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\(\frac{8^{15}+8^{16}}{16^{13}+32^{11}}=\frac{8^{15}(1+8)}{(2^4)^{13}+(2^5)^{11}}=\frac{(2^3)^{15}.9}{2^{52}+2^{55}}=\frac{2^{45}.9}{2^{52}.(2+2^3)}=\frac{2^{45}.9}{2^{52}.10}=\frac{9}{2^7.10}=\frac{9}{1280}\)
_Học tốt_
\(\frac{8^{15}+8^{16}}{16^{13}+32^{11}}=\frac{8^{15}.\left(1+8\right)}{\left(2^4\right)^{13}+\left(2^5\right)^{11}}\)
\(=\frac{8^{15}.9}{2^{52}+2^{55}}=\frac{8^{15}.9}{2^{52}.\left(1+2^3\right)}\)
\(=\frac{8^{15}.9}{2^{52}.9}=\frac{8^{15}}{2^{52}}=\frac{\left(2^3\right)^{15}}{2^{52}}\)
\(=\frac{2^{45}}{2^{52}}=\frac{1}{128}\)
a)
3210 = (25)10 = 250
1615 = (24)15 = 260
Vì 50 < nên 250 < 260
Vậy 3210 < 1615
b)
2711 = (33)11 = 333
818 = (34)8 = 332
Vì 33 > 32 nên 333 > 332
Vậy 2711 > 818
c)
536 = (53)12 = 12512
1124 = (112)12 = 12112
Vì 125 > 121 nên 12512 > 12112
Vậy 536 > 1124
d)
216 = 23.213 = 8.213
Vì 7 < 8 nên 7.213 < 8.213
Vậy
a) Ta có: 3210 = (25)10 = 250
1615 = (24)15 = 260
Vì 50 < 60 => 250 < 260 => 3210 < 1615
b) Ta có: 2711 = (33)11 = 333
818 = (34)8 = 332
Vì 33 > 32 => 333 > 332 => 2711 > 818
c) Ta có: 536 = (53)12 = 12512
1124 = (112)12 = 12112
Vì 125 > 121 => 12512 > 12112 => 536 > 1124
d) Ta có: 216 = 213.23 = 8.213
Vì 7 < 8 => 7.213 < 8.213 => 7.213 < 8.213
A=\(\frac{14^{16}.21^{32}.35^{48}}{10^{16}.15^{32}.7^{96}}\)= \(\frac{\left(2.7\right)^{16}.\left(3.7\right)^{32}.\left(5.7\right)^{48}}{\left(2.5\right)^{16}.\left(3.5\right)^{32}.7^{96}}\)= \(\frac{2^{16}.7^{16}.3^{32}.7^{32}.5^{48}.7^{48}}{2^{16}.5^{16}.3^{32}.5^{32}.7^{96}}\)= \(\frac{2^{16}.7^{96}.3^{32}.5^{48}}{2^{16}.5^{48}.3^{32}.7^{96}}\)=1
\(\frac{14^{16}.21^{32}.35^{48}}{10^{16}.15^{32}.7^{96}}=\frac{2^{16}.7^{16}.3^{32}.7^{32}.5^{48}.7^{48}}{2^{16}.5^{16}.3^{32}.5^{32}.7^{96}}\)
\(=\frac{2^{16}.\left(7^{16}.7^{32}.7^{48}\right).5^{48}.3^{32}}{2^{16}\left(5^{16}.5^{32}\right).3^{32}.7^{96}}=\frac{2^{16}.7^{96}.5^{48}.3^{32}}{2^{16}.5^{48}.3^{32}.7^{96}}\)=1
\(\frac{\left(-2\right)^{18}.8^{15}.16^4}{32^{16}}\)
\(=\frac{2^{18}.2^{45}.2^{16}}{2^{80}}\)
\(=\frac{2^{79}}{2^{80}}=\frac{1}{2}\)
(-2)^18.8^15.16^4/32^16
= 1/2
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