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Đặt A=\(\frac{1}{3^1}+\frac{1}{3^2}+\frac{1}{3^3}+....+\frac{1}{3^{99}}\)
3A=\(\frac{1}{3^2}+\frac{1}{3^3}+\frac{1}{3^4}+....+\frac{1}{3^{98}}\)
2A = 3A - A = \(\frac{1}{3}-\frac{1}{3^{98}}\)<\(\frac{1}{2}\)
=> A = \(\frac{\frac{1}{3}-\frac{1}{3^{98}}}{2}<\frac{1}{2}\)(đpcm)
Đặt B=2100-299+298-297+.....+22-2
2A=2101-2100+299-298+...+23-22
3A=2A+A=2101-2
=> A=\(\frac{2^{101}-2}{3}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(A=3+3^2+...+3^{50}\)
\(\Rightarrow3A=3^2+3^3+...+3^{50}+3^{51}\)
\(\Rightarrow3A-A=3^{51}-3\)
\(\Rightarrow2A=3^{51}-3\)
\(\Rightarrow A=\frac{3^{51}-3}{2}\)
\(B=2-2^2+2^3-2^4+...+2^{2019}-2^{2020}\)
\(2B=2^2-2^3+2^4-2^5+...+2^{2020}-2^{2021}\)
\(B+2B=2-2^{2021}\)
\(3B=2-2^{2021}\)
\(B=\frac{2-2^{2021}}{3}\)
\(C=\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{2008.2009}\)
\(C=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{2008}-\frac{1}{2009}\)
\(C=1-\frac{1}{2009}\)
\(C=\frac{2008}{2009}\)
\(D=\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}+\frac{1}{7.9}+\frac{1}{9.11}\)
\(D=\frac{1}{2}\left(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}\right)\)
\(D=\frac{1}{2}\left(\frac{1}{1}-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}\right)\)
\(D=\frac{1}{2}\left(1-\frac{1}{11}\right)\)
\(D=\frac{1}{2}.\frac{10}{11}=\frac{5}{11}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 15 + 23 = 1 + 8 = 9 = 32 ( là số chính phương )
b) 52 + 122 = 25 + 144 = 169 = 132 ( là số chính phương )
c) 26 + 62 = 64 + 36 = 100 = 1002 ( là số chính phương )
d) 13 + 23 + 33 + 43 + 53 + 63
= 1 + 8 + 27 + 64 + 125 + 216
= 441 = 212 ( là số chính phương )
a) 15 + 23=1 + 8 = 9 (là số chính phương)
b) 52 + 122= 25 + 144= 169 (là số chính phương)
c) 26 + 62= 64 + 36=100 (là số chính phương)
d) 142 – 122= 196 - 144=52 (không là số chính phương)
e) 13 + 23 + 33 + 43 + 53 + 63= 1 + 8 + 27 + 64 + 125 + 216 = 411 (là số chính phương)
![](https://rs.olm.vn/images/avt/0.png?1311)
ta có: M = 1/3 - 2/3^2 + 3/3^3 - 4/3^4 +......+ 99/3^99 - 100/3^100
=> 3.M = 1 - 2/3 + 3/3^2 - 4/3^3 +.......+ 99/3^98 - 100/3^99
=> 3M + M = ( 1 - 2/3 + 3/3^2 - 4/3^3 +.........+ 99/3^98 - 100/3^99 ) + ( 1/3 - 2/3^2 + 3/3^3 - 4/3^4 +....+ 99/3^99 - 100/3^100 )
=> 4.M = 1- 1/3 + 1/3^2 - 1/3^3 +........+ 1/3^98 - 1/3^99 - 100/3^100
=> 12.M = 3 - 1 + 1/3 - 1/3^2 +.......+ 1/3^97 - 1/3^98 - 1/3^99
=> 12M + 4M = ( 3 - 1 + 1/3 - 1/3^2 +......+ 1/3^97 - 1/3^98 - 1/3^99 ) + ( 1 - 1/3 + 1/3^2 - 1/3^3 +.......+ 1/3^99 - 1/3^100 )
=> 16M = 3 - 101/3^99 - 100/3^100
vù 16M < 3
=> M < 3/16
vậy M < 3/16
tk cho mk nha,mk bị âm rùi
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{-9}{4}\).\(19\frac{2}{5}\)+\(\left(\frac{-3}{2}\right)^2\).\(\left(-14\frac{3}{5}\right)\)-\(\left(\frac{99}{100}\right)^0\)
=\(\frac{-9}{4}\).\(\frac{97}{5}\)+\(\frac{9}{4}\).\(\frac{-73}{5}\)-1
=\(\frac{-9}{4}\).\(\frac{97}{5}\)+\(\frac{-9}{4}\).\(\frac{73}{5}\)-1
=\(\frac{-9}{4}\).(\(\frac{97}{5}\)+\(\frac{73}{5}\))
=\(\frac{-9}{4}\).34
=\(\frac{-153}{2}\)
Học tốt
![](https://rs.olm.vn/images/avt/0.png?1311)
B = 3-32+33-34+....+399-3100
3B = 32-33+34-35+....+3100-3101
4B = 3B + B = 3 - 3101
=> B = \(\frac{3-3^{101}}{4}\)
A = 1 + 3 + 32 +......+ 399 + 3100
A = 3(0+1+2+3+.......+99)
A =3. 4950
A = 14850
học tốt nha