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UC (144;120)=Ư( 24) ={1 ;2 ;3;4;6;8;12;24}
Vậy phần tử của nó là 8
B)
28=22.7
48=24.3
ƯCLN (28,48)= 2.3.7=42.
d)ƯCLN(51, 102, 144) = 3, suy ra ƯC(51, 102, 144) = {1; 3}
\(2^7.3^8.4^9.9^8\)
\(=2^7.3^8.\left(2^2\right)^9.\left(3^2\right)^8\)
\(=2^7.3^8.2^{18}.3^{16}\)
\(=2^{19}.3^{24}\)
\(a,=251+\left(-151\right)+\left(-144\right)+\left(-216\right)=100+-360=-260\)
\(b,=-178+\left(-172\right)+58+350=-350+350+58=58\)
\(c,=\left(-37\right)+\left(-163\right)+\left(-70\right)+354+146=-270+500=230\)
\(d,=\left(-4795\right)+\left(-205\right)+3029+1971=-5000+5000=0\)
\(a)\)\(251+\left(-144\right)+\left(-151\right)+\left(-216\right)\)
\(=\)\(251+\left(-151\right)+\left(-144\right)+\left(-216\right)\)
\(=\)\(100+\left(-360\right)\)
\(=\)\(100-360\)
\(=\)\(-260\)
\(b)\)\(-359+181+\left(-123\right)+350+\left(-172\right)\)
\(=\)\(-178+\left(-172\right)+58+350\)
\(=\)\(-350+350+58\)
\(=\)\(0+58\)
\(=\)\(58\)
a) \(-\frac{11}{18}\)
b)\(-\frac{3}{2}\)
c)\(\frac{49}{78}\)
d)\(\frac{23}{11}\)
e) \(\frac{11.12+22.24+44.48}{33.36+66.72+132.144}\)
\(=\frac{11.12+22.24+44.48}{11.3.12.3+22.3.3.24+44.3.348}\)
\(=\frac{11.12+22.24+44.48}{\left(1.12+22.24+44.48\right).9}\)
\(=\frac{1}{9}\)
13 + 21.5 - (198 : 11 - 8)
= 13 + 105 - 10
= 108
272 : 16 - 5 +4 (30 - 5 - 255 : 17)
= 17 - 5 + 4. ( 30 - 5 - 15 )
= 16 . 10
= 160
15.24 - 14.5 (145 : 5 - 27)
= 360 - 70 ( 29 - 27 )
= 290 . 2
= 580
18.3 - 18.2 + 3 (51 : 17)
= 54 - 36 + 3 . 3
= 54 - 36 + 9
= 27
(64 + 115 + 36) - 25.8
= 215 - 200
= 15
15.8 - (17 - 30 + 83) - 144 : 6
= 120 - 70 - 24
= 26
250 : 50 - (46 - 75 + 54) : 5
= 5 - 25 : 5
= 5 - 5
= 0
13 (17 - 95 + 83) : 5 - 18 : 9
= 13. 5 : 5 - 2
= 65 : 5 - 2
= 13 - 2
= 11
140 - 180(47 - 90 + 43) + 7
= 140 - 180 . 0 + 7
= 140 + 7
= 147
24 (15 + 30 + 85 - 120):10
= 24. 10 : 10
= 240 : 10
= 24
27 + 73 - 30 : (25 -10)
= 27 + 73 - 30 : 15
= 27 + 73 - 2
= 98
18 - 4 (27 - 90 + 73) : 10
= 18 - 4. 10 : 10
= 18 - 40 : 10
= 18 - 4
= 14
Bài 2: Tính
140 - [ 25 : (4 mũ 2 - 11) + 4 ]
= 140 - [25 : (16 - 11) + 4 ]
= 140 - [ 25 : 5 + 4 ]
= 140 - [ 5 + 4]
= 140 - 9
= 131
2:
a: \(2^2\cdot3-4=4\cdot3-4=12-4=8\)
b: \(16-2^3\cdot2=16-2^4=16-16=0\)
c: \(4^2-4\cdot2=16-8=8\)
d: \(3^3-2\cdot3^2=27-2\cdot9=27-18=9\)
e: \(7^2-9\cdot2^2=49-9\cdot4=49-36=13\)
f: \(2^2\cdot3+4^2=4\cdot3+16=12+16=28\)
Bài 1:
a: \(13+21\cdot5-\left(198:11-8\right)\)
\(=13+105-18+8\)
=21+87
=108
b: \(272:16-5+4\cdot\left(30-5-255:17\right)\)
\(=17-5+4\cdot\left(30-5-15\right)\)
\(=12+4\cdot10=12+40=52\)
c: \(15\cdot24-14\cdot5\cdot\left(145:5-27\right)\)
\(=360-70\left(29-27\right)\)
=360-140
=220
d: \(18\cdot3-18\cdot2+3\cdot\left(\dfrac{51}{17}\right)\)
\(=18\left(3-2\right)+3\cdot3\)
=18+9
=27
e: \(64+115+36-25\cdot8\cdot6\cdot2^2\cdot3+4^2\)
\(=100+115-200\cdot6\cdot4\cdot3+16\)
\(=231-14400=-14169\)
f: \(15\cdot8-\left(17-30+83\right)-144:6\)
\(=120-24-\left(100-30\right)\)
=96-70
=26
a) 7.(x-5) +2 = 51
=> 7.(x-5) = 49
=> x-5 = 7
=> x= 12
b)\(\left(4^3-11.x\right).5^3=4.5^4\)
\(\Rightarrow\left(64-11.x\right).125=2500\)
\(\Rightarrow64-11.x=20\)
\(\Rightarrow11.x=44\)
\(\Rightarrow x=4\)
44. 51 - ( -51) . ( -144) = 44. 51 + 51 . ( -144 )
= 51 . [ 44 + ( -144) ]
= 51 . ( -100)
= - 5100.
HOK TỐT😚😚