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a) \(\dfrac{5}{7}-x=-\dfrac{9}{21}\)
\(\Leftrightarrow x=\dfrac{5}{7}-\left(-\dfrac{9}{21}\right)\)
\(\Leftrightarrow x=\dfrac{15}{21}+\dfrac{9}{21}\)
\(\Leftrightarrow x=\dfrac{24}{21}=\dfrac{8}{7}\)
Vậy: \(x=\dfrac{8}{7}\)
b) \(-x-\dfrac{1}{9}=-\dfrac{2}{45}\)
\(\Leftrightarrow x+\dfrac{1}{9}=\dfrac{2}{45}\)
\(\Leftrightarrow x=\dfrac{2}{45}-\dfrac{1}{9}\)
\(\Leftrightarrow x=\dfrac{2}{45}-\dfrac{5}{45}\)
\(\Leftrightarrow x=-\dfrac{3}{45}=-\dfrac{1}{15}\)
Vậy: \(x=-\dfrac{1}{15}\)
c) \(\left|x+\dfrac{5}{6}\right|=\dfrac{11}{24}\)
\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{5}{6}=\dfrac{11}{24}\\x+\dfrac{5}{6}=-\dfrac{11}{24}\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{11}{24}-\dfrac{5}{6}\\x=-\dfrac{11}{24}-\dfrac{5}{6}\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{11}{24}-\dfrac{20}{24}\\x=-\dfrac{11}{24}-\dfrac{20}{24}\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{9}{24}=-\dfrac{3}{8}\\x=-\dfrac{31}{24}\end{matrix}\right.\)
Vậy: \(x=-\dfrac{31}{24};-\dfrac{3}{8}\)
_Chúc bạn học tốt_
a, 5/7- x=-9/21=-3/7
x = 5/7 - (-3)/7
x=8/7
Vậy x=8/7 là giá trị cần tìm
Câu 1:
( 2 + 4 + 6 + ... + 40 ) - x = 280
SSH là : ( 40 - 2 ) : 2 + 1 = 20 ( số )
Tổng là : ( 40 + 2 ) . 20 : 2 = 420
=> 420 - x = 280
=> x = 140
P/s : mk làm từng phần một nha
( x + 3 ) + ( x + 5 ) + ( x + 7 ) + ( x + 9 ) = 72
4x + 24 = 72
4x = 48
x = 12
1) -5x - (-3) = 13
\(\Rightarrow-5x+3=13\)
\(\Rightarrow-5x=10\)
\(\Rightarrow x=-2\)
Vậy: \(x=-2\)
2) 15 - ( x - 7) = -21
\(\Rightarrow15-x+7=-21\)
\(\Rightarrow15+7-x=-21\)
\(\Rightarrow22-x=-21\)
\(\Rightarrow x=-22-21=-43\)
Vậy: \(x=-43\)
3) 45 - ( x - 9) = -35
\(\Rightarrow45-x+9=-35\)
\(\Rightarrow45+9-x=-35\)
\(\Rightarrow54-x=-35\)
\(\Rightarrow x=-54-35=-89\)
Vậy: \(x=-89\)
4)/x-2/=3\(\Rightarrow\)ta có 2 t/h:
t/h1: x-2=3\(\Rightarrow\)x=2+3=5
t/h2: x-2=-3\(\Rightarrow\)x=2+(-3)=-1
Vậy x=5 hoặc -1
a) \(\frac{18}{45}-\frac{4}{12}-\frac{6}{9}-\frac{21}{35}=\frac{2}{5}-\frac{1}{3}-\frac{2}{3}-\frac{3}{5}\)
\(=\left(\frac{2}{5}-\frac{3}{5}\right)-\left(\frac{1}{3}+\frac{2}{3}\right)\)
\(=\frac{-1}{3}-1\)
\(=\frac{-4}{3}\)
b) \(\frac{4}{3}+\frac{3}{5}+\frac{7}{3}+\frac{2}{5}+\frac{1}{3}=\left(\frac{4}{3}+\frac{7}{3}+\frac{1}{3}\right)+\left(\frac{3}{5}+\frac{2}{5}\right)\)
\(=4+1=5\)
c) \(\frac{1}{3}.\frac{4}{5}.\frac{1}{3}.\frac{6}{5}=\frac{8}{75}\)
d) \(\frac{6}{7}.\frac{8}{13}+\frac{6}{7}.\frac{9}{13}-\frac{3}{13}.\frac{6}{7}\)
\(=\frac{6}{7}.\left(\frac{8}{13}+\frac{9}{13}-\frac{3}{13}\right)\)
\(=\frac{6}{7}.\frac{14}{13}\)
\(=\frac{12}{13}\)
cau1 :120-(100+x)=25
100+x=120-25
100+x=95
x=-5
cau2: 5(x+23)+6=96
5(x+23)+6=96
5(x+23)=90
x+23=18
x=-5
cau3: 100-(25+x)=40
25+x=100-40
25+x=60
x=35
cau4: 35-9(x+2)=45
9(x+2)=-10
x+2=-10/9
x=-28/9
-6/18 + 10/18 + 3/18 < x < 95/45 + 9/45 + 2/45
4/18 + 3/18 < x < 104/45 + 2/45
7/18 < x < 106/45
10/45 < x < 106/45
Vậy x = 11/45,12/45,13/45,.......,105/45
Lời giải:
$45-(x+9):2=6$
$(x+9):2=45-6=39$
$x+9=39\times 2=78$
$x=78-9=69$
\(45-\left(x+9\right):2=6\)
\(45-\left(x+9\right)=6\times2\)
\(45-\left(x+9\right)=12\)
\(\left(x+9\right)=45-12\)
\(\left(x+9\right)=33\)
\(x=33-9\)
\(x=24\)