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2/6+2/12+2/20+.............+2/210
xin hãy trả lời
Ta có:\(\frac{2}{6}+\frac{2}{12}+\frac{2}{20}+..+\frac{2}{210}=\frac{2}{2.3}+\frac{2}{3.4}+\frac{2}{4.5}+..+\frac{2}{14.15}\)
\(=2.\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+..+\frac{1}{14}-\frac{1}{15}\right)\)
\(=2.\left(\frac{1}{2}-\frac{1}{15}\right)\)
\(=1-\frac{2}{15}=\frac{15-2}{15}=\frac{13}{15}\)
????????????????????????????????????????????????????????????????????????????????????????????????????????
1/ tinh tong : 2/6 + 2/12 + 2/20 + ... +2/210
Tính A= 1/2 + 1/6 + 1/ 12 + 1/20 + 1/30 +...+1/182 + 210
A = \(\dfrac{1}{2}\) + \(\dfrac{1}{6}\) + \(\dfrac{1}{12}\) + \(\dfrac{1}{20}\) + \(\dfrac{1}{30}\)+...+\(\dfrac{1}{182}\)+ 210
A = \(\dfrac{1}{1\times2}\) + \(\dfrac{1}{2\times3}\)+\(\dfrac{1}{3\times4}\)+ \(\dfrac{1}{4\times5}\)+...+ \(\dfrac{1}{13\times14}\)+ 210
A = \(\dfrac{1}{1}\) - \(\dfrac{1}{2}\)+ \(\dfrac{1}{2}\) - \(\dfrac{1}{3}\)+ \(\dfrac{1}{3}\)- \(\dfrac{1}{4}\)+ \(\dfrac{1}{4}\) - \(\dfrac{1}{5}\)+...+\(\dfrac{1}{13}\) - \(\dfrac{1}{14}\) + 210
A = 1 - \(\dfrac{1}{14}\) + 210
A = 211 - \(\dfrac{1}{14}\)
A = \(\dfrac{2953}{14}\)
tìm b biết: 2+ 4+ 6+8+ 10 +12+......+b = 210
Dãy số cách đều: 2;4;6;8...; b
Có số số hạng là: \(\frac{\left(b-2\right)}{2}+1=\frac{b}{2}\)
Có tổng là: \(\frac{1}{2}\cdot\left(2+b\right)\cdot\frac{b}{2}=210\Leftrightarrow b\left(b+2\right)=840=28\cdot30=28\cdot\left(28+2\right)\)
Do đó, b = 28
Viết thêm 2 số hạng vào dãy số:
a) 10, 13, 18, 26, … k) 1, 3, 3, 9, 27, …b) 0, 1, 2, 4, 7, 12, … l) 1, 2, 3, 6, 12, 24,....c) 0, 1, 4, 9, 18, … m) 1, 4, 9, 16, 25, 36, …d) 5, 6, 8, 10, … o) 2, 12, 30, 56, 90, …e) 1, 6, 54, 648, … p) 1, 3, 9, 27, …g) 1, 5, 14, 33, 72, … q) 2, 6, 12, 20, 30, …h) 2, 20, 56, 110, 182,…. t) 6, 24, 60, 120, 210,..
a) 39 b) 20 c) 29 d) ...
Câu 20. Cho dãy số tự nhiên liên tiếp 2; 4; 6; 8; …. Hãy cho biết chữ số hạng thứ 210 là số nào?
2*x+1/2*x + 6*x+1/6*x +12*x+1/12*x +20*x+1/20*x= 5.tìm x
2/6+2/12+2/20+.........+2/90
S=2/6+2/12+2/20+...+2/90
S=2/2.3+2/3.4+...+2/9.10
S=2(1/2.3+...+1/9.10)
S=2(1/2-1/3+...+1/9-1/10)
S=2.2/5
S=4/5
\(\frac{2}{6}+\frac{2}{12}+\frac{2}{20}+...+\frac{2}{90}\)
\(=\frac{2}{2x3}+\frac{2}{3x4}+\frac{2}{4x5}+...+\frac{2}{9x10}\)
\(=\left(\frac{2}{2x3}+\frac{2}{3x4}+\frac{2}{4x5}+...+\frac{2}{9x10}\right):2x2\)
\(=\left(\frac{1}{2x3}+\frac{1}{3x4}+\frac{1}{4x5}+...+\frac{1}{9x10}\right)x2\)
\(=\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{9}-\frac{1}{10}\right)x2\)
\(=\left(\frac{1}{2}-\frac{1}{10}\right)x2\)
\(=\frac{4}{5}x2\)
\(=\frac{8}{5}\)
2*x+1/2*x+6*x+1/6*x+12*x+1/12*x+20*x+1/20*x=5.Tim x
xin hãy trả lời
2/6+2/12+2/20+.............+2/210
Ta có:\(\frac{2}{6}+\frac{2}{12}+\frac{2}{20}+..+\frac{2}{210}=\frac{2}{2.3}+\frac{2}{3.4}+\frac{2}{4.5}+..+\frac{2}{14.15}\)
\(=2.\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+..+\frac{1}{14}-\frac{1}{15}\right)\)
\(=2.\left(\frac{1}{2}-\frac{1}{15}\right)\)
\(=1-\frac{2}{15}=\frac{15-2}{15}=\frac{13}{15}\)
????????????????????????????????????????????????????????????????????????????????????????????????????????
1/ tinh tong : 2/6 + 2/12 + 2/20 + ... +2/210
Tính A= 1/2 + 1/6 + 1/ 12 + 1/20 + 1/30 +...+1/182 + 210
A = \(\dfrac{1}{2}\) + \(\dfrac{1}{6}\) + \(\dfrac{1}{12}\) + \(\dfrac{1}{20}\) + \(\dfrac{1}{30}\)+...+\(\dfrac{1}{182}\)+ 210
A = \(\dfrac{1}{1\times2}\) + \(\dfrac{1}{2\times3}\)+\(\dfrac{1}{3\times4}\)+ \(\dfrac{1}{4\times5}\)+...+ \(\dfrac{1}{13\times14}\)+ 210
A = \(\dfrac{1}{1}\) - \(\dfrac{1}{2}\)+ \(\dfrac{1}{2}\) - \(\dfrac{1}{3}\)+ \(\dfrac{1}{3}\)- \(\dfrac{1}{4}\)+ \(\dfrac{1}{4}\) - \(\dfrac{1}{5}\)+...+\(\dfrac{1}{13}\) - \(\dfrac{1}{14}\) + 210
A = 1 - \(\dfrac{1}{14}\) + 210
A = 211 - \(\dfrac{1}{14}\)
A = \(\dfrac{2953}{14}\)
tìm b biết: 2+ 4+ 6+8+ 10 +12+......+b = 210
Dãy số cách đều: 2;4;6;8...; b
Có số số hạng là: \(\frac{\left(b-2\right)}{2}+1=\frac{b}{2}\)
Có tổng là: \(\frac{1}{2}\cdot\left(2+b\right)\cdot\frac{b}{2}=210\Leftrightarrow b\left(b+2\right)=840=28\cdot30=28\cdot\left(28+2\right)\)
Do đó, b = 28
Viết thêm 2 số hạng vào dãy số:
a) 10, 13, 18, 26, … k) 1, 3, 3, 9, 27, …
b) 0, 1, 2, 4, 7, 12, … l) 1, 2, 3, 6, 12, 24,....
c) 0, 1, 4, 9, 18, … m) 1, 4, 9, 16, 25, 36, …
d) 5, 6, 8, 10, … o) 2, 12, 30, 56, 90, …
e) 1, 6, 54, 648, … p) 1, 3, 9, 27, …
g) 1, 5, 14, 33, 72, … q) 2, 6, 12, 20, 30, …
h) 2, 20, 56, 110, 182,…. t) 6, 24, 60, 120, 210,..
a) 39 b) 20 c) 29 d) ...
Câu 20. Cho dãy số tự nhiên liên tiếp 2; 4; 6; 8; …. Hãy cho biết chữ số hạng thứ 210 là số nào?
2*x+1/2*x + 6*x+1/6*x +12*x+1/12*x +20*x+1/20*x= 5.tìm x
2/6+2/12+2/20+.........+2/90
S=2/6+2/12+2/20+...+2/90
S=2/2.3+2/3.4+...+2/9.10
S=2(1/2.3+...+1/9.10)
S=2(1/2-1/3+...+1/9-1/10)
S=2.2/5
S=4/5
\(\frac{2}{6}+\frac{2}{12}+\frac{2}{20}+...+\frac{2}{90}\)
\(=\frac{2}{2x3}+\frac{2}{3x4}+\frac{2}{4x5}+...+\frac{2}{9x10}\)
\(=\left(\frac{2}{2x3}+\frac{2}{3x4}+\frac{2}{4x5}+...+\frac{2}{9x10}\right):2x2\)
\(=\left(\frac{1}{2x3}+\frac{1}{3x4}+\frac{1}{4x5}+...+\frac{1}{9x10}\right)x2\)
\(=\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{9}-\frac{1}{10}\right)x2\)
\(=\left(\frac{1}{2}-\frac{1}{10}\right)x2\)
\(=\frac{4}{5}x2\)
\(=\frac{8}{5}\)
2*x+1/2*x+6*x+1/6*x+12*x+1/12*x+20*x+1/20*x=5.Tim x
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