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Do đó: A = 2 10 : − 2 5 = 2 10 : − 2 5 = − 2 10 − 5 = − 2 5 = − 32
Chọn đáp án B
2 3 x + 1 + 1 4 - 5 = 2 3 x - 1 5 - 3 x + 2 10 ⇔ 6 x + 3 4 - 5 = 6 x - 2 5 - 3 x + 2 10 ⇔ 5 6 x + 3 - 5 . 20 20 = 4 6 x - 2 - 2 3 x + 2 20
⇔ 5. (6x +3) – 5.20 = 4( 6x – 2) – 2( 3x + 2)
⇔ 30x + 15 – 100 = 24x -8 – 6x -4
⇔ 30x – 85= 18x – 12
⇔ 30x – 18x = - 12 + 85
⇔ 12 x = 73
⇔ x = 73 12
Vậy phương trình có nghiệm x = 73 12
\(x^2+y^2=\left(x+y\right)^2-2xy=\left(-8\right)^2-2\cdot15=34\)
Chọn D.
Mình tính đc kết quả 22 nhưng hơi khó hiểu mong mọi người giải dùm
a: \(A=2\cdot2^2\cdot...\cdot2^{10}\)
=>\(A=2^{1+2+...+10}\)
=>\(A=2^{55}\)
b: \(B=3\cdot3^3\cdot3^5\cdot...\cdot3^{99}\)
\(=3^{1+3+5+...+99}\)
\(=3^{50^2}=3^{2500}\)
đặt A=(1-1/3)........
Ta có A=\(\frac{2}{3}\cdot\frac{5}{6}\cdot\frac{9}{10}\cdot...\cdot\frac{209}{210}=\frac{4}{6}\cdot\frac{10}{12}\cdot\frac{18}{20}\cdot...\cdot\frac{418}{420}=\frac{1\cdot4}{2\cdot3}\cdot\frac{2\cdot5}{3\cdot4}\cdot\frac{3\cdot6}{4\cdot5}\cdot...\cdot\frac{19\cdot22}{20\cdot21}\)
=\(\frac{1\cdot4\cdot2\cdot5\cdot3\cdot6\cdot...\cdot19\cdot22}{2\cdot3\cdot3\cdot4\cdot4\cdot5\cdot...\cdot20\cdot21}=\frac{\left(1\cdot2\cdot3\cdot...\cdot19\right)\cdot\left(4\cdot5\cdot6\cdot...\cdot22\right)}{\left(2\cdot3\cdot4\cdot...\cdot20\right)\cdot\left(3\cdot4\cdot5\cdot...\cdot21\right)}\)
=\(\frac{1\cdot22}{20\cdot3}=\frac{11}{30}\)
Đặt \(A=\left(1-\frac{1}{3}\right).\left(1-\frac{1}{6}\right).\left(1-\frac{1}{10}\right).\left(1-\frac{1}{15}\right)...\left(1-\frac{1}{210}\right)\)
=>\(A=\frac{2}{3}.\frac{5}{6}.\frac{9}{10}.\frac{14}{15}...\frac{209}{210}\)
=>\(A=\frac{2.2}{3.2}.\frac{5.2}{6.2}.\frac{9.2}{10.2}.\frac{14.2}{15.2}...\frac{209.2}{210.2}\)
=>\(A=\frac{4}{6}.\frac{10}{12}.\frac{18}{20}.\frac{28}{30}...\frac{418}{420}\)
=>\(A=\frac{1.4}{2.3}.\frac{2.5}{3.4}.\frac{3.6}{4.5}.\frac{4.7}{5.6}...\frac{19.22}{20.21}\)
=>\(A=\frac{\left(1.4\right).\left(2.5\right).\left(3.6\right).\left(4.7\right)...\left(19.22\right)}{\left(2.3\right).\left(3.4\right).\left(4.5\right).\left(5.6\right)...\left(20.21\right)}\)
=>\(A=\frac{\left(1.2.3.4...19\right).\left(4.5.6.7...22\right)}{\left(2.3.4.5...20\right).\left(3.4.5.6...21\right)}\)
=>\(A=\frac{1.22}{20.3}\)
=>\(A=\frac{22}{60}=\frac{11}{30}\)
Vậy \(\left(1-\frac{1}{3}\right).\left(1-\frac{1}{6}\right).\left(1-\frac{1}{10}\right).\left(1-\frac{1}{15}\right)...\left(1-\frac{1}{210}\right)=\frac{11}{30}\)
20 x 10 + 210 = 200 + 210
= 410
410
duyệt đi