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3x+2=369
=>x+2=69
x=69-2
x=67
2x-5=810
2x-5=230
=>x-5=30
x=30+5
x=35
3x+2+3x=810
3x.32+3x=810
3x.(32+1)=810
3x.10=810
3x=810:10
3x=81
3x=34
=>x=4
5x+1-5x=500
5x.5-5x=500
5x.(5-1)=500
5x.4=500
5x=500:4
5x=125
5x=53
=>x=3
a) 3x+2 = 369
x + 2 = 69
x = 69 - 2
x = 67
b) 2x-5 = 810
2x-5 = 230
x - 5 = 30
x = 30 + 5
x = 35
c) 3x+2 + 3x = 810
3x . 9 + 3x . 1 = 810
3x . ( 9 + 1 ) = 810
3x . 10 = 810
3x = 810 : 10
3x = 81
3x = 34
=> x = 4
d) 5x+1 - 5x = 500
5x . 5 - 5x . 1 = 500
5x . ( 5 - 1 ) = 500
5x . 4 = 500
5x = 500 : 4
5x = 125
5x = 53
=> x = 3
\(3^x+3^{x+2}=810\)
\(\rightarrow3\left(x+x+2\right)=810\)
\(\rightarrow x+x+2\)\(=810:3\)
\(\rightarrow2x+2\) \(=270\)
\(\rightarrow2x\) \(=270-2\)
\(\rightarrow2x\) \(=268\)
\(\rightarrow x\) \(=134\)
Tk cho mk nhé thks nhìu!
CHÚC BẠN HỌC TỐT!
=>\(\left(3^2+1\right).3^{x+1}=810\)
=>\(3^{x+1}=81\)
=>\(3^{x+1}=3^4\)
=>x+1=4
=> x=3
3x+1 +3x+3=810
<=> 3x.3 +3x.3.3.3=810
<=>3x.(3+3.3.3)=810
<=>3x.30=810
<=>3x=27
<=>x=3
vậy x=3
bạn k cho mình nha :))
e,
\(2^x-15=17\\ 2^x=17+15\\ 2^x=32\\ 2^x=2^5\\ x=5\)
Vậy \(x=5\)
d,
\(\left(x-1\right)^5-\left(x-1\right)^2=0\\ \left(x-1\right)^2\cdot\left[\left(x-1\right)^3-1\right]=0\\ \Rightarrow\left[{}\begin{matrix}\left(x-1\right)^2=0\\\left(x-1\right)^3-1=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x-1=0\\\left(x-1\right)^3=1\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=1\\\left(x-1\right)^3=1^3\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=1\\x-1=1\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=1\\x=2\end{matrix}\right.\)
Vậy \(x=1\) hoặc \(x=2\)
mấy câu còn lại coi lại đề
Bài 1
a, 23 + ( x - 32 ) = 1
x - 32 = 1 - 23 = -7
x = -7 + 32
x = 2
b, 5 . (x+7) -10 = 40
5 . (x+7) = 50
x+7 = 50 :5 =10
x = 10 - 7
x = 3
c)
\(\left|\dfrac{2}{3}x-\dfrac{1}{2}\right|-1=\dfrac{5}{6}\)
\(\Leftrightarrow\left|\dfrac{4x-3}{6}\right|=1+\dfrac{5}{6}=\dfrac{11}{6}\)
\(\Leftrightarrow\left|4x-3\right|=11\Leftrightarrow\left[{}\begin{matrix}4x-3=11=>x=\dfrac{11+3}{4}=\dfrac{7}{2}\\4x-3=-11=>x=\dfrac{-8}{2}=-4\end{matrix}\right.\)
Tìm x :
a) \(2.x.\frac{-3}{4}=-\frac{5}{12}\)
\(\Rightarrow2x=-\frac{5}{12}:-\frac{3}{4}\)
\(\Rightarrow2x=\frac{5}{9}\)
\(\Rightarrow x=\frac{5}{9}:2\)
\(\Rightarrow x=\frac{5}{18}\)
Vậy : \(x=\frac{5}{18}\)
b) \(\frac{2}{3}+\frac{1}{3}.x=7\)
\(\Rightarrow\frac{1}{3}.x=7-\frac{2}{3}\)
\(\Rightarrow\frac{1}{3}.x=\frac{19}{3}\)
\(\Rightarrow x=\frac{19}{3}:\frac{1}{3}\)
\(\Rightarrow x=19\)
Vậy : \(x=19\)
c) \(\left(4.x+\frac{1}{8}\right)=\frac{3}{10}\)
\(\Rightarrow4.x=\frac{3}{10}-\frac{1}{8}\)
\(\Rightarrow4.x=\frac{7}{40}\)
\(\Rightarrow x=\frac{7}{40}:4\)
\(\Rightarrow x=\frac{7}{160}\)
Vậy : \(x=\frac{7}{160}\)
d) \(\frac{1}{3}.x-5=1\frac{1}{2}\)
\(\Rightarrow\frac{1}{3}.x-5=\frac{3}{2}\)
\(\Rightarrow\frac{1}{3}.x=\frac{3}{2}+5\)
\(\Rightarrow\frac{1}{3}.x=\frac{13}{2}\)
\(\Rightarrow x=\frac{13}{2}:\frac{1}{3}\)
\(\Rightarrow x=\frac{39}{2}\)
Vậy : \(x=\frac{39}{2}\)
e) \(-\frac{2}{3}.x+\frac{1}{3}=-\frac{1}{2}\)
\(\Rightarrow-\frac{2}{3}.x=-\frac{1}{2}-\frac{1}{3}\)
\(\Rightarrow-\frac{2}{3}.x=-\frac{5}{6}\)
\(\Rightarrow x=-\frac{5}{6}:\left(-\frac{2}{3}\right)\)
\(\Rightarrow x=\frac{5}{4}\)
Vậy : \(x=\frac{5}{4}\)
3x+2 + 3x = 810
=> 3x . 32 + 3x = 810
=> 3x . (32 + 1) = 810
=> 3x . (9 + 1) = 810
=> 3x . 10 = 810
=> 3x = 810 : 10
=> 3x = 81 = 34
=> x = 4
Vậy x = 4
Ủng hộ mk nha ^_-
3x + 3x+2 = 810
3x.1 + 3x.1 3x.2 = 810
3x . ( 1 + 32 ) = 810
3x . 10 = 810
3x = 810 : 10 = 81
=> X = 4.