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a: \(=\dfrac{3}{5}:\dfrac{7}{5}=\dfrac{3}{5}\cdot\dfrac{5}{7}=\dfrac{3}{7}\)
b: \(=\dfrac{9}{17}\left(\dfrac{8}{5}-\dfrac{3}{5}\right)+\dfrac{8}{17}\)
=9/17+8/17=1
c: =>x-3/10=7/15*1/5=7/75
=>x=7/75+3/10=59/150
a) \(\dfrac{2}{3}x-\dfrac{1}{2}=\dfrac{1}{10}\)
\(\dfrac{2}{3}x=\dfrac{1}{10}+\dfrac{1}{2}=\dfrac{3}{5}\)
\(x=\dfrac{3}{5}:\dfrac{2}{3}=\dfrac{9}{10}\)
b) \(\dfrac{39}{7}:x=13\)
\(x=\dfrac{\dfrac{39}{7}}{13}=\dfrac{3}{7}\)
c) \(\left(\dfrac{14}{5}x-50\right):\dfrac{2}{3}=51\)
\(\dfrac{14}{5}x-50=51\cdot\dfrac{2}{3}=34\)
\(\dfrac{14}{5}x=34+50=84\)
\(x=\dfrac{84}{\dfrac{14}{5}}=30\)
d) \(\left(x+\dfrac{1}{2}\right)\left(\dfrac{2}{3}-2x\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{2}=0\\\dfrac{2}{3}-2x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{2}\\x=\dfrac{1}{3}\end{matrix}\right.\)
e) \(\dfrac{2}{3}x-\dfrac{1}{2}x=\dfrac{5}{12}\)
\(\dfrac{1}{6}x=\dfrac{5}{12}\)
\(x=\dfrac{5}{12}:\dfrac{1}{6}=\dfrac{5}{2}\)
g) \(\left(x\cdot\dfrac{44}{7}+\dfrac{3}{7}\right)\dfrac{11}{5}-\dfrac{3}{7}=-2\)
\(\left(x\cdot\dfrac{44}{7}+\dfrac{3}{7}\right)\cdot\dfrac{11}{5}=-2+\dfrac{3}{7}=-\dfrac{11}{7}\)
\(x\cdot\dfrac{44}{7}+\dfrac{3}{7}=-\dfrac{11}{7}:\dfrac{11}{5}=-\dfrac{5}{7}\)
\(\dfrac{44}{7}x=-\dfrac{5}{7}-\dfrac{3}{7}=-\dfrac{8}{7}\)
\(x=-\dfrac{8}{7}:\dfrac{44}{7}=-\dfrac{2}{11}\)
h) \(\dfrac{13}{4}x+\left(-\dfrac{7}{6}\right)x-\dfrac{5}{3}=\dfrac{5}{12}\)
\(\dfrac{25}{12}x-\dfrac{5}{3}=\dfrac{5}{12}\)
\(\dfrac{25}{12}x=\dfrac{5}{12}+\dfrac{5}{3}=\dfrac{25}{12}\)
\(x=1\)
Mỏi tay woa bn làm nốt nha!!
a) (18+12.3):9-5
=(18+36):9-5
=54:9-5
=6-5
=1
b) 368+42:7-(23+3)
= 368+42:7-(8+3)
= 368+42:7-11
= 368+6-11
=374-11
=363
c) 324 :322+3.4+3560
=324-22+12+1
=32+12+1
=9+12+1
=21+2
=22
d) 210:25-75:25+3.3
=210-5-3+9
=25-3+9
=32-3+9
=29+9
=38
e) 1449-[(216+184):23].32
=1449-(400:8).9
=1449-50.9
=1449-450
=999
f) 600-400:[118.2-2(50.3-9.16)2]
=600-400:[118.2-2(150-144)2]
=600-400:(118.2-2.62)
=600-400:(118.2-2.36)
=600-400:(236-72)
=600-400:164
=600-100/41
=24500/41 (đề sai)
g) 2001.27+2001.63+2001.10
=2001.(27+63+10)
=2001.100
=200100
h) 64.54+47.64-64
=64.(54+47-1)
=64.100
=6400
i) (-17)+15+68+17+(-15)
=(-17+17)+(-15+15)+68
=0+0+68
=68
j) (-17)+|-5|+|10|+(-11)
= (-17)+5+10+(-11)
=-12+10+(-11)
=-2+(-11)
=-13
k) -75+(-9)+4
=-84+4
=-80
l) -100+(-15+10)+|(-48)+(-22)|
=-100+(-5)+|-70|
=-100+(-5)+70
=-105+70
=-35
a) (18+12.3):9-5
=(18+36):9-5
=54:9-5
=6-5
=1
b) 368+42:7-(23+3)
= 368+42:7-(26)
=368+6-64
=374-64
=310
c) 324 :322+3.4+3560
=32+12+1
=9+12+1
=21+1
=22
d) 210:25-75:25+3.3
=25-3+9
=32-3+9
=29+9
=38
e) 1449-[(216+184):23].32
= 1449-[400:8].9
=1449-50.9
=1449-450
=999
f) 600-400:[118.2-2(50.3-9.16)2]
=600-400:[118.2-2.(150-9.16)2]
=600-400:[118.2-2.(150-144)2]
=600-400:[118.2-2.62]
=600-400:[118.2-2.36]
=600-400:[236-72]
=600-400:164
=Đề sai nha bạn
g) 2001.27+2001.63+20010
=2001.(27+63)+20010
=2001.100+20010
=200100+20010
=220110
h) 64.54+47.64-64
=64.(54+47-1)
=64.(101-1)
=64.100
=6400
i) (-17)+115+68+17+(-15)
=98+68+17+(-15)
=166+17+(-15)
=183+(-15)
=168
j) (-17)+|-5-|+|10|+(-11)
=(-17)+5+10+(-11)
=(-12)+5+10+(-11)
=-7+10+(-11)
=3+(-11)
=-8
k) -75+|(-9)+4|
=-75+|-5|
=-75+5
=-70
l) -100+(-15+10)+|(-48)+(-22)|
= -100+(-15+10)+|-70|
= -100+(-15+10)+70
=-100+(-5)+70
=-105+70
=-35
1) \(A=\left\{136-32.\left[\left(25:25+17.2016^0\right):3-3\right]\right\}:102.52\)
\(\Rightarrow A=\left\{136-32.\left[\left(1+17\right):3-3\right]\right\}:102.52\)
\(\Rightarrow A=\left[136-32.\left(18:3-3\right)\right]:102.52\)
\(\Rightarrow A=\left[136-32.\left(6-3\right)\right]:102.52\)
\(\Rightarrow A=\left(136-32.3\right):102.52\)
\(\Rightarrow A=\left(136-96\right):102.52\)
\(\Rightarrow A=40:102.52\)
\(\Rightarrow A=\dfrac{20}{51}.52\)
\(\Rightarrow A=\dfrac{1040}{51}\)
\(-\dfrac{9}{25}\cdot17\dfrac{2}{3}-\left(-\dfrac{3}{5}\right)^2\cdot\dfrac{22}{3}\)
\(=-\dfrac{9}{25}\cdot\dfrac{53}{3}-\dfrac{9}{25}\cdot\dfrac{22}{3}\)
\(=-\dfrac{9}{25}\left(\dfrac{53}{3}+\dfrac{22}{3}\right)=-\dfrac{9}{25}\cdot25=-9\)