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( 2014 x 2015 - 2016 ) : ( 2012 + 2013 x 2014 )
= ( 4058210 - 2016 ) : ( 2012 + 4054182 )
= 4056194 : 4056194
= 1
a, 13 \(\times\) 15 - 150 + 97 \(\times\)15
13 \(\times\) 15 - 15 \(\times\) 10 + 97 \(\times\) 15
= 15 \(\times\) ( 13 - 10 + 97)
= 15 \(\times\) ( 3 + 97)
= 15 \(\times\) 100
=1500
b, \(\dfrac{2016}{2015}\) \(\times\) \(\dfrac{4}{7}\) - \(\dfrac{4}{7}\) \(\times\) \(\dfrac{1}{2015}\) + \(\dfrac{3}{7}\)
= \(\dfrac{4}{7}\) \(\times\) ( \(\dfrac{2016}{2015}\) - \(\dfrac{1}{2015}\)) + \(\dfrac{3}{7}\)
= \(\dfrac{4}{7}\) \(\times\) \(\dfrac{2015}{2015}\) + \(\dfrac{3}{7}\)
= \(\dfrac{4}{7}\) + \(\dfrac{3}{7}\)
= \(\dfrac{7}{7}\)
= 1
a, \(13\) \(\times\) 15 - 150 + 97 \(\times\) 15
= 15 \(\times\) ( 13 - 10 + 97)
= 15 \(\times\) ( 3 + 97)
= 15 \(\times\) 100
= 1500
b, \(\dfrac{2016}{2015}\) \(\times\) \(\dfrac{4}{7}\) - \(\dfrac{4}{7}\) \(\times\) \(\dfrac{1}{2015}\) + \(\dfrac{3}{7}\)
= \(\dfrac{4}{7}\) \(\times\) ( \(\dfrac{2016}{2015}\) - \(\dfrac{1}{2015}\)) + \(\dfrac{3}{7}\)
= \(\dfrac{4}{7}\) \(\times\) \(\dfrac{2015}{2015}\) + \(\dfrac{3}{7}\)
= \(\dfrac{4}{7}\) + \(\dfrac{3}{7}\)
= \(\dfrac{7}{7}\)
= 1
( 2013 x 2014 + 2014 x 2015 + 2015 x 2016) x ( 1 + 1/3 - 4/3)
=( 2013 x 2014 + 2014 x 2015 + 2015 x 2016) x ( 4/3 - 4/3)
=( 2013 x 2014 + 2014 x 2015 + 2015 x 2016) x 0
=0
Ta có: \(\left(2013\cdot2014+2014\cdot2015+2015\cdot2016\right)\left(1+\dfrac{1}{3}-\dfrac{4}{3}\right)\)
\(=\left(2013\cdot2014+2014\cdot2015+2015\cdot2016\right)\left(\dfrac{3}{3}+\dfrac{1}{3}-\dfrac{4}{3}\right)\)
=0
=2.5:4/1+0.75x2.5=2.5x0.25+0.75x2.5=2.5(0.25+0.75)=2.5x1=2.5
17 x 0,75 - 17 x 0,25 + 17 x 0,5
= 17 x ( 0,75 - 0,25 + 0,5 )
= 17 x 1
= 17
= 17 x ( 0,75 - 0,25 + 0,5 )
= 17 x 1
= 17
Đúng 100%
Đúng 100%
Đúng 100%
( 3092 x 0,75 - 408 x 3/4 ) : 6/4
= ( 3092 x 0,75 - 408 x 0.75 ) x 4/6
= 0,75 x (3092- 408) x 4/6
= 3/4 x 2684 x 4/6
= 12/24 x 2684
= 0,5 x 2684
= 1342
(3092 x 0,75 - 408 x 3 phần 4) : 6 phần 4
=(2319 - 306 ) : 6 phần 4
= 2013 : 6 phần 4
= 1342
=3/4.0,25+3/4.1,25-3/4.0,5
=3/4.(0,25+1,25-0,5)
=3/4.10
=15/2
\(2015\cdot\dfrac{1}{4}+2015\cdot0,75\)
\(=2015\left(\dfrac{1}{4}+0,75\right)\)
\(=2015\left(0,25+0,75\right)\)
\(=2015\cdot1=2015\)
2015 x 0,25 + 2015 x 0,75
=2015 x (0,25+0,75)
=2015 x 1
=2015