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a,\(5^3.2-100:4+2^3.5\)
= 125 . 2 - 25 + 8 . 5
= 250 - 25 + 40
= 265
b, \(6^2:9+50.2-3^3.3\)
= 36 : 9 + 100 - 27 . 3
= 4 + 100 - 81
= 23
a: \(7^{x-5}+121=58\cdot2^3\)
=>\(7^{x-5}+121=58\cdot8\)
=>\(7^{x-5}=343\)
=>x-5=3
=>x=8
b: \(10^{x+25}+168=73\cdot2^4\)
=>\(10^{x+25}+168=73\cdot16\)
=>\(10^{x+25}=1000\)
=>x+25=3
=>x=-22
c: \(5x+59=21\cdot2^2=21\cdot4=84\)
=>5x=84-59=25
=>x=5
d: \(3+2^{x-1}=24-\left[4^2-\left(2^2-1\right)\right]\)
=>\(2^{x-1}+3=24-16+3\)
=>\(2^{x-1}=8\)
=>x-1=3
=>x=4
7ˣ⁻⁵ + 121 = 58.2³
7ˣ⁻⁵ = 58.8 - 121
7ˣ⁻⁵ = 464 - 121
7ˣ⁻⁵ = 343
7ˣ⁻⁵ = 7³
x - 5 = 3
x = 3 + 5
x = 8
-------
10ˣ⁻²⁵ + 168 = 73.2⁴
10ˣ⁻²⁵ = 73.16 - 168
10ˣ⁻²⁵ = 1000
10ˣ⁻²⁵ = 10³
x - 25 = 3
x = 3 + 25
x = 28
--------
5x + 59 = 21.2²
5x = 21.4 - 59
5x = 84 - 59
5x = 25
x = 25 : 5
x = 5
--------
3 + 2ˣ⁻¹ = 24 - [4² - (2² - 1)]
3 + 2ˣ⁻¹ = 24 - (16 - 3)
2ˣ⁻¹ = 24 - 13 - 3
2ˣ⁻¹ = 8
2ˣ⁻¹ = 2³
2ˣ⁻¹ = 3
x - 1 = 3
x = 3 + 1
x = 4
a, Ta có : \(\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{5.6}+...+\frac{1}{199.200}=1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+\frac{1}{5}-\frac{1}{6}+...+\frac{1}{199}-\frac{1}{200}\)
\(=\left(1+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{199}\right)-\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+...+\frac{1}{200}\right)\)
\(=\left(1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+...+\frac{1}{199}+\frac{1}{200}\right)-2\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+...+\frac{1}{200}\right)\)
\(=\left(1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{199}+\frac{1}{200}\right)-\left(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{100}\right)\)
\(=\frac{1}{101}+\frac{1}{102}+...+\frac{1}{200}\)
=> \(\frac{\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{5.6}+...+\frac{1}{199.200}}{\frac{1}{101}+\frac{1}{102}+...+\frac{1}{200}}=1\)
=> đpcm
Study well ! >_<
đề:(3+3^2+3^3)+......+(3^58+3^59+3^60)
xin lỗi bn mk ko biết làm
chúc bn giải đc bài toán này
tk mk nhé ! Thanks
A=(3+3^2+3^3)+....+(3^58+3^59+3^60)
A=3+3^2+......+3^60
3A=3(3+3^2+.....+3^60)
3A=3^2+3^3+3^4+......+3^61
3A-A=(3^2+3^3+....+3^61)-(3+3^2+....+3^60)
2A=3^61-3
A=(3^61-30)/2
+) 37 x ( 3 + 7 ) = 3^3 + 3^7
- 37 x ( 3 + 7 ) = 370
- 3^3 + 3^7 = 27 + 2187 = 2214
Từ đó, suy ra => SAI
+) 59 x ( 5 + 9 ) = 5^3 + 9^3
- 59 x ( 5 + 9 ) = 826
- 5^3 + 9^3 = 125 + 729 = 854
Từ đó, suy ra => SAI
23.27.24=23+7+4=214
23.24:25=23+4-5=27
(-3)+(-125)+(-25)
=-128+(-25)
=-153
25+(-38)=25-38=-13
126+159=285
120+(-135)+200
=120-135+200
=-15+200
=185
2^3x2^7=2^10x2^4=2^14=16384
2^3x2^4=2^7:2^5=2^2=4
1300-(150.2+(900+90):9)=1300-(150.2+990:9)=1300-(300+11)=1300-311=989
(-3) + (-125)+(-25)= -(3+125+25)= -153
25 + (-38)= -(38-25)= - 13
(126)+159=285
(120)+(-135)+200= -(135-120) + 200= (-15) + 200= +(200-15)=185
a) \(2^{4x}-3^{2x}=144-164:41\)
\(\Leftrightarrow16^x-9^x=144-4\)
\(\Leftrightarrow\) ......
bjan tự tính tiếp đc òi
[2x + 59]: 3 = 25
2x + 59 = 25 x 3
2x + 59 = 75
2x = 75 - 59
2x = 16
2x = 24
x = 4