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\(a,2^x.4=128\)
\(\Leftrightarrow2^x=128:4\)
\(\Leftrightarrow2^x=32\)
\(\Leftrightarrow2^x=2^5\)
\(\Rightarrow x=5\)
\(b,2^x=4.128\)
\(\Leftrightarrow2^x=2^2.2^7\)
\(\Leftrightarrow2^x=2^9\)
\(\Rightarrow x=9\)
\(c,3^x=3^3.3^5\)
\(\Leftrightarrow3^x=3^8\)
\(\Rightarrow x=8\)
\(d,2^x.\left(2^2\right)^3=\left(2^3\right)^2\)
\(\Leftrightarrow2^x.2^6=2^6\)
\(\Leftrightarrow2^x=2^6:2^6\)
\(\Leftrightarrow2^x=1\)
\(\Rightarrow x=0\)
\(2^x\cdot2=128\)
\(\Rightarrow2^x=128:2\)
\(\Rightarrow2^x=64\)
\(\Rightarrow2^x=2^6\)
\(\Rightarrow x=6\)
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\(4^x:4^3=16\)
\(\Rightarrow4^{x-3}=16\)
\(\Rightarrow4^{x-3}=4^2\)
\(\Rightarrow x-3=2\)
\(\Rightarrow x=3+2=5\)
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\(2^x:3=48\)
\(\Rightarrow2^x=48:3\)
\(\Rightarrow2^x=16\)
\(\Rightarrow2^x=2^4\)
\(\Rightarrow x=4\)
==============
\(3^{x-5}=81\)
\(\Rightarrow3^{x-5}=3^4\)
\(\Rightarrow x-5=4\)
\(\Rightarrow x=4+5\)
\(\Rightarrow x=9\)
2ˣ⁻² = 128
2ˣ⁻² = 2⁷
x - 2 = 7
x = 7 + 2
x = 9
Các câu còn lại xem bài bạn Phong
a,2^x*16=128
2^x=8
2^x=2^3
suy ra x=3
b,3^x/9=27
3^x/3^2=3^3
3^x=3^5
suy ra x=5
c,(2*x+1)^3=27
(2*x+1)^3=3^3
suy ra 2*x+1=3
suy ra 2x=2
suy ra x=1
d,(x*2)^2=(x*2)^4
suy ra (x*2)^4-(x*2)^2=0
(x*2)^2*((x*2)^2-1)=0
suy ra (x*2)^2=0 hoac (x*2)^2-1=0
+(x*2)^2=0 +(x*2)^2-1=0
suy ra x*2=0 (x*2)^2=1
suy ra x=0 suy ra x*2=1 hoac -1
suy ra x=1/2 hoac -1/2
\(4< 2^x< 128\Rightarrow2^2< 2^x< 2^7\) \(\Rightarrow2< x< 7\)
\(^{2^x}.4=128\Rightarrow2^x=128:4\Rightarrow2^x=32=2^5\Rightarrow x=5\)
`@` `\text {Ans}`
`\downarorw`
`2^x \div 2 = 128?`
`=> 2^x = 128 * 2`
`=> 2^x = 256`
`=> 2^x = 2^8`
`=> x = 8`
Vậy, `x = 8`
______
`4^x \div 4^3 = 16`
`=> 4^x = 16 * 4^3`
`=> 4^x = 4^2 * 4^3`
`=> 4^x = 4^5`
`=> x = 5`
Vậy, ` x = 5`
________
`12^x \div 3 = 48 ?`
`=> 12^x = 48 * 3`
`=> 12^x = 144`
`=> 12^x = 12^2`
`=> x = 2`
Vậy, `x = 2`
________
`3^x - 5 = 81`
`3^x = 81 + 5`
`3^x = 86`
Bạn xem lại đề
`@` `\text {Kaizuu lv uuu}`
\(2^x.4=128\)
\(2^x.2^2=2^7\)
\(2^{x+2}=2^7\)
\(\Rightarrow x+2=7\)
x = 7 - 2
x = 5
$2^{4-x}=128$
$\Rightarrow 2^{4-x}=2^7$
$\Rightarrow 4-x=7$
$\Rightarrow x=4-7$
$\Rightarrow x=-3$
\(2^{4-x}=128\)
\(2^{4-x}=2^7\)
\(4-x=7\)
\(x=4-7\)
\(x=-3\)