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8 tháng 7 2020
Trả lời
\(A=\frac{7}{12}+\frac{5}{12}\div6-\frac{11}{36}\)
\(A=\frac{7}{12}+\frac{5}{12}\times\frac{1}{6}-\frac{11}{36}\)
\(A=\frac{7}{12}+\frac{5}{72}-\frac{11}{36}\)
\(A=\frac{25}{72}\)
\(B=12\frac{1}{3}-\frac{5}{7}\div\left(24-23\frac{5}{7}\right)\)
\(B=\frac{37}{3}-\frac{5}{7}\div\left(24-\frac{166}{7}\right)\)
\(B=\frac{37}{3}-\frac{5}{7}\div\frac{2}{7}\)
\(B=\frac{37}{3}-\frac{5}{7}\times\frac{7}{2}\)
\(B=\frac{37}{3}-\frac{5}{2}\)
\(B=\frac{59}{6}\)
NC
8 tháng 7 2020
Bài làm:
Ta có:
\(A=\frac{7}{12}+\frac{5}{12}\div6-\frac{11}{36}\)
\(A=\frac{7}{12}+\frac{5}{72}-\frac{11}{36}\)
\(A=\frac{42+5-22}{72}=\frac{25}{72}\)
và
\(B=12\frac{1}{3}-\frac{5}{7}\div\left(24-23\frac{5}{7}\right)\)
\(B=\frac{37}{3}-\frac{5}{7}\div\left(24-23-\frac{5}{7}\right)\)
\(B=\frac{37}{3}-\frac{5}{7}\div\left(1-\frac{5}{7}\right)\)
\(B=\frac{37}{3}-\frac{5}{7}+1\)
\(B=\frac{265}{21}\)
KN
8 tháng 7 2020
\(A=\frac{7}{12}+\frac{5}{12}:6-\frac{1}{36}\)
\(=\frac{7}{12}+\frac{5}{72}-\frac{11}{36}\)
\(=\frac{42}{72}+\frac{5}{72}-\frac{22}{72}\)
\(=\frac{25}{72}\)
11 tháng 6 2020
-5/8 . 5/12 + -5/8 .7/12 + 17/8=(-5/8 + -5/8).(5/12 + 7/12).17/8 = 0 . 1 .17/8 = 0 .17/8 = 0
5 tháng 6 2020
Bài làm
a) \(-\frac{3}{7}+\frac{3}{4}:\frac{3}{14}\)
= \(-\frac{3}{7}+\frac{3}{4}.\frac{14}{3}\)
= \(-\frac{3}{7}+\frac{7}{2}\)
\(=-\frac{7}{14}+\frac{49}{14}\)
\(=\frac{42}{14}=3\)
b) \(5-\frac{7}{39}:\frac{7}{13}+\frac{8}{9}:4\)
\(=5=\frac{7}{39}.\frac{13}{7}+\frac{8}{9}.\frac{1}{4}\)
\(=5-\frac{1}{3}+\frac{2}{9}\)
\(=\frac{45}{9}-\frac{3}{9}+\frac{2}{9}\)
\(=\frac{44}{9}\)
c) \(\left(\frac{5}{12}:\frac{11}{6}+\frac{5}{12}:\frac{11}{5}\right)-\frac{-7}{12}\)
\(=\left(\frac{5}{12}.\frac{6}{11}+\frac{5}{12}.\frac{5}{11}\right)+\frac{7}{12}\)
\(=\left[\frac{5}{12}\left(\frac{6}{11}+\frac{5}{11}\right)\right]+\frac{7}{12}\)
\(=\frac{5}{12}+\frac{7}{12}\)
\(=\frac{12}{12}=1\)
d) \(-\frac{5}{9}+\frac{14}{9}\left(\frac{3}{4}-\frac{2}{5}\right):49\)
\(=-\frac{5}{9}+\frac{14}{9}\left(\frac{15}{20}-\frac{8}{20}\right):49\)
\(=-\frac{5}{9}+\frac{14}{9}.\frac{7}{20}.\frac{1}{49}\)
\(=-\frac{5}{9}+\frac{7}{9}.\frac{7}{10}.\frac{1}{7.7}\)
\(=-\frac{5}{9}+\frac{1}{90}\)
\(=-\frac{50}{90}+\frac{1}{90}=-\frac{49}{90}\)
16 tháng 5 2018
a/=(74-(-1937)1)
=74-(-1937)
=2011
b/=4/7+5/6:5-3/8*(-4)
=4/7+1/6-(-3/2)
=31/42-(-3/2)
=47/21
minh chi biet bay nhieu
KN
15 tháng 5 2019
\(\frac{-3}{7}.\frac{5}{12}+\frac{3}{7}.\frac{7}{12}+\frac{-3}{12}\)
\(=\frac{3}{7}.\frac{-5}{12}+\frac{3}{7}.\frac{7}{12}+\frac{-1}{4}\)
\(=\frac{3}{7}.\left(\frac{-5}{12}+\frac{7}{12}\right)+\frac{-1}{4}\)
\(=\frac{3}{7}.\frac{2}{12}+\frac{-1}{4}\)
\(=\frac{3}{7}.\frac{1}{6}+\frac{-1}{4}\)
\(=\frac{3}{42}+\frac{-1}{4}\)
\(=\frac{1}{14}-\frac{1}{4}\)
\(=\frac{4}{56}-\frac{14}{56}\)
\(=\frac{-10}{56}=\frac{-5}{28}\)
WH
10 tháng 5 2018
\(\frac{5}{12}\cdot\frac{19}{6}+\frac{1}{6}-\frac{5}{12}\cdot\frac{7}{6}\)
\(=\frac{5}{12}\left(\frac{19}{6}-\frac{7}{6}\right)+\frac{1}{6}\)
\(=\frac{5}{12}\cdot\frac{19-7}{6}+\frac{1}{6}\)
\(=\frac{5}{12}\cdot\frac{12}{6}+\frac{1}{6}\)
\(=\frac{5\cdot12}{12\cdot6}+\frac{1}{6}\)
\(=\frac{5}{6}+\frac{1}{6}\)
\(=\frac{5+1}{6}=\frac{6}{6}=1\)
10 tháng 5 2018
= 5/12*16/9+2/12-5/12*7/6
= 5/12*(19/6+1-7/6)
= 5/12*3
= 5/4
\(\frac75.\frac{-5}{12}-\frac56\)
= \(\frac{-7}{12}-\frac56\)
=\(\frac{-17}{12}\)