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a) \(27-48=-21\)
b) \(29-\left(+39\right)=-10\)
c) \(-15-\left(-21-46\right)=52\)
a: =46-16+35-5=30+30=60
b: =32-12+34-14+36-16+38-18-10
=20+20+20+20-10
=80-10=70
c: \(=125-125-170+120=-50\)
d: =(-1)+(-1)+...+(-1)
=-50
#\(N\)
`a, 4573 + 46 - 4573 + 35 - 16 - 5`
`= (4573-4573) + (46 - 16)+(35-5)`
`= 0 +30+30 = 60`
`b, 32+34+36+38-10-12-14-16-18`
`= (32-12)+(34-14)+(38-18)+10`
`= 20+20+20+10 = 70`
`c, 125-170+120+(-125)`
`= (125 + -125)-170+120`
`= 0-170+120`
`=-170 + 120 = -50`
`d, 1-2+3-4+...-98+99-100`
Các số hạng có trong biểu thức: \(\left(100-1\right)\div1+1=100\) `(` số hạng `)`
`=> (1-2)+(3-4)+...+(97-98)+(99-100)`
Các cặp mà trong bthuc có là: \(100\div2=50\)
`=> (-1)+(-1)+...(-1)+(-1) = (-50)`
`e,`
*Mình xp sửa đề phải là `1-5 + 7-11+...+997-1001` nhỉ? Vì để như vậy nó lẻ á ._.
`1-5+7-11+...+997-1001`
Các số hạng có trong biểu thức là: \(\left(1001-1\right)\div4+1=251\) `(` số `)`
`-> (1-5)+(7-11)+...+(997-1001)`
Các cặp được ghép ở trong bthuc là: \(251\div2=125,5\)
`-> (-4)+(-4)+...+(-4) = (-4)*125,5 = -502`
Câu 1 :
a) 25 - (-75) + 32 - (32 + 75)
= 25 + 75 + 32 - 32 - 75
= 25 + (75 - 75) + (32 - 32)
= 25 + 0 + 0
= 25
b) |-127| - 18 . (5 - 6)
= 127 - 18 . (-1)
= 127 + 18
= 145
c) 24.(16 - 5) - 16.(24 - 5)
= 24.11 - 16.19
= 16.16,5 - 16.19
= 16.(16,5 - 19)
= 16.(-2,5)
= -40
ủng hộ tớ nha
kb nha
a)25-(-75)+32-(32+75)=25-(-75)+32-107=25
b)l-127l-18.(5-6)=127-18.(-1)=127-(-18)=145
c)24.(16-5)-16.(24-15)=24.11-16.9=264-144=120
Câu 1:
a) 25-(30+x) = x-(27-8)
25-30-x = x-19
-5-x = x-19
(-5)+19 = x+x
14 = 2x
x = 7
Vậy x = 7
b) (x-12)-15 = (20-7)-(18+x)
x-12-15 = 13-18-x
x-(12+15)= -5-x
x-27 = -5-x
x+x = -5+27
2x = 22
x = 11
Câu 2:
a) 4573+46-4573+35-16-5
= (4573-4573)+(46-16)+(35-5)
= 0+30+30
= 60
b) 32+34+36+38-10-12-14-16-18
= (32-12)+(34-14)+(36-16)+(38-18)-10
= 10+10+10+10-10
= 30
1, a) 25 - (30 + x) = x - (27 - 8)
25 - 30 - x = x - 27 + 8
-x - x = -27 + 8 - 25 + 30
-2x = -14
x = -14 : (-2)
x = 7
b) (x - 12) - 15 = (20 - 7) - (18 + x)
x - 12 - 15 = 20 - 7 - 18 - x
x + x = 20 - 7 - 18 + 12 + 15
2x = 22
x = 22 : 2
x = 11
2, a) 4573 + 46 - 4573 + 35 - 16 - 5
= (4573 - 4573) + (46 - 16) + (35 - 5)
= 0 + 30 + 30
= 60
b) 32 + 34 + 36 + 38 - 10 - 12 - 14 - 16 - 18
= (32 - 10) + (34 - 12) + (36 - 14) + (38 - 16) - 18
= 22 + 22 + 22 + 22 - 18
= 22 x 4 - 18
= 88 - 18
= 70
12=22.3
15=3.5
21=3.7
32=25
46=2.23
98=2.72
120=23.3.5
127=127(nó nguyên tố)
214=2.107
275=52.11
312=23.3.13
450=2.32.52
900=22.32.52
a, 2 3 x + 5 2 x = 2 5 2 + 2 3 - 33
8x+25x = 33
33x = 33
x = 1
b, 260 : x + 4 = 5 2 3 + 5 - 3 3 2 + 2 2
260:(x+4) = 5.13–3.13
x+4 = 260:26
x+4 = 10
x = 6
c, 720 : [ 41 - 2 x - 5 ] = 2 3 . 5
41–(2x–5) = 720:40
2x–5 = 41–18
2x = 28
x = 14
d, 3 2 - 2 x - 12 + 35 = 5 2 + 279 : 3 2
7(x–12)+35 = 56
7(x–12) = 21
x–12 = 3
x = 15
1.
a) \(125+80+375+220\)
\(=\left(125+375\right)+\left(80+220\right)\)
\(=500+300\)
\(=800\)
b) \(25.11.8.4.125\)
\(=\left(25.4\right).\left(8.125\right).11\)
\(=100.1000.11\)
\(=1100000\)
c) \(18.74+18.27-18\)
\(=18.\left(74+27-1\right)\)
\(=18.100\)
\(=1800\)
d) \(75.23+75.77-500\)
\(=75.\left(23+77\right)-500\)
\(=75.100-500\)
\(=7500-500\)
\(=7000\)
e) \(150:\left[25.\left(18-4^2\right)\right]\)
\(=150:\left[25.\left(18-16\right)\right]\)
\(=150:\left[25.2\right]\)
\(=150:50\)
\(=3\)
f) \(125.23.2.8.50\)
\(=\left(125.8\right).\left(2.50\right).23\)
\(=1000.100.23\)
\(=2300000\)
g) \(235+88+165+12\)
\(=\left(235+165\right)+\left(88+12\right)\)
\(=400+100\)
\(=500\)
h) \(71.32+71.68-1100\)
\(=71.\left(32+68\right)-1100\)
\(=71.100-1100\)
\(=7100-1100\)
\(=6000\)
i) \(6^7:6^6+4^3.2-24^0\)
\(=6+64.2-1\)
\(=6+128-1\)
\(=133\)
j) \(546-6.\left[158:\left(30+7^2\right)\right]\)
\(=546-6.\left[158:\left(30+49\right)\right]\)
\(=546-6.\left[158:79\right]\)
\(=546-6.2\)
\(=546-12\)
\(=534\)
k) \(268+147+132+253\)
\(=\left(268+132\right)+\left(147+253\right)\)
\(=400+400\)
\(=800\)
2.
a) \(7x=707\)
\(x=707:7\)
\(x=101\)
b) \(6x+5=47\)
\(6x=47-5\)
\(6x=42\)
\(x=42:6\)
\(x=7\)
c) \(35:\left(x+1\right)=7\)
\(x+1=35:7\)
\(x+1=5\)
\(x=5-1\)
\(x=4\)
d) \(12+\left(29-3x\right)=35\)
\(29-3x=35-12\)
\(29-3x=23\)
\(3x=29-23\)
\(3x=6\)
\(x=6:3\)
\(x=2\)
e) \(2.4^x+10^1=138\)
\(2.4^x=138-10\)
\(2.4^x=128\)
\(4^x=128:2\)
\(4^x=64=4^3\)
\(\Rightarrow x=3\)
f) \(7x=140\)
\(x=140:7\)
\(x=20\)
g) \(7\left(15-x\right)+14=84\)
\(7\left(15-x\right)=84-14\)
\(7\left(15-x\right)=70\)
\(15-x=70:7\)
\(15-x=10\)
\(x=15-10\)
\(x=5\)
h) \(3^x.5-15=390\)
\(3^x.5=390+15\)
\(3^x.5=405\)
\(3^x=405:5\)
\(3^x=81=3^4\)
\(\Rightarrow x=4\)