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\(\left(4x-1\right)\left(4x-1\right)^2-\left(4x-3\right)\left(16x^2+3\right)\)
\(=\left(4x-1\right)^3-\left(4x-3\right)\left(16x^2+3\right)\)
\(=64x^3-48x^2+12x-1-64x^3-12x+48x^2-9\)
=-10
4 \(\times\) (\(x-1\))3 - 1 = 3
4 \(\times\) (\(x\) - 1)3 = 3 + 1
4 \(\times\) (\(x-1\))3 = 4
(\(x-1\))3 = 4:4
(\(x-1\))3 = 1
\(x-1=1\)
\(x\) = 1 + 1
\(x\) = 2
3/4x-7/3=1/4x+1/6
=>3/4x=1/4x+1/6+7/3
=>3/4x=1/4x+5/2
=>3/4x - 1/4x =5/2
=>1/2x=5/2
=>.......................................
1)8(4x-3)-3(2-3x)=13-40x
(32x-24)-(6-9x)=13-40x
32x-24-6+9x=13-40x
41x-30=13-40x
41x+40x=13+30
81x=43
x=43/81
Vậy x=43/81
2)10x-5(1-4x)=5x-11
10x-(5-20x)=5x-11
10x-5+20x=5x-11
30x-5=5x-11
30x-5x=5-11
25x=-6
x=-6/25
Vậy x=-6/25
Sửa đề : \(\frac{3}{4}x-\frac{1}{4}=2\left(x-3\right)-\frac{1}{4}x\)
\(\frac{3}{4}x-\frac{1}{4}=2x-6-\frac{1}{4}x\)
\(\frac{3}{4}x-\frac{1}{4}=\frac{7}{4}x+2x\)
\(-x-\frac{1}{4}=2x\)
\(-x-\frac{1}{4}-2x=0\)
\(-3x-\frac{1}{4}=0\)
\(-3x=\frac{1}{4}\Leftrightarrow x=-\frac{1}{12}\)
\(2\left(\frac{3}{4}x-1\right)-3y\left(1-\frac{3}{4}x\right)=0\)
\(\Leftrightarrow\)\(2\left(\frac{3}{4}x-1\right)+3y\left(\frac{3}{4}x-1\right)=0\)
\(\Leftrightarrow\)\(\left(\frac{3}{4}x-1\right)\left(2+3y\right)=0\)
\(\Leftrightarrow\)\(\orbr{\begin{cases}\frac{3}{4}x-1=0\\2+3y=0\end{cases}}\)
\(\Leftrightarrow\)\(\orbr{\begin{cases}x=\frac{4}{3}\\y=-\frac{2}{3}\end{cases}}\)
\(\Leftrightarrow\frac{3}{4}x-\frac{1}{4}=2x-6+\frac{1}{4}x\)
\(\Leftrightarrow\frac{3}{4}x-2x-\frac{1}{4}x=-6+\frac{1}{4}\)
\(\Leftrightarrow\frac{-3}{2}x=\frac{-23}{4}\)
\(\Leftrightarrow x=\frac{23}{6}\)
Ta có:
3/4x-1/4=2(x-3)+1/4x
<=>3/4x-1/4x=2x-6+1/4
<=>x-2x=-23/4
<=>-x=-23/4
<=>x=23/4.
Vậy x=23/4
\(\Rightarrow\frac{3}{4}x-\frac{1}{4}=2x-6+\frac{1}{4}x\)
\(\Rightarrow\frac{3}{4}x-2x-\frac{1}{4}x=-6+\frac{1}{4}\)
\(\Rightarrow-\frac{3}{2}x=-\frac{23}{4}\)
\(\Rightarrow x=\frac{23}{4}:\frac{3}{2}=\frac{23}{6}\)
\(\Rightarrow\frac{8}{9}x-\frac{1}{3}x=\frac{2}{3}+\frac{11}{3}\)
\(\Rightarrow\frac{5}{9}x=\frac{13}{3}\)
\(\Rightarrow x=\frac{13}{3}:\frac{5}{9}=\frac{39}{5}\)
\(\Rightarrow\frac{3}{4}x-\frac{1}{4}=2x-6+\frac{1}{4}x\)
\(\Rightarrow\frac{3}{4}x-2x-\frac{1}{4}x=-6+\frac{1}{4}\)
\(\Rightarrow-\frac{3}{2}x=-\frac{23}{4}\)
\(\Rightarrow x=\frac{23}{4}:\frac{3}{2}=\frac{23}{6}\)
\(\Rightarrow\frac{8}{9}x-\frac{1}{3}x=\frac{2}{3}+\frac{11}{3}\)
\(\Rightarrow\frac{5}{9}x=\frac{13}{3}\)
\(\Rightarrow x=\frac{13}{3}:\frac{5}{9}=\frac{39}{5}\)
\(4^{x+3}-3x4^{x+1}=13x4^{11}\)
\(\Rightarrow4^{x+1}x4^2-3x4^{x+1}=13x4^{11}\)
\(\Rightarrow4^{x+1}\left(16-3\right)=13x4^{11}\)
\(\Rightarrow4^{x+1}=4^{11}\)
\(\Rightarrow x+1=11\)
\(\Rightarrow x=10\)