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x + ( x + 1 ) + ( x + 2 ) + .... + ( x + 2344 ) + 2345 = 2345
( có 2346 số hạng )
x + ( x + 1 ) + ( x + 2 ) + ..... + ( x + 2344 ) = 2345 - 2345
x + ( x + 1 ) + ( x + 2 ) + ..... + ( x + 2344 ) = 0
( có 2345 số hạng )
[ ( x + 2344 ) + x ] . 2345 : 2 = 0
[ ( x + 2344 ) + x ] . 2345 = 0 . 2
( 2x + 2344 ) . 2345 = 0
2x + 2344 = 0 : 2345
2x + 2344 = 0
2x = 0 - 2344
2x = - 2344
x = - 2344 : 2 = - 1172
Vậy x = - 1172
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Câu 2:
\(a\cdot\left(b-c\right)-b\left(a+c\right)\)
\(=ab-ac-ab-bc\)
\(=-ac-bc=-c\left(a+b\right)\)
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2345-1000:[19-2(21-18)2]
= 2345 - 1000 : [19-2x32 ]
=2345-1000 : [19 - 2x9]
= 2345 - 1000 : [19 - 18]
= 2345 - 1000 : 1
= 2345 -1000
= 1345
\(2345-1000\div\text{ }\left[19-2\left(21-18\right)^2\right]\)
\(=2345-1000\div\left(19-2.3^2\right)\)
\(=2345-1000\div\left(19-2.9\right)\)
\(=2345-1000\div\left(19-18\right)\)
\(=2345-1000\div1\)
\(=2345-1000\)
\(=1345\)
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2345 - 100 : [19 - 2.(21 - 18)2] = 2345 - 100 : (19 - 2.32)
= 2345 - 100 : (19 - 2.9) = 2345 - 100 : (19 - 18)
= 2345 - 100 = 2245
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2345-1000:(19-2.(21-18)^2)
= 2345 - 1000 : (19 - 2.32)
= 2345 - 1000 : (19 - 2.9)
= 2345 - 1000 : 1
= 2345 - 1000
= 1345
HỌC TỐT
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\(2345-1000:\left[19-2\times\left(21-18\right)^2\right]\)
\(=2345-1000:\left[19-2\times3^2\right]\)
\(=2345-1000:\left[19-18\right]\)
\(=2345-1000\)
\(=1345\)
2345-1000:[19-2(21-18)2]
= 2345-1000:(19-2.32)
= 2345-1000:(19-2.9)
= 2345-1000:(19-18)
= 2345-1000:1
= 2345 - 1000
= 1345
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\(-2+\left(-2\right)=-4\)
\(-2345+\left(-6753\right)=-9098\)