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a) \(5\left(x+7\right)-10=2^3\cdot5\)
\(\Rightarrow5\left(x+7\right)-10=40\)
\(\Rightarrow5\left(x+7\right)=40+10\)
\(\Rightarrow x+7=\dfrac{50}{5}\)
\(\Rightarrow x+7=10\)
\(\Rightarrow x=10-7\)
\(\Rightarrow x=3\)
b) \(9x-2\cdot3^2=3^4\)
\(\Rightarrow9x-18=81\)
\(\Rightarrow9x=81+18\)
\(\Rightarrow9x=99\)
\(\Rightarrow x=\dfrac{99}{9}\)
\(\Rightarrow x=11\)
c) \(5^{25}\cdot5^{x-1}=5^{25}\)
\(\Rightarrow5^{x-1}=5^{25}:5^{25}\)
\(\Rightarrow5^{x-1}=1\)
\(\Rightarrow5^{x-1}=5^0\)
\(\Rightarrow x-1=0\)
\(\Rightarrow x=1\)
\(9x^5+8^3=2699\)
\(9x^5=2699-512\)
\(x^5=243\)
\(x^5=3^5\)
\(\Rightarrow x=3\)
\(9x^5+8^3=2699\)
\(9x^5+512=2699\)
\(9x^5=2187\)
\(x^5=243\)
\(x^5=3^5\)
\(\Rightarrow x=3\)
\(9x+x=2^3\cdot5^2\)
\(10x=8\cdot25\)
\(10x=200\)
\(x=\frac{200}{10}\)
\(x=20\)
\(A=5\cdot4^{15}\cdot9^9-4\cdot3^{20}\cdot8^9\)
\(A=5\cdot\left(2^2\right)^{15}\cdot\left(3^2\right)^9-2^2\cdot3^{20}\cdot\left(2^3\right)^9\)
\(A=5\cdot2^{30}\cdot3^{18}-2^2\cdot3^{20}\cdot2^{27}\)
\(A=5\cdot2^{30}\cdot3^{18}-2^{29}\cdot3^{20}\)
\(A=2^{29}\cdot3^{18}\cdot\left(5\cdot2^1\cdot1-1\cdot3^2\right)\)
\(A=2^{29}\cdot3^{18}\cdot\left(5-9\right)\)
\(A=-2^2\cdot2^{29}\cdot3^{18}\)
\(A=-2^{31}\cdot3^{18}\)
_______________
\(B=5\cdot2^9\cdot6^{19}-7\cdot2^{29}\cdot27^6\)
\(B=5\cdot2^9\cdot2^{19}\cdot3^{19}-7\cdot2^{29}\cdot\left(3^3\right)^6\)
\(B=5\cdot2^{28}\cdot3^{19}-7\cdot2^{29}\cdot3^{18}\)
\(B=2^{28}\cdot3^{18}\cdot\left(5\cdot1\cdot3-7\cdot2\cdot1\right)\)
\(B=2^{28}\cdot3^{18}\cdot\left(15-14\right)\)
\(B=2^{28}\cdot3^{18}\)
Ta có: \(A:B\)
\(=\left(-2^{31}\cdot3^{18}\right):\left(2^{28}\cdot3^{18}\right)\)
\(=\left(-2^{31}:2^{28}\right)\cdot\left(3^{18}:3^{18}\right)\)
\(=-2^3\cdot1\)
\(=-8\)
\(9x-20=5^5:5^3\)
\(\Leftrightarrow9x-20=5^{5-3}\)
\(\Leftrightarrow9x-20=5^2\)
\(\Leftrightarrow9x-20=25\)
\(\Leftrightarrow9x=25+20\)
\(\Leftrightarrow9x=45\)
\(\Leftrightarrow x=45:9\)
\(\Leftrightarrow x=5\)
\(9x-20=5^5:5^3\)
\(9x-20=25\)
\(9x=25+20\)
\(9x=45\)
\(x=45:9\)
\(x=5\)
\(\Rightarrow9x-8=10\\ \Rightarrow9x=18\\ \Rightarrow x=2\)
\(9x-20=5^5-5^3\)
\(\Rightarrow9x-20=5^2\)
\(\Rightarrow9x=25+20\)
\(\Rightarrow9x=45\)
\(\Rightarrow1x=45:9\)
\(\Leftrightarrow1x=5\)
Vây x=5
9x-20 = 5^5 - 5^3
9x-20 = 3125-125
9x-20 = 3000
9x = 3000+20
9x = 3020
x = 3020 : 9
x =
ĐỐ Đứa nào làm được đứa nào làm được bằng mình
53 - (242 - 9x) = 33
125 - (242 - 9x) = 27
242 - 9x = 125 - 27
242 - 9x = 98
9x = 242 - 98
9x = 144
x = 144 : 9
x = 16