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\(5.\left(x+35\right)=515\)
\(x+35=515:5\)
\(x+35=103\)
\(x=103-35\)
\(\Rightarrow x=68\)
\(\left(x+40\right).15=75.12\)
\(\Rightarrow\left(x+40\right)=5.12\)[ rút gọn theo t/c đẳng thức ]
\(x+40=60\)
\(x=20\)
\(5.\left(x+35\right)=515\)
\(\Rightarrow x+35=515:5\)
\(\Rightarrow x+35=103\)
\(\Rightarrow x=103-35\)
\(\Rightarrow x=68\)
Mấy câu còn lại tương tự nhé !
a) \(\left(x-2\right)\left(y+1\right)=14\)
Do \(x,y\in N\)
\(\Rightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}x-2=1\\y+1=14\end{matrix}\right.\\\left\{{}\begin{matrix}x-2=14\\y+1=1\end{matrix}\right.\\\left\{{}\begin{matrix}x-2=2\\y+1=7\end{matrix}\right.\\\left\{{}\begin{matrix}x-2=7\\y+1=2\end{matrix}\right.\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}x=3\left(tm\right)\\y=13\left(tm\right)\end{matrix}\right.\\\left\{{}\begin{matrix}x=16\left(tm\right)\\y=0\left(tm\right)\end{matrix}\right.\\\left\{{}\begin{matrix}x=4\left(tm\right)\\y=6\left(tm\right)\end{matrix}\right.\\\left\{{}\begin{matrix}x=9\left(tm\right)\\y=1\left(tm\right)\end{matrix}\right.\end{matrix}\right.\)
a. 5(x+35)=515
=> x+35=515:5
=> x+35=103
=> x = 103-35
=> x = 68
b. (x+40).15=75.12
=>(x+40).15=900
=>x+40=900:15
=>x+40=60
=>x=60-40
=>x=20
c.460+85.4=(x+200):4
=>460+340=(x+200):4
=>800=(x+200):4
=>800.4=x+200
=>3200=x+200
=>x=3200-200
=>x=3000
4.120+[45:9+15-(x+1)]=500
480+[45:9+15-(x+1)]=500
45:9+15-(x+1)=500-480
45:9+15-(x+1)=20
5+15-(x+1)=20
20-(x+1)=20
x+1=20-20
x+1=0
x=0-1
x=-1
=>4.120+[45:9+15-(x+1)]=500
=>480+[45:9+15-(x+1)]=500
=>45:9+15-(x+1)=500-480
=>45:9+15-(x+1)=20
=>5+15-(x+1)=20
=>20-(x+1)=20
=>x+1=20-20
=>x+1=0
=>x=0-1
=> x=-1
4.120+[45:9+15(x+1)]=500
=>480+[5+15(x+1)]=500
=>5+15(x+1)=20
=>15(x+1)=15
=>x+1=1
=>x=0
4.120+[45:9+15(x+1)]=500
480+[5+15x+15]=500
480+5+15x+15=500
500+15x=500
15x=0
x=0
Ta có: 460+85,4=(x-200):4
suy ra 460+340=(x-200):4
suy ra 800=9x-200):4
suy ra 800:4=x-200
suy ra x=3200+200=3400
a: \(\Leftrightarrow5x-42=251\)
=>5x=293
hay x=293/5
b: \(\Leftrightarrow20-x=20\)
hay x=0
c: \(\Leftrightarrow x-4300-\dfrac{1}{50}=4250\)
\(\Leftrightarrow x=\dfrac{427501}{50}\)
d: =>(x+200):4=460-340=120
=>x+200=480
hay x=280
e: =>5+15(x+1)=500-480=20
=>15(x+1)=15
=>x+1=1
hay x=0