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a)\(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}\)
\(=\frac{5}{6}+\frac{1}{4}\)
\(=\frac{13}{12}\)
b)\(\frac{6}{5}+\frac{4}{3}+\frac{9}{7}\)
\(=\frac{38}{15}+\frac{9}{7}\)
\(=\frac{401}{105}\)
c)\(\frac{90}{108}-\frac{40}{72}\)
\(=\frac{5}{6}+\frac{5}{9}\)
\(=\frac{25}{18}\)
~~~~~~~~~~~ai đi ngang qua nhớ để lại k ~~~~~~~~~~~~~
~~~~~~~~~~~~ Chúc bạn sớm kiếm được nhiều điểm hỏi đáp ~~~~~~~~~~~~~~~~~~~
~~~~~~~~~~~ Và chúc các bạn trả lời câu hỏi này kiếm được nhiều k hơn ~~~~~~~~~~~~
\(\frac{1}{10}+\frac{2}{20}+\frac{3}{30}+\frac{4}{40}+\frac{5}{50}+\frac{6}{60}+\frac{7}{70}+\frac{8}{80}+\frac{9}{90}\)
\(=\frac{1}{10}+\frac{1}{10}+\frac{1}{10}+\frac{1}{10}+\frac{1}{10}+\frac{1}{10}+\frac{1}{10}+\frac{1}{10}+\frac{1}{10}\)
\(=\frac{9}{10}\)
\(a)9+\frac{24}{25}=\frac{9\cdot25+24}{25}=\frac{249}{25}\)
\(b)\frac{1}{20}+\frac{1}{4}+\frac{2}{5}=\frac{1}{20}+\frac{5}{20}+\frac{8}{20}=\frac{1+5+8}{20}=\frac{14}{20}=\frac{7}{10}\)
\(c)\frac{7}{12}+4=\frac{7}{12}+\frac{4}{1}=\frac{7+48}{12}=\frac{55}{12}\)
\(d)10+\frac{9}{8}=\frac{10}{1}+\frac{9}{8}=\frac{80+9}{8}=\frac{89}{8}\)
\(e)\frac{1}{4}+\frac{2}{25}+\frac{9}{100}=\frac{25}{100}+\frac{8}{100}+\frac{9}{100}=\frac{25+8+9}{100}=\frac{42}{100}=\frac{21}{50}\)
Còn 3 câu làm tương tự
Ba câu còn lại mình làm luôn :D
\(f)\frac{28}{90}+6=\frac{14}{45}+6=\frac{14}{45}+\frac{6}{1}=\frac{14+270}{45}=\frac{284}{45}\)
\(g)\frac{3}{7}+\frac{4}{9}+\frac{4}{7}+\frac{7}{11}=(\frac{3}{7}+\frac{4}{7})+\frac{4}{9}+\frac{4}{11}=1+\frac{4}{9}+\frac{4}{11}\)
\(=\frac{7}{7}+\frac{4}{9}+\frac{4}{11}=\frac{693+308+252}{693}=\frac{1253}{693}=\frac{179}{99}\)
\(h)\frac{1}{8}+\frac{1}{12}+\frac{3}{8}+\frac{5}{12}=(\frac{1}{8}+\frac{3}{8})+(\frac{1}{12}+\frac{5}{12})=\frac{4}{8}+\frac{6}{12}=\frac{1}{2}+\frac{1}{2}=1\)
Ta có :\(\frac{1}{31}+\frac{1}{32}+\frac{1}{33}+...+\frac{1}{90}=\left(\frac{1}{31}+\frac{1}{32}+...+\frac{1}{60}\right)+\left(\frac{1}{61}+\frac{1}{62}+...+\frac{1}{90}\right)\)
60 số hạng 30 số hạng 30 số hạng
\(>\left(\frac{1}{60}+\frac{1}{60}+...+\frac{1}{60}\right)+\left(\frac{1}{90}+\frac{1}{90}+...+\frac{1}{90}\right)=30.\frac{1}{60}+30.\frac{1}{90}=\frac{1}{2}+\frac{1}{3}=\frac{5}{6}\)
Vậy \(\frac{1}{31}+\frac{1}{32}+\frac{1}{33}+...+\frac{1}{90}>\frac{5}{6}\)
Ta có: \(\frac{1}{31}+\frac{1}{32}+\frac{1}{33}+...+\frac{1}{60}>\frac{1}{60}+\frac{1}{60}+...+\frac{1}{60}=30.\frac{1}{60}=\frac{1}{2}\)
Lại có: \(\frac{1}{61}+\frac{1}{62}+\frac{1}{63}+...+\frac{1}{90}>\frac{1}{90}+\frac{1}{90}+...+\frac{1}{90}=30.\frac{1}{90}=\frac{1}{3}\)
\(\Rightarrow\frac{1}{31}+\frac{1}{32}+\frac{1}{33}+...+\frac{1}{90}>\frac{1}{2}+\frac{1}{3}=\frac{5}{6}\)
\(\Rightarrow\frac{1}{31}+\frac{1}{32}+\frac{1}{33}+...+\frac{1}{90}>\frac{5}{6}\) (đpcm)
Trả lời :
( X + 1 ) + ( X + 2 ) + ( X + 3 ) + ( X + 4 ) + ( X + 5 ) = 90
=> ( X + X + X + X + X ) + ( 1 + 2 + 3 + 4 + 5 ) = 90
=> ( X x 5 ) + 15 = 90
=> X x 5 = 90 - 15
=> X x 5 = 75
=> X = 75 : 5
=> X = 15.
Vậy X = 15.
Học tốt nha~
(x+1)+(x+2)+(x+3)+(x+4)+(x+5)=90
x+1+x+2+x+3+x+4+x+5=90
5x+(1+2+3+4+5)=90
5x+15=90
5x=90-15
5x=75
x=75:5
x=15
Bạn kia áp dụng công thức sai rồi nhé
\(1+2+3+....+n=\frac{n\left(n+1\right)}{2}\)
\(\left(X+1\right)+\left(X+2\right)+\left(X+3\right)+\left(X+4\right)+\left(X+5\right)=90\)
\(\left(X+X+X+X+X\right)+\left(1+2+3+4+5\right)=90\)
\(5X+\frac{5\left(5+1\right)}{2}=90\)
\(5X+15=90\)
\(5X=75\)
\(X=5\)
Vậy X=5
Kagura:Bạn nên nhớ là lớp 4 chưa học dấu <=> nhé !
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????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????
90+90=1800
1/2*1/3*1/4*1/5*1/6=1/720
ai k mk mk k lai
90 + 90 = 90x2 = 180
1/2 x 1/3x1/4x1/5x1/6 = 1/720
Đáp số : a) 180 ; b) 1/720