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a) \(=\left(127+73\right)^2=200^2=40000\)
b) \(=18^8-\left(18^8-1\right)=1\)
c) \(=\left(100+99\right)\left(100-99\right)+\left(98+97\right)\left(98-97\right)+...+\left(2+1\right)\left(2-1\right)\)
\(=100+99+98+97+...+2+1=5050\)
d) biến đổi thành \(20^2-19^2+18^2-17^2+..+2^2-1^2\)
rồi giải ra như trên
\(=\left(1-2\right)\left(1+2\right)+\left(3-4\right)\left(3+4\right)+...+\left(2003-2004\right)\left(2003+2004\right)+2005^2\\ =-\left(1+2\right)-\left(3+4\right)-...-\left(2003+2004\right)+2005^2\\ =-\left(1+2+3+...+2003+2004\right)+2005^2\\ =-\dfrac{\left(2004+1\right)\cdot2004}{2}+2005^2\\ =2011015\)
SSH:(20152-12):10+1=2015
(12-22)+(32-42)+(52-62)+...+(20132-20142)+20152
-10+(-10)+(-10)+...+(-10)+20152
-10x(2015-1):2+20152=12
=> C=12
1.
$=153^2+2.47.153+47^2=(153+47)^2=200^2=40000$
2.
$=1,24^2-2.1,24.0,24+0,24^2=(1,24-0,24)^2=1^2=1$
3. Không phù hợp để tính nhanh
4.
$=15^8-(15^8-1)=1$
5.
$=(1^2-2^2)+(3^2-4^2)+(5^2-6^2)+...+(2019^2-2020^2)$
$=(1-2)(1+2)+(3-4)(3+4)+(5-6)(5+6)+...+(2019-2020)(2019+2020)$
$=(-1)(1+2)+(-1)(3+4)+(-1)(5+6)+....+(-1)(2019+2020)$
$=(-1)(1+2+3+4+....+2019+2020)=(-1).2020(2020+1):2=-2041210$
6:
\(\left(2+1\right)\left(2^2+1\right)\left(2^4+1\right)....\left(2^{2020}+1\right)+1\\ =1.\left(2+1\right)\left(2^2+1\right)\left(2^4+1\right)....\left(2^{2020}+1\right)+1\\ =\left(2-1\right)\left(2+1\right)\left(2^2+1\right)\left(2^4+1\right)....\left(2^{2020}+1\right)+1\\ =\left(2^2-1\right)\left(2^2+1\right)\left(2^4+1\right)....\left(2^{2020}+1\right)+1\\ =\left(2^4-1\right)\left(2^4+1\right)....\left(2^{2020}+1\right)+1\\ =\left(2^8-1\right)....\left(2^{2020}+1\right)+1\\ =\left(2^{2020}-1\right)\left(2^{2020}+1\right)+1\\ =2^{4040}-1+1=2^{4040}\)
Xét
M – N = 77 2 + 75 2 + 73 2 + … + 3 2 + 1 2 – ( 76 2 + 74 2 + … + 2 2 ) = ( 77 2 – 76 2 ) + ( 75 2 – 74 2 ) + ( 73 2 – 71 2 ) + … + ( 3 2 – 2 2 ) + 1 2
= (77 + 76)(77 – 76) + (75 + 74)(75 – 74) + … + (3 + 2)(3 – 2) + 1
= (77 + 76).1 + (75 + 74).1 + … + (3 + 2).1 + 1
= 77 + 76 + 75 + 74 + 73 + … + 3 + 2 + 1
= 77 + 1 2 . 77 = 3003
Từ đó M - N - 3 3000 = 3003 - 3 3000 = 3000 3000 = 1
Đáp án cần chọn là: C
Ta có
x 2 + y 2 - 17 2 - 4 x y - 4 2 = x 2 + y 2 - 17 2 - 2 x y - 4 2 = x 2 + y 2 - 17 + 2 x y - 8 x 2 + y 2 - 17 - 2 x y + 8 = x 2 + y 2 + 2 x y - 25 x 2 + y 2 - 2 x y - 9 = x + y 2 - 5 2 x - y 2 - 3 2 = x + y + 5 x + y - 5 x - y + 3 x - y - 3 ⇒ m = - 5 ; n = - 3 ⇒ m . n = - 5 . - 3 = 15
Đáp án cần chọn là: D
\(\left(20^2+18^2+16^2+....+2^2\right)-\left(19^2+17^2+....+1^2\right)=\left(20^2-19^2\right)+\left(18^2-17^2\right)+......+\left(2^2-1^2\right)=\left(20+19\right)\left(20-19\right)+\left(18+17\right)\left(18-17\right)+....+\left(2+1\right)\left(2-1\right)=20+19+18+....+1=\frac{20\left(20+1\right)}{2}=10.21=210\)