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1. \(6x^3-8=40\\ 6x^3=48\\ x^3=8\\ \Rightarrow x=2\)Vậy x = 2
2. \(4x^5+15=47\\ 4x^5=32\\ x^5=8\\ \Rightarrow x\in\varnothing\left(\text{vì }x\in N\right)\)Vậy x ∈ ∅
3. \(2x^3-4=12\\ 2x^3=16\\ x^3=8\\ \Rightarrow x=2\)Vậy x = 2
4. \(5x^3-5=0\\ 5x^3=5\\ x^3=1\\ \Rightarrow x=1\)Vậy x = 1
5. \(\left(x-5\right)^{2016}=\left(x-5\right)^{2018}\\ \Rightarrow\left[{}\begin{matrix}x-5=0\\x-5=1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=5\\x=6\end{matrix}\right.\)Vậy \(x\in\left\{5;6\right\}\)
6. \(\left(3x-2\right)^{20}=\left(3x-1\right)^{20}\\ \Rightarrow3x-2=3x-1\\ 3x-3x=2-1\\ 0=1\left(\text{vô lí}\right)\)Vậy x ∈ ∅
7. \(\left(3x-1\right)^{10}=\left(3x-1\right)^{20}\\ \left(3x-1\right)^{10}=\left[\left(3x-1\right)^2\right]^{10}\\ \Rightarrow\left(3x-1\right)^2=3x-1\\ \left(3x-1\right)^2-\left(3x-1\right)=0\\ \left(3x-1\right)\left[\left(3x-1\right)-1\right]=0\\ \left(3x-1\right)\left(3x-2\right)=0\\ \Rightarrow\left[{}\begin{matrix}3x-1=0\\3x-2=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}3x=1\\3x=2\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\frac{1}{3}\left(\text{loại vì }x\in N\right)\\x=\frac{2}{3}\left(\text{loại vì }x\in N\right)\end{matrix}\right.\)Vậy x ∈ ∅
8. \(\left(2x-1\right)^{50}=2x-1\\ \left(2x-1\right)^{50}-\left(2x-1\right)=0\\ \left(2x-1\right)\left[\left(2x-1\right)^{49}-1\right]=0\\ \Rightarrow\left[{}\begin{matrix}2x-1=0\\\left(2x-1\right)^{49}=1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}2x=1\\2x-1=1\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\frac{1}{2}\left(\text{loại vì }x\in N\right)\\x=1\left(t/m\right)\end{matrix}\right.\)Vậy x = 1
9. \(\left(\frac{x}{3}-5\right)^{2000}=\left(\frac{x}{3}-5\right)^{2008}\\ \left(\frac{x}{3}-5\right)^{2008}-\left(\frac{x}{3}-5\right)^{2000}=0\\ \left(\frac{x}{3}-5\right)^{2000}\left[\left(\frac{x}{3}-5\right)^8-1\right]=0\\ \Rightarrow\left[{}\begin{matrix}\left(\frac{x}{3}-5\right)^{2000}=0\\\left(\frac{x}{3}-5\right)^8=1\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}\frac{x}{3}-5=0\\\frac{x}{3}-5=1\\\frac{x}{3}-5=-1\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}\frac{x}{3}=5\\\frac{x}{3}=6\\\frac{x}{3}=4\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=5\cdot3=15\\x=6\cdot3=18\\x=4\cdot3=12\end{matrix}\right.\)Vậy \(x\in\left\{15;18;12\right\}\)
\(1.6x^3-8=40\\ \Leftrightarrow6x^3=48\\ \Leftrightarrow x^3=8\Leftrightarrow x^3=2^3=\left(-2\right)^3\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-2\end{matrix}\right.\)
Vậy \(x\in\left\{2;-2\right\}\)
\(2.4x^3+15=47\) (T nghĩ đề là mũ 3)
\(\Leftrightarrow4x^3=32\Leftrightarrow x^3=8=2^3=\left(-2\right)^3\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-2\end{matrix}\right.\)
Vậy \(x\in\left\{2;-2\right\}\)
Câu 3, 4 tương tự nhé.
\(a,-7x+7=21\)
\(\Rightarrow-7x=21-7=14\)
\(\Rightarrow x=-2\)
\(b,9x+11=20x+66\)
\(\Rightarrow9x-20x=66-11=55\)
\(\Rightarrow-11x=55\)
\(\Rightarrow x=-5\)
\(c,3^3.x+4^2=5^2.x-2.\left(2017\right)^0\)
\(27x+16=25x-2\)
\(\Rightarrow16+2=25x-27x=-2x\)
\(\Rightarrow-2x=18\)
\(\Rightarrow x=-9\)
1) 15:(x+2) = 3
x + 2 = 15 : 3
x + 2 = 5
x = 5 - 2
x = 3
2) 20:(1+x) = 2
1 + x = 20 : 2
1 + x = 10
x = 10 - 1
x = 9
3) 5(x+35) = 515
x + 35 = 515 : 5
x + 35 = 103
x = 103 - 35
x = 68
4) 541+(218-x) = 73
218 - x = 73 - 541
218 - x = -468
x = 218 - ( - 468 )
x = 686
5) 1230:3 (x-20) = 10
410 . ( x - 20 ) = 10
x - 20 = 10 : 410
x - 20 = 1/41
x = 1/41 + 20
x = 821/41
6) 48-3(x+5) = 24
3( x + 5 ) = 48 - 24
3( x + 5 ) = 24
x + 5 = 24 : 3
x + 5 = 8
x = 8 - 5
x = 3
7) 4x + 18 : 2=13
4x + 9 = 13
4x = 13 - 9
4x = 4
x = 1
8) X-48:16 = 37
x - 3 = 37
x = 37 + 3
x = 40
a, 15: (x+2) = 3
x+2 =15:3
x+2 = 5
x = 5-2
x = 3
b, 20: (1+x) = 2
1+x = 20:2
1+x = 10
x = 10-1
x = 9
c, 5(x+35) = 515
x+35 = 515 :5
x+35 = 103
x = 103-35
x = 68
d, 541+ (218-x) = 73
218-x = 73-541
218-x = - 468
x = 218 - (-468)
x = 218 + 468
x = 686
e, 1230:3. (x-20) = 10
410(x-20) = 10
x-20 = 10: 410
x-20 = 1/41
x = 1/41 + 20
x = 821/41
f, 48-3(x+5) = 24
3(x+5) = 48-24
3(x+5) = 24
x+5 = 24:3
x +5 = 8
x = 8-5
x =3
g, 4x + 18 : 2 = 13
4x + 9 = 13
4x = 13-9
4x = 4
x = 4:4
x = 1
j, x - 48:16 = 37
x- 3 = 37
x = 37+3
x = 40
a) 3^x.9^6=3^14 b,27^9.(3^x) = 3^31
=3^x.3^12=3^14 =>3^27.(3^x)^2=3^31
=> 3^x+12=3^14 => (3^x)^2=3^31.3^27
=> x=2 =>(3^x)^2=3^4=>2^x=4
=>x=2
a) x+15 = 20-4x
=> x=1
b) 17-x=7-6x
=> x=-2
c) -12+x=5x-20
=> x=2
d) 4x-5=15-x
=> x=4
e) 9x-7=20-6x
=>x= \(\frac{9}{5}\)
g)2.(x-10)=3.(x-20)=x-4
=> x thuộc ∅
h) (x^2+2).(x-3) <0
=> x=3,...
1. 11(x-9)=77
x-9=7
x=16
2. 4(x-3)=48
x-3=12
x=15
3.3(x-8)=81
(x-8)=27
x=35
Lời giải:
$3x+5x+2x=20$
$x(3+5+2)=20$
$x.10=20$
$x=20:10=2$
Thanks co ah