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a) 27/82 < 26/75 ( 2025/6250 < 2132\6250)
b) -49/78 > 64/ -95 ( - 3136/7410 > -4992/7410)
c) ta có: \(A=\frac{54.107-53}{53.107}=\frac{53.107+(107-53)}{53.107+54}=\frac{53.107+54}{53.107+54}=1\)
\(B=\frac{135.269-133}{134.269+135}=\frac{134.269+\left(269-133\right)}{134.269+135}=\frac{134.269+136}{134.269+135}>1\)
\(\Rightarrow A< B\)
d) ta có: \(A=\frac{3^{10}+1}{3^9+1}=\frac{3.\left(3^9+1\right)-2}{3^9+1}=\frac{3.\left(3^9+1\right)}{3^9+1}-\frac{2}{3^9+1}=3-\frac{2}{3^9+1}\)
\(B=\frac{3^9+1}{3^8+1}=\frac{3.\left(3^8+1\right)-2}{3^8+1}=\frac{3.\left(3^8+1\right)}{3^8+1}-\frac{2}{3^8+1}=3-\frac{2}{3^8+1}\)
mà \(\frac{2}{3^9+1}< \frac{2}{3^8+1}\Rightarrow3-\frac{2}{3^9+1}< 3-\frac{2}{3^8+1}\)
=> A < B
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85 = (23)5 = 215 = 2 .214 = 2. (22)7 = 2.47 và 3.47
Vì 2< 3 nên 2.47 < 3.47
Vậy 85 < 3.47
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có:
85=(23)5=215=2.214
3.47=3.(22)7=3.214
Vì 2.214<3.214 =>85 <3.47
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Ta có:
85 = (4 . 2)5 = 45 . 25 = 45 . 31
3 . 47 = 3 . 45 . 42 = 3 . 45 . 16 = 45 . 48
Vì 48 > 31 nên 85 < 3 . 47
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Ta có : 85 = 215 = 214 . 2 (1)
Ta có : 3.47 =3 . 214 (2)
Từ (1) và (2) suy ra 85 <3 . 47
Ta có:
\(3.4^{49}< 4.4^{49}=4^{50}=\left(4^2\right)^{25}=16^{25}\left(1\right)\)
\(3^{75}=\left(3^3\right)^{25}=27^{25}\left(2\right)\)
Từ \(\left(1\right),\left(2\right)\) suy ra:
\(3^{75}=27^{25}>16^{25}=4^{50}>3.4^{49}\\ \Rightarrow3^{75}>3.4^{49}\)
Đpcm