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a: x=3
b: \(2x-1=2\)
hay \(x=\dfrac{3}{2}\)
c: \(\Leftrightarrow\left[{}\begin{matrix}2x-3=3\\2x-3=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=0\end{matrix}\right.\)
a/
$(2x-3\frac{1}{2})+250\text{%}=6,2$
$(2x-\frac{7}{2})+2,5=6,2$
$2x-\frac{7}{2}=6,2-2,5=3,7$
$2x=3,7+\frac{7}{2}=7,2$
$x=7,2:2=3,6$
b/
$(25\text{%}-4\frac{1}{2}x)-2\frac{1}{2}.4^2=5,25$
$(0,25-\frac{9}{2}x)-40=5,25$
$0,25-\frac{9}{2}x=45,25$
$\frac{9}{2}x=0,25-45,25=-45$
$x=-45:\frac{9}{2}=-10$
1: =>\(5^{x-2}-9=2^4-\left(6^2-6^2\right)\)
=>\(5^{x-2}=16+9=25\)
=>x-2=2
=>x=4
2: \(\Leftrightarrow3^x+16=19^6:19^5-3=19-3=16\)
=>3^x=0
=>x=0
3: \(\Leftrightarrow2^x+2^x\cdot16=272\)
=>2^x*17=272
=>2^x=16
=>x=4
4: \(\Leftrightarrow2^{x-1}+3=24-\left(4^2-2^2+1\right)=24-\left(16-4+1\right)\)
=>\(2^{x-1}+3=24-16+4-1=8+4-1=12-1=11\)
=>2^x-1=8
=>x-1=3
=>x=4
a: \(=8\cdot252-252:9+1296:52\)
=2016-28+324/13
=26168/13
b: =513+184-679+46-46
=697-679
=18
TH1: x3+1 = 0 => x3 = 0-1 = -1 => x= -1:3 ko được => x ko có giá trị
TH2: x2+4 = 0=> x2 = 0-4 = -4 => x= -4:2 = -2
TH3: x-1 = 0 => x= 0+1 = 1
duyệt đi
`2^(x+2) = 2^7`
`x = 5`
`x^3 = 46 + 18`
`x^3 = 64`
`x = 4`
`3(2x+1)^3 = 375`
`(2x+1)^3 = 125`
`2x + 1 = 5`
`x = 2`
`2^x .4 = 8^2 . 2`
`2^x . 4 =64.2`
`2^x .4 = 128`
`2^x = 128:4`
`2^x = 32`
`2^x=2^5`
`=> x=5`
___________________________
`x^3 - 6^2 : 2 = 46`
`x^3 - 18=46`
`x^3=46+18`
`x^3 = 64`
`x^3 = 4^3`
`=>x=4`
____________________
`25^2 - 3.(2x+1)^3 = 250`
`625 - 3.(2x+1)^3 = 250`
` 3.(2x+1)^3 =625-250`
`3.(2x+1)^3 =375`
`(2x+1)^3=375 : 3`
`(2x+1)^3 = 125`
`(2x+1)^3=5^3`
`2x+1=5`
`2x=5-1`
`2x=4`
`=>x=2`