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1. a. 9.(x-2)+1=2-2x
=> 9x-18+1=2-2x
=> 9x+2x = 2+18-1
=> 11x = 19
=> x=19/11
b. 9|x| = 45
=> |x| = 5
=> x=5 hoặc x=-5
c. 9:|x|=3
=> |x| = 3
=> x=3 hoặc x=-3
d. 5.(1-x)+2x=9-2x
=> 5-5x+2x=9-2x
=> -5x+2x+2x=9-5
=> -x=4
=> x=-4
b: =>15-x=-10
hay x=25
a: =>-2x+17=9
=>-2x=-8
hay x=4
d: \(\Leftrightarrow9x^2=81\)
hay \(x\in\left\{3;-3\right\}\)
e: \(\Leftrightarrow\left[{}\begin{matrix}2x-4=0\\3-x=0\end{matrix}\right.\Leftrightarrow x\in\left\{2;3\right\}\)
a,( x - 29 ) - ( 17 - 38 ) = -9
( x - 29 ) + 21 = - 9
x - 29 = - 9 - 21
x - 29 = - 30
x = -30 + 29
x = -1
c, ( 27 - x ) + ( 15 + x ) = - 24
27 - x + 15 + x = -24
- x + x = -24-27-15
Vô lí vì 0 ko bằng -66
Vậy \(x\in\varnothing\)
d, |2x - 7|- 9 =20
|2x-7|=11
* 2x-7=11 * 2x-7=-11
2x=11+7 2x=-11+7
2x=18 2x=-4
x=18:2 x=-4:2
x=9 x=-2
Vậy x=9 hoặc x=-2
a) \(x=\dfrac{25}{72}\)
b)\(x=-\dfrac{1}{4}\)
\(x=\dfrac{3}{2}\)
c)\(x=\dfrac{5}{4}\) hoặc
x \(=\dfrac{8}{5}\)
d và e chịu vì mk kg giỏi lắm về mũ
f)\(x=-2\)
G)\(x=-\dfrac{5}{12}\)
a: =>-2x=9-17=-8
hay x=4
b: =>15-x=-10
hay x=25
d: \(\Leftrightarrow9x^2=81\)
hay \(x\in\left\{3;-3\right\}\)
e: \(\Leftrightarrow\left[{}\begin{matrix}2x-4=0\\3-x=0\end{matrix}\right.\Leftrightarrow x\in\left\{2;3\right\}\)
\(x+\frac{1}{2}=\frac{x}{3}\)
\(\Rightarrow3x+\frac{3}{2}=x\)
\(\Rightarrow x-3x=\frac{3}{2}\)
\(\Rightarrow-2x=\frac{3}{2}\)
\(\Rightarrow x=\frac{3}{2}:-2\)
\(\Rightarrow x=\frac{3}{2}.-\frac{1}{2}\)
\(\Rightarrow x=-\frac{3}{4}\)
Vậy \(x=-\frac{3}{4}\)
\(x+\frac{1}{2}=\frac{x}{3}\)
\(x=\frac{x}{3}-\frac{1}{2}\)
\(\frac{6x}{6}=\frac{2x}{6}-\frac{3}{6}\)
\(\Rightarrow6x=2x-3\)
\(6x-2x=3\)
\(4x=3\)
\(x=\frac{3}{4}\)
\(\frac{1-2x}{9}=\frac{1}{1-2x}\)
\(\Rightarrow\left(1-2x\right).\left(1-2x\right)=1.9\)
\(\Rightarrow\left(1-2x\right)^2=\left(\pm3\right)^2\)
\(\Rightarrow\orbr{\begin{cases}1-2x=3\\1-2x=-3\end{cases}\Leftrightarrow\orbr{\begin{cases}2x=-2\\2x=4\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=-1\\x=2\end{cases}}}\)
\(\frac{4}{5}=\frac{12}{x}=\frac{y}{20}=\frac{8.\left(y-x\right)}{z}\)
\(\Rightarrow\frac{4}{5}=\frac{12}{x}\)
\(4x=60\)
\(x=15\)
\(\frac{4}{5}=\frac{y}{20}\)
\(y5=80\)
\(y=16\)
\(\frac{4}{5}=\frac{8\left(y-x\right)}{z}\Leftrightarrow\frac{4}{5}=\frac{8.\left(80-15\right)}{z}\Leftrightarrow\frac{4}{5}=\frac{520}{z}\)
\(\Leftrightarrow4z=2600\)
\(z=650\)
Vậy ... ( bạn tự kết luận nhé )
chúc bạn học tốt !!!
1, \(\frac{x+1}{2}=\frac{x}{3}\)
<=> 3(x+1)=2x
<=> 3x+3-2x=0
<=> x+3=0
<=> x=-3
2, \(\frac{1-2x}{9}=\frac{1}{1-2x}\left(x\ne\frac{1}{2}\right)\)
<=> (1-2x)2=9
<=> \(\orbr{\begin{cases}1-2x=3\\1-2x=-3\end{cases}\Leftrightarrow\orbr{\begin{cases}2x=-2\\2x=4\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=-1\\x=2\end{cases}}\left(tmđk\right)}\)
Vậy x={-1;2}
2*x|x+1|=x9=2*x+2=x+9=x=7 .Vậy x bằng 7