Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(\dfrac{11}{8}-\dfrac{3}{8}\cdot x=\dfrac{1}{8}\)
\(\dfrac{3}{8}\cdot x=\dfrac{11}{8}-\dfrac{1}{8}\)
\(\dfrac{3}{8}\cdot x=\dfrac{5}{4}\)
\(x=\dfrac{5}{4}:\dfrac{3}{8}\)
\(x=\dfrac{10}{3}\)
` 11/8 - 3/8 . x = 1/8 <=> 2/8 . x = 11/8 - 1/8 <=> 2/8x = 10/8 <=> x = 10/8 : 2/8 <=> x = 5 `
4x -15 = -75 - x
4x + x = 15 -75
5x = - 60
x = - 12
Vậy kết wả của bài này là -12, nhớ nha,
4x - 15 = -75 - x
4x - 15 + x = -75
5x - 15 = -75
5x = -75 + 15
5x = -60
x = -60 : 5
x = -12
\(x-\frac{3}{4}x+\frac{1}{2}>0\)
\(\Leftrightarrow x\left(1-\frac{3}{4}\right)+\frac{1}{2}>0\)
\(\Leftrightarrow\frac{1}{4}x+\frac{1}{2}>0\)
\(\Leftrightarrow\frac{1}{4}x>\frac{1}{2}\)
\(\Leftrightarrow x>2\)
\(3x+4x-xy=15\)
\(x\left(3+4-y\right)=15\)
\(x\left(7-y\right)=15=1\cdot15=15\cdot1=3\cdot5=5\cdot3=\left(-1\right)\cdot\left(-15\right)=\left(-15\right)\cdot\left(-1\right)=\left(-3\right)\cdot\left(-5\right)=\left(-5\right)\cdot\left(-3\right)\)
+, \(\left\{{}\begin{matrix}x=1\\7-y=15\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=1\\y=7-15=-8\end{matrix}\right.\)
+, \(\left\{{}\begin{matrix}x=15\\7-y=1\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=15\\y=7-1=6\end{matrix}\right.\)
+, \(\left\{{}\begin{matrix}x=3\\7-y=5\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=3\\y=7-5=2\end{matrix}\right.\)
+, \(\left\{{}\begin{matrix}x=5\\7-y=3\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=5\\y=7-3=4\end{matrix}\right.\)
+, \(\left\{{}\begin{matrix}x=-1\\7-y=-15\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=-1\\y=7-\left(-15\right)=22\end{matrix}\right.\)
+, \(\left\{{}\begin{matrix}x=-15\\7-y=-1\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=-15\\y=7-\left(-1\right)=8\end{matrix}\right.\)
+, \(\left\{{}\begin{matrix}x=-3\\7-y=-5\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=-3\\y=7-\left(-5\right)=12\end{matrix}\right.\)
+, \(\left\{{}\begin{matrix}x=-5\\7-y=-3\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=-5\\y=7-\left(-3\right)=10\end{matrix}\right.\)
Vậy \(\text{(x;y)=(1;-8);(15;6);(3;2);(5;4);(-1;22);(-15;8);(-3;12);(-5;10)}\)
15{240-[4x(25-5x4)+80]:4}
=15.{240-[4x5+80]:4}
=15.{240-100:4}
=15.215
=3225
4x - 10 = 15 - x
=> 4x + x = 15 + 10
=> 5x = 25
=> x = 25 : 5
=> x = 5
\(a,\Rightarrow x=\dfrac{-120}{-15}=8\\ b,\Rightarrow x=\dfrac{15}{-5}=-3\\ c,\Rightarrow x=\dfrac{140}{-20}=-7\\ d,\Rightarrow x^2=5^2=\left(-5\right)^2\Rightarrow\left[{}\begin{matrix}x=5\\x=-5\end{matrix}\right.\\ e,\Rightarrow4x=-8\Rightarrow x=-2\\ g,\Rightarrow x^2=\dfrac{-12}{-3}=4\Rightarrow\left[{}\begin{matrix}x=2\\x=-2\end{matrix}\right.\)
15 - x = 4x - 5
=> 15 + 5 = 4x + x
=> 20 = 5x
=> x = 20 : 5
=> x = 4
4x :15=8
4x =8.15
4x =120
x =120:4
x =30
4x =8.15
4x =120
x =120:4
x =30