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câu c có A là sao
a) ( 3x - 4 )3 = 8
(3x-4)3=23
=>3x-4=2
3x=2+4
3x=6
x=6:2
x=3
b) 2 . ( 2x + 3 )3 = 250
(2x+3)3=250:2
(2x+3)3=125
(2x+3)3=53
=>2x+3=5
2x=5-3
2x=2
x=2:2
x=1
d) 2x + 2x + 1 + 2x + 2 = 56
2x.1+2x.21+2x.22=56
2x.(1+21+22)=56
2x.(1+2+4)=56
2x.7=56
2x=56:7
2x=8
2x=23
=>x=3
\(3^{2x}.3+7^3:7^2=250\)
\(\Rightarrow3^{2x+1}+7=250\)
\(\Rightarrow3^{2x+1}=243\)
\(\Rightarrow3^{2x+1}=3^5\)
\(\Rightarrow2x+1=5\)
\(\Rightarrow2x=4\)
\(\Rightarrow x=2\)
Vậy \(x=2\)
9x+5.4 = 200 4x-20 = 2^5:2^2 2.3^x-5=157
9x+ 20 = 200 4x-20 = 2^3 2.3^x=157+5
9x = 200-20 4x-20 = 8 2.3^x=162
9x = 180 4x = 8+20 3^x=162:2
x= 180 : 9 4x = 28 3^x=81
x=2 x = 28:4 mà 3^4=81 => x=4
x = 7
tìm x
a) 7(x-4)3+30=219
7(x-4)3=219-30
7(x-4)3=189
(x-4)3=189:7
(x-4)3=27
(x-4)3=33
x-4=3
x=3+4
x=7
b,720:[41(2.x-5)]=40
41(2.x-5)=720:40
41(2.x-5)=18
2.x-5=18:41
2.x-5=\(\frac{18}{41}\)
2.x=\(\frac{18}{41}\)+5
2.x=\(\frac{223}{41}\)
x=\(\frac{223}{41}\):2
x=\(\frac{223}{82}\)
Tính
c)100:{250:[450-(4.53-22.25]}
=100:{250:[450-(4.125-4.25]}
=100:{250:[450-[500-100]}
=100:{250:[450-400]}
=100:{250:50}]
=100:50
=2
(li-ke cho mình nha)
a: \(\Leftrightarrow5x-42=251\)
=>5x=293
hay x=293/5
b: \(\Leftrightarrow20-x=20\)
hay x=0
c: \(\Leftrightarrow x-4300-\dfrac{1}{50}=4250\)
\(\Leftrightarrow x=\dfrac{427501}{50}\)
d: =>(x+200):4=460-340=120
=>x+200=480
hay x=280
e: =>5+15(x+1)=500-480=20
=>15(x+1)=15
=>x+1=1
hay x=0
\(5\cdot\left(x-2\right)^3-3\cdot\left(x-2\right)^3=250\)
\(\left(x-2\right)^3\cdot\left(5-3\right)=250\)
\(\left(x-2\right)^3\cdot2=250\)
\(\left(x-2\right)^3=\dfrac{250}{2}\)
\(\left(x-2\right)^3=125\)
\(\left(x-2\right)^3=5^3\)
\(x-2=5\)
\(x=5+2\)
\(x=7\)
\(5.\left(x-2\right)^3-3\left(x-2\right)^3=250\)
\(\Leftrightarrow\left(x-2\right)^3.\left(5-3\right)=250\)
\(\Leftrightarrow\left(x-2\right)^3.2=250\)
\(\Leftrightarrow\left(x-2\right)^3=125\)
\(\Leftrightarrow\left(x-2\right)^3=5^3\)
\(\Leftrightarrow x-2=5\)
\(\Leftrightarrow x=7\)