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a) \(\frac{x}{2}-\frac{11}{5}=\frac{7}{8}.\frac{64}{49}\)
\(\frac{x}{2}-\frac{11}{5}=\frac{8}{7}\)
\(\frac{x}{2}=\frac{8}{7}+\frac{11}{5}\)
\(\frac{x}{2}=\frac{117}{35}\)
\(x=\frac{117}{35}\times2\)
\(x=\frac{234}{35}\)
b) \(\frac{y}{5}+\frac{9}{2}=\frac{6}{7}.\frac{36}{49}\)
\(\frac{y}{5}+\frac{9}{2}=\frac{216}{343}\)
\(\frac{y}{5}=\frac{216}{343}-\frac{9}{2}\)
\(\frac{y}{5}=\frac{-2655}{686}\)
\(y=\frac{-2655}{686}.5\)
\(y=\frac{-13275}{686}\)
ra kết quả to quá bn ạ! Bn xem lại giúp mk nha!
a) |4x - 7| = 13
=> \(\orbr{\begin{cases}4x-7=13\\4x-7=-13\end{cases}}\)
=> \(\orbr{\begin{cases}4x=20\\4x=-6\end{cases}}\)
=> \(\orbr{\begin{cases}x=5\\x=-\frac{3}{2}\end{cases}}\)
b) tương tự)
d) Ta có: 11 = 1. 11 = 11. 1
Lập bảng:
2x - 1 | 1 | 11 | -1 | -11 |
y + 3 | 11 | 1 | -11 | -1 |
x | 1 | 6 | 0 | -5 |
y | 8 | -2 | -14 | -4 |
Vậy ...
e) tương tự
1) \(\left(5+x\right)^2-36=0\)
\(\Rightarrow\left(5+x-6\right)\left(5+x+6\right)=0\Rightarrow\left(x-1\right)\left(x+11\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=1\\x=-11\end{matrix}\right.\)
2) \(\Rightarrow\left(7x-11\right)^3=1000=10^3\)
\(\Rightarrow7x-11=10\Rightarrow7x=21\Rightarrow x=3\)
`(5/6 -x+7/12) : ( 11/24 -1/8)=11/36`
`=>(5/6 -x+7/12) : (11/24 - 3/24)=11/36`
`=>(5/6 -x+7/12) : 8=11/36`
`=>5/6 -x+7/12=11/36 xx 8`
`=>5/6 -x+7/12=22/9`
`=> x+7/12=5/6-22/9`
`=> x+7/12=-29/18`
`=>x=-29/18 -7/12`
`=>x=-79/36`
13/36-5/18-x=-11/9
5/18-x=13/36-(-11/9)
5/18-x=19/12
x=5/18-19/12
x= -47/36
vậy x = -47/36
\(\frac{13}{36}-\frac{5}{18}-x=\frac{-11}{9}\)
\(\Leftrightarrow\)\(\frac{13}{36}-\frac{10}{36}-x=\frac{-44}{36}\)
\(\Leftrightarrow\frac{3}{36}-x=\frac{-44}{36}\)
\(\Leftrightarrow x=\frac{3}{36}-\frac{-44}{36}\)
\(\Leftrightarrow x=\frac{47}{36}\)
chắc là vậy
2x - 36 = 46 : 43
2x - 36 = 64
2x = 64 + 36
2x = 100
x = 100 : 2
x = 50
5x+ 11= 36
5x = 36 - 11
5x = 25
=> x = 2
k mik nha làm ơn
a)\(2x-36=4^6:4^3\Rightarrow2x-36=4^3\Rightarrow2x-36=64\Rightarrow2x=64+36\Rightarrow2x=100\Rightarrow x=50\)
b)\(5^x+11=36\Rightarrow5^x=36-11\Rightarrow5^x=25\Rightarrow x=2\)
Bài 1:
a: \(x=\dfrac{2}{3}:\dfrac{3}{5}=\dfrac{2}{3}\cdot\dfrac{5}{3}=\dfrac{10}{9}\)
b: \(x=\dfrac{17}{8}:\dfrac{7}{17}=\dfrac{17}{8}\cdot\dfrac{17}{7}=\dfrac{289}{56}\)
c: \(x=-\dfrac{3}{4}:\dfrac{7}{12}=\dfrac{-3}{4}\cdot\dfrac{12}{7}=\dfrac{-63}{28}=-\dfrac{9}{4}\)
d: \(\Leftrightarrow x\cdot\dfrac{1}{6}=\dfrac{3}{8}-\dfrac{1}{4}=\dfrac{1}{4}\)
hay \(x=\dfrac{1}{4}:\dfrac{1}{6}=\dfrac{3}{2}\)
e: \(\Leftrightarrow\dfrac{1}{2}:x=-4-\dfrac{1}{3}=-\dfrac{17}{3}\)
hay \(x=-\dfrac{1}{2}:\dfrac{17}{3}=\dfrac{-3}{34}\)
a: \(\Leftrightarrow x=\dfrac{16\cdot6}{4}=24\)
b: \(\Leftrightarrow x=\dfrac{-5\cdot42}{14}=-15\)
c: \(\Leftrightarrow\dfrac{x}{11}=\dfrac{-3}{11}\)
hay x=-3