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a) \(x=\dfrac{1}{4}+\dfrac{2}{13}\)
\(x=\dfrac{13}{52}+\dfrac{8}{52}\)
⇒ \(x=\dfrac{21}{52}\)
b) \(\dfrac{x}{3}=\dfrac{2}{3}+\dfrac{-1}{7}\)
\(\dfrac{x}{3}=\dfrac{14}{21}+\dfrac{-3}{21}\)
\(\dfrac{x}{3}=\dfrac{11}{21}\)
⇒ \(x=\dfrac{11.3}{21}=\dfrac{33}{21}\)
⇒ \(x=\dfrac{11}{7}\)
c) \(\dfrac{-8}{3}+\dfrac{1}{3}< x< \dfrac{-2}{7}+\dfrac{-5}{7}\)
\(\dfrac{-17}{7}< x< -1\)
⇒ \(-17< x< -7\)
⇒ \(x\in\left\{-16;-15,....;-6\right\}\)
d) \(\dfrac{1}{6}+\dfrac{2}{5}\)
\(=\dfrac{5}{30}+\dfrac{12}{30}\)
\(=\dfrac{17}{30}\)
e) \(\dfrac{3}{5}+\dfrac{-7}{4}\)
\(=\dfrac{12}{20}+\dfrac{-35}{20}\)
\(=\dfrac{-23}{20}\)
f) \(\dfrac{4}{13}+\dfrac{-12}{30}\)
\(=\dfrac{4}{13}+\dfrac{-2}{5}\)
\(=\dfrac{20}{65}+\dfrac{-26}{65}\)
\(=\dfrac{-6}{65}\)
g) \(\dfrac{-3}{29}+\dfrac{16}{58}\)
\(=\dfrac{-6}{58}+\dfrac{16}{58}\)
\(=\dfrac{10}{58}\)
h) \(\dfrac{8}{40}+\dfrac{-36}{45}\)
\(=\dfrac{1}{5}+\dfrac{-4}{5}\)
\(=\dfrac{-3}{5}\)
j) \(\dfrac{-8}{18}+\dfrac{15}{27}\)
\(=\dfrac{-2}{9}+\dfrac{5}{9}\)
\(=\dfrac{3}{9}\)
\(=\dfrac{1}{3}\)
a) 2x−92�−9 = 10 phần 91
b) -5 phần 2x = 20 phần 28\
c) 1 phần 3 = -3x phần 36
bài 2
a)Tìm các số nguyên x, y sao cho : -4 phần = x phần 22 = 40 phần
b)Tìm các số nguyên x, y, z thỏa mãn: -4 phần 8 = x phần -10 = -7 phần y = z phần -24
a, 2 x 31 x 12 + 4 x 6 x 42 + 8 x 27 x 3
= 2 x 12 x 31 + 4 x 6 x 42 + 8 x 3 x 27
= 24 x 31 + 24 x 42 + 24 x 27
= 24 x ( 31 + 24 + 27 )
= 24 x 82
= 1968
b, 2 x 53 x 12 + 4 x 6 x 87 - 3 x 8 x 40
= 24 x 53 + 24 x 87 - 24 x 40
= 24 x ( 53 + 87 - 40 )
= 24 x 100
= 2400
c, Tương tự
Bài 1:
a: \(\Leftrightarrow\dfrac{6}{7}\left(\dfrac{7}{12}x-\dfrac{14}{3}\right)=\dfrac{5}{9}-\dfrac{9}{8}=\dfrac{-41}{72}\)
\(\Leftrightarrow x\cdot\dfrac{7}{12}-\dfrac{14}{3}=-\dfrac{287}{432}\)
\(\Leftrightarrow x\cdot\dfrac{7}{12}=\dfrac{1729}{432}\)
hay \(x=\dfrac{247}{36}\)
b: \(\Leftrightarrow\dfrac{1}{5}:x=\dfrac{1}{5}+\dfrac{3}{14}-\dfrac{8}{7}=\dfrac{-51}{70}\)
hay \(x=-\dfrac{14}{51}\)
c: đề sai rồi bạn
\(8+\left(x-6\right)=-40\)
\(\Leftrightarrow x-6=-40-8\)
\(\Leftrightarrow x-6=-48\)
\(\Leftrightarrow x=-48+6\)
\(\Leftrightarrow x=-42\)
\(\left(2x+5\right)-\left(-9\right)=-6\)
\(\Leftrightarrow2x+5=-6-9\)
\(\Leftrightarrow2x+5=-15\)
\(\Leftrightarrow2x=-15-5\)
\(\Leftrightarrow2x=-20\)
\(\Leftrightarrow x=\frac{-20}{2}\)
\(\Leftrightarrow x=-10\)
\(2\left(x-5\right)-3\left(x+7\right)=14\)
\(\Leftrightarrow2x-10-3x-21=14\)
\(\Leftrightarrow-x-31=14\)
\(\Leftrightarrow-x=14+31\)
\(\Leftrightarrow-x=45\)
\(\Leftrightarrow x=-45\)
\(-7\left(5-x\right)-2\left(x+3\right)=12\)
\(\Leftrightarrow-35+7x-2x-6=12\)
\(\Leftrightarrow-30x=12+6\)
\(\Leftrightarrow-30x=18\)
\(\Leftrightarrow x=\frac{-3}{5}\)
\(a.\dfrac{6}{5}=\dfrac{18}{x}\Rightarrow x=\dfrac{18\cdot5}{6}=15\\ \text{Vậy}\text{ }x=15.\)
\(b.\dfrac{3}{4}=\dfrac{-21}{x}\Rightarrow x=\dfrac{-21\cdot4}{3}=28\\ \text{ }\text{ }\text{ }\text{ }\text{Vậy }x=28.\)
\(c.\dfrac{x}{4}=\dfrac{21}{28}\Rightarrow x=\dfrac{21\cdot4}{28}=3\\ \text{Vậy }x=3.\)
\(d.\dfrac{-8}{2x}=\dfrac{3}{-9}\Rightarrow x=\dfrac{-8\cdot\left(-9\right)}{3}:2=12\\ \text{Vậy }x=12.\)
\(e.\dfrac{-4}{11}=\dfrac{x}{22}=\dfrac{40}{z}\\ \Rightarrow x=\dfrac{-4\cdot22}{11}=-8\\ \Rightarrow z=\dfrac{22\cdot40}{-8}=-110\\ \text{Vậy }x=-8;z=-110.\)
\(f.\dfrac{-3}{4}=\dfrac{x}{20}=\dfrac{21}{y}\\ \Rightarrow x=\dfrac{-3\cdot20}{4}=-15\\ \Rightarrow y=\dfrac{21\cdot20}{-15}=-28\\ \text{Vậy }x=-15;y=-28.\)
\(g.\dfrac{-4}{8}=\dfrac{x}{-10}=\dfrac{-7}{y}=\dfrac{z}{-24}\\ \Rightarrow x=\dfrac{-4\cdot\left(-10\right)}{8}=5\\ \Rightarrow y=\dfrac{-7\cdot\left(-10\right)}{5}=14\\ \Rightarrow z=\dfrac{-7\cdot\left(-24\right)}{14}=12\\ \text{Vậy }x=5;y=14;z=12.\)
\(h.\dfrac{x}{4}=\dfrac{9}{x}\\ \Rightarrow x\cdot x=9\cdot4\\ \Rightarrow x\cdot x=36\\ \Rightarrow x\cdot x=6\cdot6\\ \text{Vậy }\text{cả hai }x=6.\)
+) Ta có:\(2.4.6.8.10.12⋮6;40⋮̸6\)
Vậy:\(A⋮̸6\)
+) Ta có:\(2.4.6.8.10.12⋮8;40⋮8\)
Vậy:\(A⋮6\)
+) Ta có:\(2.4.6.8.10.12⋮20;40⋮̸6\)
Vậy:\(A⋮̸6\)
6 . x3 - 8 = 40
6x3 = 48
x3 = 8
x3 = 23
x=2
=.= hok tốt!!
ta có :6x3-8=40
suy ra:6x3=48
suy ra:x^3=8
suy ra:x=2