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ta có A=\(\dfrac{6}{8}\)+\(\dfrac{6}{56}\)+\(\dfrac{6}{140}\)+...+\(\dfrac{6}{1100}\)+\(\dfrac{6}{1400}\)
=\(\dfrac{3}{4}\)+\(\dfrac{3}{28}\)+\(\dfrac{3}{70}\)+...+\(\dfrac{3}{550}\)+\(\dfrac{3}{700}\)
=\(\dfrac{3}{1.4}\)+\(\dfrac{3}{4.7}\)+\(\dfrac{3}{7.10}\)+...+\(\dfrac{3}{22.25}\)+\(\dfrac{3}{25.28}\)
=1-\(\dfrac{1}{4}\)+\(\dfrac{1}{4}\)-\(\dfrac{1}{7}\)+\(\dfrac{1}{7}\)-\(\dfrac{1}{10}\)+...+\(\dfrac{1}{22}\)-\(\dfrac{1}{25}\)+\(\dfrac{1}{25}\)-\(\dfrac{1}{28}\)
=1-\(\dfrac{1}{28}\)
=\(\dfrac{27}{28}\)
Vậy A=\(\dfrac{27}{28}\)
Ta có:
A =6/8+6/56+6/140+...+6/1100+6/1400
⇒A=3/4+3/28+3/70+...+3/550+3/700
⇒A=3/1.4+3/4.7+3/7.10+...+3/22.25+3/25.28
⇒A=1−1/4+1/4−1/7+1/7−1/10+...+1/22−1/25+1/25−1/28
⇒A=1−1/28
⇒A=1-1/38
137+4 (2x+3)=200(hình như đề bài sai)
200-6(x-5)=140
6(x-5)=200-140
6(x-5)=60
x-5=60:6
x-5=10
x=10+5
x=15
140:(x-8)=7
x-8=140:7
x-8=20
x=20+8
x=28
137+4(2x+3)=200
4(2x+3)=200-137
4(2x+3)=63
2x+3=63:4
2x+3=\(\frac{63}{4}\)
2x=\(\frac{63}{4}\)-3
2x=\(\frac{51}{4}\)
x=\(\frac{51}{4}\):2
x=\(\frac{51}{8}\)
Vậy ...
200-6(x-5)=140
6(x-5)=200-140
6(x-5)=60
x-5=60:6
x-5=10
x=15
Vậy...
140:(x-8)=7
x-8=140:7
x-8=20
x=20+8
x=28
Vậy...
k mik nhé
Ta có:
\(B=\frac{6}{8}+\frac{6}{56}+\frac{6}{140}+...+\frac{6}{1100}+\frac{6}{1400}\)
\(\Rightarrow B=\frac{3}{4}+\frac{3}{28}+\frac{3}{140}+...+\frac{3}{550}+\frac{3}{700}\)
\(\Rightarrow B=\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+...+\frac{3}{22.25}+\frac{3}{25.28}\)
\(\Rightarrow B=1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{22}-\frac{1}{25}+\frac{1}{25}-\frac{1}{28}\)
\(\Rightarrow B=1-\frac{1}{28}\)
\(\Rightarrow B=\frac{28}{28}-\frac{1}{28}=\frac{27}{28}\)
NHỚ TK MK NHA,MK ĐANG ÂM ĐIỂM
\(B=\frac{6}{8}+\frac{6}{56}+\frac{6}{140}+....+\frac{6}{1100}+\frac{6}{1400}\)
Rút gọn các phân số số ; ta được :
\(B=\frac{3}{4}+\frac{3}{56}+\frac{3}{70}+....+\frac{3}{550}+\frac{3}{700}\)
\(B=\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+...+\frac{3}{22.25}+\frac{3}{25.28}\)
\(B=1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{22}-\frac{1}{25}+\frac{1}{25}-\frac{1}{28}\)
\(B=1-\frac{1}{28}=\frac{27}{28}\)
Vậy biểu thức \(B=\frac{27}{28}\)
10( x - 4 ) - 8( x + 2 ) = 12
10x - 40 - 8x + 16 = 12
=> x( 10 - 8 ) - 40 + 16 = 12
2x - 40 + 16 = 12
2x - 40 = -4
2x = -4 + 40 = 36
x = 36 : 2 = 18
8.(x+2)-6.x=140
8( x + 2 ) - 6x = 140
8x + 16 - 6x = 140
x( 8 - 6 ) + 16 = 140
2x + 16 = 140
2x = 140 - 16
2x = 124
x = 124 : 2
x= 62
10.(x-4)-8.(x+2)=12
10x - 40 - 8x + 16 = 12
x( 10 - 8 ) - 40 + 16 = 12
2x - 40 + 16 = 12
2x - 40 = 12-16
2x - 40 = -4
2x = -4 + 40
2x = 36
x = 36 : 2
x= 18
x.(x-3)=6.(x-3)
+ -2X-12+6X-60=8
<=>4X=80]
<=> X = 20
V.....
+ -8X-36 +8X -3 - X - 13 =0
<=> -X = 52
<=> X = -52
V.....
+ 14X +7\(X^2\)-7\(X^2\)-21X=14
<=> -7X =14
<=> X= -2
V .......
Rốt cuộc YC tìm gì
\(\text{(−8):140=−6:(−7x)}\)
\(\Rightarrow\text{-6:(−8):140=(−7x)}\)
\(\Rightarrow105=-7x\)
\(\Rightarrow x=\frac{105}{-7}=-15\)
\(\text{Vậy }x=-15\)