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\(\left(x-3\right)^2=\left(x-3\right)^3\Leftrightarrow\left(x-3\right)^3-\left(x-3\right)^2=0\)
\(\Leftrightarrow\left(x-3\right)^2\left[x-3-1\right]=0\Leftrightarrow\left(x-3\right)^2\left(x-4\right)=0\Leftrightarrow x=3;x=4\)
\(10-\left\{\left[\left(x:4+15\right):10+3.2^4\right]:10\right\}=5\)
\(\Leftrightarrow\left[\left(\dfrac{x}{4}+15\right):10+3.16\right]:10=5\)
\(\Leftrightarrow\left(\dfrac{x}{4}+15\right):10+48=50\Leftrightarrow\left(\dfrac{x}{4}+15\right):10=2\Leftrightarrow\dfrac{x}{4}+15=20\)
\(\Leftrightarrow x=20\)
6, \(x=\dfrac{9}{2}+\dfrac{1}{2}=\dfrac{10}{2}=5\)
7, \(x=-\dfrac{3}{4}-\dfrac{5}{4}=-\dfrac{8}{4}=-2\)
8, \(x=\dfrac{5}{7}-\dfrac{2}{7}=\dfrac{3}{7}\)
9, \(x=\dfrac{1}{3}+\dfrac{4}{3}=\dfrac{5}{3}\)
10, \(x=-\dfrac{7}{2}-\dfrac{5}{2}=-\dfrac{12}{2}=-6\)
\(6,x-\dfrac{1}{2}=\dfrac{9}{2}\Leftrightarrow x=5\)
\(7,x+\dfrac{5}{4}=\dfrac{-3}{4}\Leftrightarrow x=-2\)
\(8,x+\dfrac{2}{7}=\dfrac{5}{7}\Leftrightarrow x=\dfrac{3}{7}\)
\(9,x-\dfrac{4}{3}=\dfrac{1}{3}\Leftrightarrow x=\dfrac{5}{3}\)
\(10,x+\dfrac{5}{2}=\dfrac{-7}{2}\Leftrightarrow x=-6\)
a: Ta có: \(60-3\left(x-2\right)=51\)
\(\Leftrightarrow3\left(x-2\right)=9\)
\(\Leftrightarrow x-2=3\)
hay x=5
b: Ta có: \(4x-20=2^5:2^3\)
\(\Leftrightarrow4x=24\)
hay x=6
a) 310-(118-x)=217
118-x=310-217
118-x=93
x=118-93
x=25
b) 814-(x-305)=712
x-305=814-712
x-305=102
x =102+305
x = 407
c)5(x+35)=515
x+35 =515:5
x+35 =103
x =103-35
x =68
\(a,310-\left(118-x\right)=217\) \(c,5\left(x+35\right)=515\)
\(118-x=310-217\) \(x+35=515:5\)
\(118-x=93\) \(x+35=103\)
\(x=118-93\) \(x=103-35\)
\(x=25\) \(x=68\)
\(b,814-\left(x-305\right)=712\) \(\left[\left(6.x-39\right):3\right].28=5628\)
\(x-305=814-712\) \(\left(6.x-39\right):3=5628:28\)
\(x-305=102\) \(\left(6.x-39\right):3=201\)
\(x=102+305\) \(6.x-39=201x3\)
\(x=407\) \(6.x-39=603\)
\(6x=603+39\)
\(6x=642\)
\(x=107\)
\(e,2.x-138=2^3.2^2\)
\(2.x-138=32\)
\(2.x=32+138\)
\(2.x=170\)
\(x=170:2\)
\(x=85\)
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