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5 / 14 + 18 / 35 + ( 5 / 4 - 5 / 4 ) : ( 5/12)^2
= 61 / 70 + 0 : ( 5 / 12)^2
= 61 / 70 + 0
= 61 / 70
A =\(\frac{2\left(1-\frac{1}{19}+\frac{1}{43}-\frac{1}{1943}\right)}{3\left(1-\frac{1}{19}+\frac{1}{43}-\frac{1}{1943}\right)}:\frac{4\left(1-\frac{1}{29}+\frac{1}{41}-\frac{1}{2941}\right)}{5\left(1-\frac{1}{29}+\frac{1}{41}-\frac{1}{2941}\right)}\)
=\(\frac{2}{3}:\frac{4}{5}=\frac{2}{3}.\frac{5}{4}=\frac{10}{12}=\frac{5}{6}\)
A=\(\frac{\frac{3}{7}-\frac{3}{17}+\frac{3}{37}}{\frac{5}{7}-\frac{5}{17}+\frac{5}{37}}+\frac{\frac{1}{2}-\frac{1}{3}+\frac{1}{4}-\frac{1}{5}}{\frac{7}{5}-\frac{7}{4}+\frac{7}{3}-\frac{7}{2}}\)
\(=\frac{3\left(\frac{1}{7}-\frac{1}{17}+\frac{1}{37}\right)}{5\left(\frac{1}{7}-\frac{1}{17}+\frac{1}{37}\right)}+\frac{\frac{1}{2}-\frac{1}{3}+\frac{1}{4}-\frac{1}{5}}{-7\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{4}-\frac{1}{5}\right)}\)
\(=\frac{3}{5}+\frac{1}{-7}=\frac{3}{5}-\frac{1}{7}\)
\(=\frac{21}{35}-\frac{5}{35}=\frac{16}{35}\)
B=1/5.(1+1/5+...+\(^{\frac{1}{5^{ }}99}\))
C=1/5.(1/5+\(\frac{1}{5}^3\)+...+\(\frac{1}{5}^{99}\))
\(\frac{1}{3}-\frac{1}{4}=\frac{4}{12}-\frac{3}{12}=\frac{4-3}{12}=\frac{1}{12}\)
\(\frac{1}{4}-\frac{1}{5}=\frac{5}{20}-\frac{4}{20}=\frac{5-4}{20}=\frac{1}{20}\)
\(\frac{6}{7}-\frac{3}{10}=\frac{60}{70}-\frac{21}{70}=\frac{60-21}{70}=\frac{39}{70}\)
\(\frac{5}{9}-\frac{1}{4}=\frac{20}{36}-\frac{9}{36}=\frac{20-9}{36}=\frac{11}{36}\)
5/4+5/5=5/4+1=9/4
9/4