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2 . 14 . 98 + 7 . 4 . 32 - 28 . 30
= 28 . 98 + 28 . 32 - 28 . 30
= 28 . ( 98 + 32 - 30 )
= 28 . 100
= 2800
Bài 1:
1. 36.7 + 34.37 + 19.100
= 34.(32.7 + 37) + 19.100
= 81.100 + 19.100
= 100.(81 + 19)
= 100.100
= 10000
2) 2.14.98+7.4.32-28.30
= 28.98 + 28.32 - 28.30
= 28. (98 + 32 - 30)
= 28.100
= 2800
3) (56.35+56.18):53
= [56.(35 + 18)] : 53
= 56.53:53
= 56
4) (158.129-158.39):28
= [158. (129 - 39)] : 28
= 158.90:28
= 5,675
\(\frac{4}{4.6}+\frac{4}{6.8}+\frac{4}{8.10}+...+\frac{4}{28.30}\)
\(=2.\left(\frac{2}{4.6}+\frac{2}{6.8}+\frac{2}{8.10}+...+\frac{2}{28.10}\right)\)
\(=2.\left(\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{8}+\frac{1}{8}-\frac{1}{10}+...+\frac{1}{28}-\frac{1}{30}\right)\)
\(=2.\left(\frac{1}{4}-\frac{1}{30}\right)=2.\left(\frac{15}{60}-\frac{2}{60}\right)=2.\frac{13}{60}=\frac{26}{60}=\frac{13}{30}\)
\(A=\frac{1}{2.4}+\frac{1}{4.6}+\frac{1}{6.8}+...+\frac{1}{28.30}\)
\(A=\frac{2}{2}\left(\frac{1}{2.4}+\frac{1}{4.6}+\frac{1}{6.8}+...+\frac{1}{28.30}\right)\)
\(A=\frac{1}{2}\left(\frac{2}{2.4}+\frac{2}{4.6}+\frac{2}{6.8}+...+\frac{2}{28.30}\right)\)
\(A=\frac{1}{2}\left(\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+...+\frac{1}{28}-\frac{1}{30}\right)\)
\(A=\frac{1}{2}\left(\frac{1}{2}-\frac{1}{30}\right)\)
\(A=\frac{1}{2}.\frac{7}{15}\)
\(A=\frac{7}{30}\)
\(2.A=\frac{2}{2.4}+\frac{2}{4.6}+\frac{2}{6.8}+...+\frac{2}{28.30}\)
\(2.A=\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{8}+...+\frac{1}{28}-\frac{1}{30}\)
\(2.A=\frac{1}{2}-\frac{1}{30}\)
\(2.A=\frac{7}{15}\)
\(A=\frac{7}{15}:2=\frac{7}{30}\)
A= 1.3+2.4+3.5+4.6+...........+27.29+28.30
B= 20.22+21.23+...........+32.34+33.35
. là nhân nha các bn
Tương tự suy ra
1.2.3........30≡−60.−59.......−31=60.59...311.2.3........30≡−60.−59.......−31=60.59...31 (mod 61)
Suy ra 1.2.3....30−60.59...311.2.3....30−60.59...31 chia hết cho 61 Toán lớp 7 mới được làm cách này!Thôi xin 1 tick Please!!!!
đặt A=tổng trên
\(2A=\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{28}-\frac{1}{30}\)
\(2A=\frac{1}{5}-\frac{1}{30}\)
\(A=\frac{1}{6}:2\)
\(A=\frac{1}{12}\)
\(2\cdot14\cdot98+7\cdot4\cdot32-28\cdot30\)
\(=28\cdot98+28\cdot32-28\cdot30\)
\(=28\cdot\left(98+32-30\right)\)
\(=28\cdot100=2800\)
2.14.98 + 7.4.32 - 28.30
= 28.98 + 28.32 - 28.30
= 28. (98 + 32 - 30)
= 28 . 100
= 2800