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20 tháng 11 2017

\(\left(35x^6y^7-25x^5y^5\right):5x^3y^5-7x^3y^2\)

\(=7x^3y^2-5x^2-7x^3y^2\)

\(=-5x^2\)

20 tháng 11 2017

cảm ơn

27 tháng 9 2017

a) 5x2y2 + 20x2y4 - 35x5y3 

= \(5x^2y^2\left(1+4y-7x^3y\right)\)

b) 2x ( x + y ) - 7x - 7y

\(=2x\left(x+y\right)-7\left(x+y\right)=\left(2x-7\right)\left(x+y\right)\)

c) 5x^2 ( x - 1 ) + 5 ( 1 - x )

\(5x^2\left(x+1\right)+5\left(1-x\right)=5x^2\left(x-1\right)-5\left(x-1\right)=\left(5x^2-5\right)\left(x-1\right)=5\left(x^2-1\right)\left(x+1\right)\)

= 5(x+1)(x-1)(x-1) = 5(x+1)(x-1)^2

28 tháng 7 2015

??                       

13 tháng 6 2019

a) \(3y^2\left(2y-1\right)+y-y\left(1-y+y^2\right)-y^2+y \)

= \(6y^3-3y^2+y-y+y^2-y^3-y^2+y\)

= \(5y^3-3y^2+y\)

b)\(25x-4\left(3x-1\right)+\left(5-2x\right)7\)

= \(25x-12x+4+35-14x\)

= \(-x+39\)

c) \(11x-2\left(10x-1\right)-\left(4x-1\right)\left(-2\right)\)

= \(11x-\left(20x-2\right)-\left(-8x+2\right)\)

= \(11x-20x+2+8x-2\)

= \(-x\)

d) \(\left(\frac{1}{2x}\right)3-x\left(1-2x-\frac{1}{8x^2}\right)-x\left(x+\frac{1}{2}\right)\)

= \(\frac{3}{2x}-x+2x^2+\frac{x}{8x^2}-x^2-\frac{x}{2}\)

= \(\left(\frac{3}{2x}+\frac{1}{8x}-\frac{x}{2}\right)+x^2-x\)

= \(\left(\frac{12+1-4x^2}{8x}\right)+x^2-x\)

= \(\frac{13-4x^2}{8x}+\frac{8x^3}{8x}-\frac{8x^2}{8x}\)

= \(\frac{13-4x^2+8x^3-8x^2}{8x}\)

= \(\frac{8x^3-12x^2+13}{8x}\)

= x2 - \(\frac{3}{2}\)+\(\frac{13}{8x}\)

e) \(12\left(2-3x\right)+35x-\left(x+1\right)\left(-5\right)\)

= \(24-36x+35x-\left(-5x-5\right)\)

= \(24-36x+35x+5x+5\)

= 4x + 29

câu d:(-1/2x)3-x.(1-2x-1/8x2)-x.(x+1/2) nha

16 tháng 7 2018

1)  \(x^6-x^4-9x^3+9x^2\)

\(=x^2\left(x^4-x^2-9x+9\right)\)

\(=x^2\left[x^2\left(x^2-1\right)-9\left(x-1\right)\right]\)

\(=x^2\left(x-1\right)\left[x^2\left(x+1\right)-9\right]\)

\(=x^2\left(x-1\right)\left(x^3+x^2-9\right)\)

2)   \(x^4-4x^3+8x^2-16x+16\)

\(=x^2\left(x^2+4\right)-4x\left(x^2+4\right)+4\left(x^2+4\right)\)

\(=\left(x^2+4\right)\left(x-2\right)^2\)

18 tháng 7 2018

3) \(x^4-25x^2+20x-4=x^4+5x^3-2x^2-5x^3-25x^2+10x+2x^2+10x-4\)

\(=x^2\left(x^2+5x-2\right)-5x\left(x^2+5x-2\right)+2\left(x^2+5x-2\right)\)

\(=\left(x^2+5x-2\right)\left(x^2-5x+2\right)\)

4) \(5x\left(x-2y\right)+2\left(2y-x\right)^2\)\(=5x\left(x-2y\right)+2\left(x-2y\right)^2=\left(x-2y\right)\left(5x+2x-4y\right)=\left(x-2y\right)\left(7x-4y\right)\)

5) \(x^2\left(x^2-6\right)-x^2+9=x^4-7x^2+9\)

\(=x^4+x^3-3x^2-x^3-x^2+3x-3x^2-3x+9\)

\(=x^2\left(x^2+x-3\right)-x\left(x^2+x-3\right)-3\left(x^2+x-3\right)\)

\(=\left(x^2+x-3\right)\left(x^2-x-3\right)\)

6) \(7x\left(y-4\right)^2-\left(4-y\right)^3=7x\left(y-4\right)^2+\left(y-4\right)^3=\left(y-4\right)^2\left(7x+y-4\right)\)

7) \(x^3+2x^2-6x-27=x^3-3x^2+5x^2-15x+9x-27\)

\(=x^2\left(x-3\right)+5x\left(x-3\right)+9\left(x-3\right)=\left(x-3\right)\left(x^2+5x+9\right)\)

16 tháng 7 2016

1^2-2^2+.......................+2011^2-2012^2=(-1)(1+2)+(-1)(3+4)+.....................+(-1)(2011+2012)=(-1)(1+2+3+..........+2011+2012)=-2025078