
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.


a) 0 < 101/100;51/50;103/100;26/25<1/4+4/5
b) 4/7+3/7<11/10;6/5;13/10;7/5;3/2;8/5;17/10;9/5;19/10;2;21/10;11/5<5/3+2/3
K MK NHA

\(\frac{3}{4}x\frac{4}{5}:\frac{3}{5}x\frac{6}{7}:\frac{1}{7}x\frac{5}{6}\)\(=\)\(\frac{3}{4}x\frac{4}{5}x\frac{5}{3}x\frac{6}{7}x\frac{7}{1}x\frac{5}{6}\)\(=\)\(\frac{3x4x5x6x7x5}{4x5x3x7x1x6}\)\(=\)\(\frac{\left(3\right)x\left(4\right)x\left(5\right)x\left(6\right)x\left(7\right)x5}{\left(3\right)x\left(4\right)x\left(5\right)x\left(6\right)x\left(7\right)x1}\)\(=\)\(\frac{5}{1}\)\(=\)\(5\).

Ta có:
\(\frac{4}{3}+\frac{3}{7}:\frac{5}{14}\)
\(=\frac{4}{3}+\left(\frac{3}{7}:\frac{5}{14}\right)\)
\(=\frac{4}{3}+\left(\frac{3}{7}×\frac{14}{5}\right)\)
\(=\frac{4}{3}+\left(\frac{3×14}{7×5}\right)\)
\(=\frac{4}{3}+\left(\frac{3×7×2}{7×5}\right)\)
\(=\frac{4}{3}+\left(\frac{3×2}{5}\right)\)
\(=\frac{4}{3}+\frac{6}{5}\)
\(=\frac{4×5}{3×5}+\frac{6×3}{5×3}\)
\(=\frac{20}{15}+\frac{18}{15}\)
\(=\frac{20+18}{15}\)
\(=\frac{38}{15}\)
\(\frac{4}{3}+\frac{3}{7}\)\(:\frac{5}{14}\)
\(=\frac{4}{3}+\frac{3}{7}\times\frac{14}{5}\)
\(=\frac{4}{3}+\frac{6}{9}\)
\(=\frac{20}{15}+\frac{18}{15}\)
\(=\frac{38}{15}\)

2/3 x X = 1/4 X x 1/5 = 1/2 X : 7/8 = 2/3
X = 1/4 : 2/3 X = 1/2 : 1/5 X = 2/3 x 7/8
X = 3/8 X = 5/2 X = 7/12
chúc bạn học tôt

3/7 + 4/9 + 5/11 + 8/14 + 10/18 + 12/22
= 3/7 + 4/9 + 5/11 + 4/7 + 5/9 + 6/11
= ( 3/7 + 4/7 ) + ( 4/9 + 5/9 ) + ( 5/11 + 6/11 )
= 7/7 +9/9 + 11/11
= 1 + 1 + 1
= 3
tk mk nha , cảm ơn ạ , được ko á ?????????
3/7 + 4/9 + 5/11 + 8/14 + 10/18 + 12/22 = 3

7/8 + 3/4=13/8
3/2 + 4/5=23/10
6/7 * 5/6=5/7
5/6 : 8/9=15/16
\(\frac{7}{8}+\frac{3}{4}=\frac{28}{32}+\frac{24}{32}=\frac{52}{32}\)
\(\frac{3}{2}+\frac{4}{5}=\frac{15}{10}+\frac{8}{10}=\frac{23}{10}\)
\(\frac{6}{7}x\frac{5}{6}=\frac{30}{42}\)
\(\frac{5}{6}:\frac{8}{9}=\frac{5}{6}x\frac{9}{8}=\frac{45}{48}\)

Bài 1:
\(\dfrac{2}{3}\) + \(\dfrac{3}{4}\) - \(\dfrac{2}{5}\)
=\(\dfrac{40}{60}\) + \(\dfrac{45}{60}\) - \(\dfrac{24}{60}\)
= \(\dfrac{61}{60}\)
b; \(\dfrac{12}{13}\) x \(\dfrac{3}{4}\) - \(\dfrac{7}{13}\)
= \(\dfrac{9}{13}\) - \(\dfrac{7}{13}\)
= \(\dfrac{2}{13}\)
c; \(\dfrac{15}{17}\) : \(\dfrac{19}{34}\) - \(\dfrac{17}{19}\)
= \(\dfrac{15}{17}\) x \(\dfrac{34}{19}\) - \(\dfrac{17}{19}\)
= \(\dfrac{30}{19}\) - \(\dfrac{17}{19}\)
= \(\dfrac{13}{19}\)
Bài 2:
a; \(\dfrac{x}{5}\) x \(\dfrac{3}{7}\) = \(\dfrac{9}{35}\)
\(\dfrac{x}{5}\) = \(\dfrac{9}{35}\) : \(\dfrac{3}{7}\)
\(\dfrac{x}{5}\) = \(\dfrac{3}{5}\)
\(x\) = \(\dfrac{3}{5}\) x 5
\(x\) = 3
4/5 . x = 3/7
x = 3/7 : 4/5
x = 3/7. 5/4
x = 15/28
Vậy x =...
x=\(\frac{3}{7}:\frac{4}{5}=\frac{3}{7}\cdot\frac{5}{4}=\frac{15}{28}\)