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\(\frac{\left(-27\right)^{10}.16^{25}}{-3.\left(-32\right)^{15}}=\frac{\left(-3\right)^{30}.\left(-2\right)^{100}}{\left(-3\right).\left(-2\right)^{75}}=\frac{\left(-3\right).\left(-3\right)^{29}.\left(-2\right)^{75}.\left(-2\right)^{25}}{\left(-3\right).\left(-2\right)^{75}}\)
= \(\left(-3\right)^{29}.\left(-2\right)^{25}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Đặt giá trị biểu thức là A, ta có:
\(A=\dfrac{\left(-27\right)^{10}.16^{25}}{6^{30}.\left(-32\right)^{15}}\)
\(A=\dfrac{\left(\left(-3\right)^3\right)^{10}.\left(2^4\right)^{25}}{2^{30}.3^{30}.\left(\left(-2\right)^5\right)^{15}}\)
\(A=\dfrac{\left(-3\right)^{30}.2^{100}}{2^{30}.3^{30}.\left(-2\right)^{75}}\)
\(A=\dfrac{3^{30}.2^{100}}{2^{30}.2^{75}.3^{30}}=\dfrac{1}{2^5}=\dfrac{1}{32}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(=\dfrac{3^{30}\cdot2^{100}}{2^{30}\cdot3^{30}\cdot2^{75}}=\dfrac{1}{2^5}=\dfrac{1}{32}\)
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\(3x+\frac{3}{6}=7x+\frac{3}{15}\)
\(\Rightarrow4x=\frac{3}{10}\Rightarrow x=\frac{3}{40}\)
Ta co:
2x+3/6 = 7x + 3/15
=> 3/6 = 5x + 3/15
=> x = (3/6 - 3/15):5 = 3/50
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25 + 62 + 15 + 38 + 28 + 27 + 6
= 25 + 15 + 62 + 28 + 15 + 38 + 27
= 40 + 90 + 53 + 27
= 130 + 80
= 210
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`((-27)^10 . 16^25)/(6^30 . (-32)^15)`
`= (3^30 . 2^100)/(2^30 . 3^30 . -2^75)`
`= (2^100)/(2^30 . -2^75)`
`= (2^70)/(-2^75)`
`= -2^145`
A = \(\dfrac{\left(-27\right)^{10}.16^{25}}{6^{30}.\left(-32\right)^{15}}\)
A = \(\dfrac{\left(3^3\right)^{10}.\left(2^4\right)^{25}}{\left(2.3\right)^{30}.\left(-32\right)^{15}}\)
A = \(\dfrac{3^{30}.2^{100}}{2^{30}.3^{30}.\left(-2^5\right)^{15}}\)
A = \(\dfrac{3^{20}.2^{100}}{3^{30}[2^{30}.\left(-2\right)^{75}].}\)
A = \(-\dfrac{2^{100}}{\left[2^{30}.\left(2\right)^{75}\right]}\)
A = -2100 - 30 - 75
A = - 270-75
A = -2-5
A = - \(\dfrac{1}{32}\)