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Bài giải
\(\frac{2}{3}+\frac{3}{4}+\frac{4}{5}=\frac{40}{60}+\frac{45}{60}+\frac{48}{60}=\frac{133}{60}\)
\(\frac{8}{5}+\frac{7}{6}+\frac{10}{9}+\frac{1}{2}=\frac{144}{90}+\frac{105}{90}+\frac{100}{90}+\frac{45}{90}=\frac{394}{90}\)
\(\frac{15}{17}-\frac{11}{13}+\frac{3}{26}=\frac{390}{442}+\frac{374}{442}+\frac{51}{442}=\frac{815}{442}\)
\(\frac{9}{12}\text{ x }\frac{4}{3}\text{ : }\frac{8}{5}=\frac{9}{12}\text{ x }\frac{4}{3}\text{ x }\frac{5}{8}=\frac{9\text{ x }4\text{ x }5}{12\text{ x }3\text{ x }8}=\frac{5}{8}\)
\(\frac{4}{5}\text{ x }\frac{15}{8}\text{ : }\frac{5}{7}=\frac{4}{5}\text{ x }\frac{15}{8}\text{ x }\frac{7}{5}=\frac{4\text{ x }15\text{ x }7}{5\text{ x }8\text{ x }5}=\frac{21}{10}\)
\(\frac{2}{3}+\frac{3}{4}+\frac{4}{5}=\frac{40}{60}+\frac{45}{60}+\frac{48}{60}=\frac{133}{60}\)
\(\frac{8}{5}+\frac{7}{6}+\frac{10}{9}+\frac{1}{2}=\frac{144}{90}+\frac{105}{90}+\frac{100}{90}+\frac{45}{90}=\frac{197}{45}\)
\(\frac{15}{17}-\frac{11}{13}+\frac{1}{26}=\frac{390}{442}+\frac{374}{442}+\frac{51}{442}=\frac{815}{442}\)
\(\frac{9}{12}\times\frac{4}{3}:\frac{8}{5}=1:\frac{8}{5}=\frac{5}{8}\)
\(\frac{4}{5}\times\frac{15}{8}:\frac{5}{7}=\frac{3}{2}:\frac{5}{7}=\frac{21}{10}\)
\(\frac{33}{5}\times\frac{3}{8}-\frac{3}{8}:\frac{5}{3}-\frac{5}{4}\)
\(=\frac{33}{5}\times\frac{3}{8}-\frac{3}{8}\times\frac{3}{5}-\frac{5}{4}\)
\(=\frac{3}{8}\times\left(\frac{33}{5}-\frac{3}{5}\right)-\frac{5}{4}\)
\(=\frac{3}{8}\times2-\frac{5}{4}\)
\(=\frac{3}{4}-\frac{5}{4}\)
\(=-\frac{1}{2}\)
\(\frac{33}{5}\)x\(\frac{3}{8}\)- \(\frac{3}{8}\):\(\frac{5}{3}\)- \(\frac{5}{4}\)= (\(\frac{33}{5}\)x \(\frac{3}{8}\)) - ( \(\frac{3}{8}\): \(\frac{5}{3}\)) - \(\frac{5}{4}\)= \(\frac{99}{40}\)- \(\frac{9}{40}\)- \(\frac{5}{4}\)= \(\frac{90}{40}\)- \(\frac{5}{4}\)= \(\frac{9}{4}\)- \(\frac{5}{4}\)= \(\frac{4}{4}\)= 1
a: 5/7+5/4
=20/28+35/28=55/28
b: 3/2-4/6
=9/6-4/6=5/6
c: 5x3/4=15/4
d: 4/6:8=2/3x1/8=2/24=1/12