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\(60\%x+0,4.x+\frac{x}{3}=2\)
\(\frac{3}{5}.x+\frac{2}{5}.x+\frac{1}{3}.x=2\)
\(x.\left(\frac{3}{5}+\frac{2}{5}+\frac{1}{3}\right)=2\)
\(x.\frac{4}{3}=2\)
\(x=2:\frac{4}{3}\)
\(x=\frac{3}{2}=1,5\)
60% x + 0,4x + x : 3 = 2
3/5 . x + 2/5 . x + x : 3 = 2
(3/5 + 2/5) x + x : 3 = 2
x + x : 3 = 2
x : (1 + 3) = 2
x : 4 = 2
x = 8
\(\frac{3}{5}x+\frac{2}{5}x+\frac{x}{3}=2\)
\(x+\frac{x}{3}=2\)
\(\frac{4}{3}x=2\)
\(x=2:\frac{4}{3}=\frac{3}{2}\)
\(60\%x+1,5x=\frac{1}{6}.\frac{2}{3}+\frac{1}{6}.\frac{1}{3}\)
\(60\%x+1,5x=\frac{1}{6}\left(\frac{2}{3}+\frac{1}{3}\right)\)
\(60\%x+1,5x=\frac{1}{6}.1\)
\(60\%x+1,5x=\frac{1}{6}\)
\(\frac{60}{100}x+1,5x=\frac{1}{6}\)
\(\frac{3}{5}x+1,5x=\frac{1}{6}\)
\(x\left(\frac{3}{5}+1,5\right)=\frac{1}{6}\)
\(\frac{21}{10}.x=\frac{1}{6}\)
\(\Rightarrow x=\frac{5}{63}\)
\(60\%.x+1,5.x=\frac{1}{6}.\frac{2}{3}+\frac{1}{6}.\frac{1}{3}\)
\(\frac{60}{100}.x+1,5.x=\frac{1}{6}.\left(\frac{2}{3}+\frac{1}{3}\right)\)
\(\frac{3}{5}.x+\frac{15}{10}.x=\frac{1}{6}.\frac{3}{3}\)
\(x+\left(\frac{3}{5}.\frac{15}{10}\right)=\frac{1}{6}.1\)
\(x+\left(\frac{3}{1}.\frac{3}{10}\right)=\frac{1}{6}\)
\(x+\frac{9}{10}=\frac{1}{6}\)
\(x=\frac{1}{6}-\frac{9}{10}\)
\(x=\frac{10}{60}-\frac{54}{60}\)
\(x=\frac{-44}{60}\)
\(x=\frac{-11}{15}\)
60%x + 2/3.x = -7/6
<=> 3/5x + 2/3x = (-7/6)
=> ( 3/5 + 2/3) x = (-7/6)
=> 19/15x = (-7/6)
=> x = (-7/6) : 19/15
=> x = -38/35
(-25)-(5.x-3)=4
5.x-3 = -25 - 4
5.x-3=-29
5.x=-26
x=-26/5
x=-5,2
a, 720:[118-(2x -10) ]=60
[118-(2x-10)]=720:60
118-(2x-10)=12
2x-10=118-12
2x-10=106
2x =106+10
2x =116
x=116:2
x=58
Lời giải:
$60\text{%}\times x+\frac{2}{3}\times x=\frac{1}{3}\times 6\frac{1}{3}$
$\frac{3}{5}\times x+\frac{2}{3}\times x=\frac{19}{9}$
$x\times (\frac{3}{5}+\frac{2}{3})=\frac{19}{9}$
$x\times \frac{19}{5}=\frac{19}{9}$
$x=\frac{19}{9}:\frac{19}{5}$
$x=\frac{5}{9}$