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\(\Leftrightarrow\)\((x+2):100=34,01\)
\(\Leftrightarrow\)\(x+2=3401\)
\(\Leftrightarrow\)\(x=3399\)
a, 2x+ 1/4 = 3/2
2x = 3/2-1/4
2x = 5/4
x=5/4:2
x= 5/8
b, (x-5) - 1/3 = 2/5
x-5= 2/5+1/3
x-5=11/15
x=11/15+5
x=86/15
c, (4,5-2x):3/4=4/3
(4,5-2x)=4/3. 3/4
4,5-2x=1
2x= 5,5
x=5,5:2
x=2,75
a) 2x+1/4=3/2
=> 2x =3/2-1/4
=> 2x =5/4
=> x =5/4:2
=> x =5/8
b) (x-5)-1/3=2/5
=> x-5 =2/5+1/3
=> x-5 =11/15
=> x =11/15+5
=> x =86/15
c) (4,5-2x):3/4=4/3
=> 4,5-2x =4/3x3/4
=> 4,5-2x =1
=> 2x =4,5-1
=> 2x =3,5
=> x =3,5:2
=> x =1,75
(\(x\) + \(\dfrac{3}{5}\))2 + \(\dfrac{41}{25}\) = 9%: 4,5%
(\(x\) + \(\dfrac{3}{5}\))2 + \(\dfrac{41}{25}\) = 2
(\(x\) + \(\dfrac{3}{5}\))2 = 2 - \(\dfrac{41}{25}\)
(\(x\) + \(\dfrac{3}{5}\))2 = \(\dfrac{9}{25}\)
\(\left[{}\begin{matrix}x+\dfrac{3}{5}=\dfrac{3}{5}\\x+\dfrac{3}{5}=-\dfrac{3}{5}\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=\dfrac{3}{5}-\dfrac{3}{5}\\x=-\dfrac{3}{5}-\dfrac{3}{5}\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=0\\x=-\dfrac{6}{5}\end{matrix}\right.\)
Vậy \(x\in\) {-1; \(\dfrac{1}{5}\)}
`a)-4/9(5/6*90%-8:0,32)`
`=-4/9(5/6*9/10-8:8/25)`
`=-4/9(3/4-25)`
`=-4/9*(-97)/4=97/9`
`b)(2/5)^2+5 1/2.(4,5-2)+(2^3)/(-4)`
`=4/25+11/2*5/2+8/(-4)`
`=4/25+55/4-2`
`=1191/100`
\(a.\dfrac{5}{3}.8,1=\dfrac{40,5}{3}\)
\(b.\dfrac{8}{5}.\left(-4,5\right)=\dfrac{-36}{5}\)
\(c.\dfrac{14}{5}.75\%=\dfrac{10,5}{5}=2,1\)
\(d.\dfrac{11}{8}.\dfrac{37}{12}=\dfrac{407}{96}\)
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