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2/3 + 7/1 = 2/3 + 7 = 2/3 + 21/3 = 23/3
25/48 + 11/24 = 25/48 + 22/48 = 47/48
5/7 + 3/8 = 40/56 + 21/56 = 61/56
15/24 + 12/6 = 5/8 + 2 = 5/8 + 16/8 = 21/8
5/6 + 4/3 = 5/6 + 8/6 = 13/6
3/8 + 7/12 = 9/24 + 14/24 = 23/24
A\(\frac{7}{8}+\frac{7}{12}+\frac{9}{8}+\frac{5}{12}\)
\(=\left(\frac{7}{8}+\frac{9}{8}\right)+\left(\frac{7}{12}+\frac{5}{12}\right)\)
\(=1+2\)
\(=3\)
B\(\frac{2}{5}\times\frac{4}{7}-\frac{3}{7}\times\frac{2}{5}\)
\(=\left(\frac{4}{7}-\frac{3}{7}\right)\times\frac{2}{5}\)
\(=\frac{1}{7}\times\frac{2}{5}\)
\(=\frac{2}{35}\)
A\(\frac{7}{8}+\frac{7}{12}+\frac{9}{8}+\frac{5}{12}\)
\(=\left(\frac{7}{12}+\frac{5}{12}\right)+\left(\frac{7}{8}+\frac{9}{8}\right)\)
\(=1+2\)
\(=3\)
( 48 x 5 + 48 x 7 - 48 x 12 )
=48 x ( 5 + 7 - 12 )
=48 x 0
= 0
\(\Rightarrow\)( 48 x 5 + 48 x 7 - 48 x 12 ) : ( 1 + 3 + 5 + 7 +.....+ 91 ) = 0
Hk tốt
\(\left(48\text{ x }5+48\text{ x }7-48\text{ x }12\right)\text{ : }\left(1+3+5+7+...+91\right)\)
\(=\left(48\text{ x }5+48\text{ x }7-48\text{ x }12\right)\text{ : }A\)
\(=48\text{ x }\left(5+7-12\right)\text{ : }A\)
\(=48\text{ x }\left(12-12\right)\text{ : }A\)
\(=48\text{ x }0\text{ : }A\)
\(=0\text{ : }A\)
\(=0\)
`a,2/5 + 3/4`
`= 8/20 + 15/20`
`= 23/20`
`b,2/7 + 5/9`
`= 18/63 + 35/63`
`= 53/63`
`c, 4/7 + 3/4 + 2/7`
`= ( 4/7 + 2/7)+3/4`
`= 6/7 + 3/4`
`= 24/28 + 21/28`
`= 45/28`
`@ yl`
\(\dfrac{2}{5}+\dfrac{3}{4}=\dfrac{8}{20}+\dfrac{15}{20}=\dfrac{23}{20}\)
\(\dfrac{2}{7}+\dfrac{5}{9}=\dfrac{18}{63}+\dfrac{35}{63}=\dfrac{53}{63}\)
\(\dfrac{4}{7}+\dfrac{3}{4}+\dfrac{2}{7}= \left(\dfrac{4}{7}+\dfrac{2}{7}\right)+\dfrac{3}{4}=\dfrac{6}{7}+\dfrac{3}{4}=\dfrac{45}{28}\)
1-2+3-4+5-6+...+99-100+101
= (1+3+5+...+101) - (2+4+6+...+100)
tu 1 den 101 co : (101-1):2+1=51
1+..+101 = (1+101)x 51:2= 2601
tu 2 den 100 co : (100-2);2+1=50
2+...+100 = (100 +2) x 50:2=2550
=> A= 2601-2550=51
học tốt
TL
= \(\frac{5}{4}\)
nhaaaa
HT
2/3+7/12
=8/12+7/12
=15/12
=5/4
HT