
Bài 2:
\(B=\left(1-\frac{1}{2}\right).\left(1-\frac{1}{3}\right).\left(1-\frac{1}{4}\right).......\left(1-\frac{1}{2004}\right)\)
\(=\frac{1}{2}.\frac{2}{3}.\frac{3}{4}....\frac{2003}{2004}\)
\(=\frac{1}{2004}\)
\(A=\frac{1\times111+2\times110+3\times109+...+111\times1}{1+\left(1+2\right)+\left(1+2+3\right)+...+\left(1+2+3+...+111\right)}\)
\(A=\frac{1\times111+2\times110+3\times109+...+111\times1}{\left(1+1+...+1\right)+\left(2+2+...+2\right)+...+111}\)(\(111\)số hạng \(1\), \(110\)số hạng \(2\),...)
\(A=\frac{1\times111+2\times110+3\times109+...+111\times1}{1\times111+2\times110+3\times109+...+111\times1}\)
\(A=1\)
\(1)\)
\(-3-18\)
\(=-(3+18)\)
\(=-21\)
\(-7\times-5\)
\(=7\times(-1)\times(-5)\)
\(=7\times5\)
\(=35\)
\(5+(-11)\)
\(=5-11\)
\(=-6\)
1,
a) -3 - 18=-21
b) (-7).(-5)=35
c) 5+(-11)=-6
2,
a) -2-13+(-14)-19=-48
b) 221 + 4[(-5).8-4]=45
c) (-2)3.(-2)2+32=0
d) -15.12 - 8.(-12)=-84
3,
a) x:(-2)=9
=>x =9.(-2)
=>x =-18
b)4x+(-8)=24
=>4x =24-(-8)
=>4x =32
=>x =32:4
=>x =8
c) (3x)(x+7)=0
\(\Rightarrow\hept{\begin{cases}3x=0\\x+7=0\end{cases}\Rightarrow\hept{\begin{cases}x=0:3\\x=0-7\end{cases}\Rightarrow}\hept{\begin{cases}x=0\\x=-7\end{cases}}}\)
a)2^x-15=17
2^x=17+15=32
2^x=32=>x=5(vì 2^5=32)
b)mk ko bt cách giải
c)7^2-(15+x)=5.2^2
49-(15+x)=5.4=20
15+x=49-20
15+x=29
d)mk cx ko bt cách giải nhưng mk bt x=2(bn thử lại là bt)
b) (7x-11)3= 25.52+200
(7x-11)3 = 25.52 + 23.52
(7x-11)3 = 23.52( 22+1)
(7x-11)3 = 8 . 25 . 5
(7x-11)3 = 1000
(7x-11)3 = 103
=> 7x-11 = 10
7x = 10+11
7x = 21
x= 3
d) (2x+1)3 = 125
(2x+1)3 = 53
=> 2x + 1 = 5
=> 2x = 5-1
2x = 4
x=2
\(\frac{1}{8}+\frac{1}{24}+\frac{1}{48}+\frac{1}{80}+\frac{1}{120}\)
\(=\frac{1}{2}(\frac{1}{2.4}+\frac{1}{4.6}+\frac{1}{6.8}+\frac{1}{8.10}+\frac{1}{10.12})\)
\(=\frac{1}{2}(\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+..+\frac{1}{10}-\frac{1}{12})\)
\(=\frac{1}{2}\cdot\left(\frac{1}{2}-\frac{1}{12}\right)=\frac{1}{2}\cdot\frac{5}{12}=\frac{5}{24}\)
\(1200:24-\left(19-x\right)=38\)
\(\Leftrightarrow50-\left(19-x\right)=38\)
\(\Leftrightarrow19-x=50-38\)
\(\Leftrightarrow19-x=12\)
\(\Leftrightarrow x=7\)