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\(9x^5+8^3=2699\)
\(9x^5=2699-512\)
\(x^5=243\)
\(x^5=3^5\)
\(\Rightarrow x=3\)
\(9x^5+8^3=2699\)
\(9x^5+512=2699\)
\(9x^5=2187\)
\(x^5=243\)
\(x^5=3^5\)
\(\Rightarrow x=3\)

\(9x+x=2^3\cdot5^2\)
\(10x=8\cdot25\)
\(10x=200\)
\(x=\frac{200}{10}\)
\(x=20\)

a) \(5\left(x+7\right)-10=2^3\cdot5\)
\(\Rightarrow5\left(x+7\right)-10=40\)
\(\Rightarrow5\left(x+7\right)=40+10\)
\(\Rightarrow x+7=\dfrac{50}{5}\)
\(\Rightarrow x+7=10\)
\(\Rightarrow x=10-7\)
\(\Rightarrow x=3\)
b) \(9x-2\cdot3^2=3^4\)
\(\Rightarrow9x-18=81\)
\(\Rightarrow9x=81+18\)
\(\Rightarrow9x=99\)
\(\Rightarrow x=\dfrac{99}{9}\)
\(\Rightarrow x=11\)
c) \(5^{25}\cdot5^{x-1}=5^{25}\)
\(\Rightarrow5^{x-1}=5^{25}:5^{25}\)
\(\Rightarrow5^{x-1}=1\)
\(\Rightarrow5^{x-1}=5^0\)
\(\Rightarrow x-1=0\)
\(\Rightarrow x=1\)
a) 5(�+7)−10=23⋅55(x+7)−10=23⋅5
⇒5(�+7)−10=40⇒5(x+7)−10=40
⇒5(�+7)=40+10⇒5(x+7)=40+10
⇒�+7=505⇒x+7=550
⇒�+7=10⇒x+7=10
⇒�=10−7⇒x=10−7
⇒�=3⇒x=3
b) 9�−2⋅32=349x−2⋅32=34
⇒9�−18=81⇒9x−18=81
⇒9�=81+18⇒9x=81+18
⇒9�=99⇒9x=99
⇒�=999⇒x=999
⇒�=11⇒x=11
c) 525⋅5�−1=525525⋅5x−1=525
⇒5�−1=525:525⇒5x−1=525:525
⇒5�−1=1⇒5x−1=1
⇒5�−1=50⇒5x−1=50
⇒�−1=0⇒x−1=0
⇒�=1⇒x=1

\(9x-20=5^5:5^3\)
\(\Leftrightarrow9x-20=5^{5-3}\)
\(\Leftrightarrow9x-20=5^2\)
\(\Leftrightarrow9x-20=25\)
\(\Leftrightarrow9x=25+20\)
\(\Leftrightarrow9x=45\)
\(\Leftrightarrow x=45:9\)
\(\Leftrightarrow x=5\)
\(9x-20=5^5:5^3\)
\(9x-20=25\)
\(9x=25+20\)
\(9x=45\)
\(x=45:9\)
\(x=5\)

\(9x-20=5^5-5^3\)
\(\Rightarrow9x-20=5^2\)
\(\Rightarrow9x=25+20\)
\(\Rightarrow9x=45\)
\(\Rightarrow1x=45:9\)
\(\Leftrightarrow1x=5\)
Vây x=5
9x-20 = 5^5 - 5^3
9x-20 = 3125-125
9x-20 = 3000
9x = 3000+20
9x = 3020
x = 3020 : 9
x =

\(A=5\cdot4^{15}\cdot9^9-4\cdot3^{20}\cdot8^9\)
\(A=5\cdot\left(2^2\right)^{15}\cdot\left(3^2\right)^9-2^2\cdot3^{20}\cdot\left(2^3\right)^9\)
\(A=5\cdot2^{30}\cdot3^{18}-2^2\cdot3^{20}\cdot2^{27}\)
\(A=5\cdot2^{30}\cdot3^{18}-2^{29}\cdot3^{20}\)
\(A=2^{29}\cdot3^{18}\cdot\left(5\cdot2^1\cdot1-1\cdot3^2\right)\)
\(A=2^{29}\cdot3^{18}\cdot\left(5-9\right)\)
\(A=-2^2\cdot2^{29}\cdot3^{18}\)
\(A=-2^{31}\cdot3^{18}\)
_______________
\(B=5\cdot2^9\cdot6^{19}-7\cdot2^{29}\cdot27^6\)
\(B=5\cdot2^9\cdot2^{19}\cdot3^{19}-7\cdot2^{29}\cdot\left(3^3\right)^6\)
\(B=5\cdot2^{28}\cdot3^{19}-7\cdot2^{29}\cdot3^{18}\)
\(B=2^{28}\cdot3^{18}\cdot\left(5\cdot1\cdot3-7\cdot2\cdot1\right)\)
\(B=2^{28}\cdot3^{18}\cdot\left(15-14\right)\)
\(B=2^{28}\cdot3^{18}\)
Ta có: \(A:B\)
\(=\left(-2^{31}\cdot3^{18}\right):\left(2^{28}\cdot3^{18}\right)\)
\(=\left(-2^{31}:2^{28}\right)\cdot\left(3^{18}:3^{18}\right)\)
\(=-2^3\cdot1\)
\(=-8\)
ĐỐ Đứa nào làm được đứa nào làm được bằng mình
53 - (242 - 9x) = 33
125 - (242 - 9x) = 27
242 - 9x = 125 - 27
242 - 9x = 98
9x = 242 - 98
9x = 144
x = 144 : 9
x = 16