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\(\frac{18}{5}+1=\frac{23}{5}=\frac{23\cdot7}{5\cdot7}=\frac{161}{35}\)
\(\frac{30}{7}+1=\frac{37}{7}=\frac{37\cdot5}{7\cdot5}=\frac{185}{35}\)
=>161/35<x<185/35
=>x=162/35 ;163/35 ;..............184/35
18/5 + 1=23/5
1+30/7=37/7
Quy đòng tử 23/5 và 37/7 được 851/185 và 851/161
Vậy x = 851/184;851/183;.....;851/162
a) 4/7 + x = 5/8
x=5/8 - 4/7
x=3/56
b) x/30 = 2/5
x/30=12/30
=>x=12
a. x + \(\dfrac{3}{7}\)= \(\dfrac{2}{5}:\dfrac{18}{25}=>x+\dfrac{3}{7}=\dfrac{2}{5}\)x\(\dfrac{35}{18}=>x+\dfrac{3}{7}=\dfrac{7}{9}\)
=> x = \(\dfrac{7}{9}-\dfrac{3}{7}=\dfrac{49}{63}-\dfrac{27}{63}=\dfrac{22}{63}\)
b. \(x\) x \(\dfrac{5}{9}\)= \(\dfrac{4}{5}-\dfrac{1}{3}\)
=> \(x\) x \(\dfrac{5}{9}\)= \(\dfrac{12}{15}-\dfrac{5}{15}=>x\) x \(\dfrac{5}{9}\)= \(\dfrac{7}{15}\)
=> x = \(\dfrac{7}{15}:\dfrac{5}{9}\)
=> x = \(\dfrac{21}{25}\)
\(a.x+\dfrac{3}{7}=\dfrac{2}{5}:\dfrac{18}{35}\\x+\dfrac{3}{7}=\dfrac{2}{5}\times\dfrac{35}{18} \\ x+\dfrac{3}{7}=\dfrac{7}{9}\\ x=\dfrac{7}{9}-\dfrac{3}{7}\\ x=\dfrac{22}{63}\)
\(b.x\times\dfrac{5}{9}=\dfrac{4}{5}-\dfrac{1}{3}\\x\times\dfrac{5}{9}=\dfrac{7}{15}\\ x=\dfrac{7}{15}:\dfrac{5}{9}\\ x= \dfrac{21}{25}\)
Câu 1. 3/2:5/4=? Nhớ rút gọn. Câu 2. Tìm x biết X x 18/5 = 7/10+3/5 nhớ rút gọn thank you các bạn🙏🏻😇
\(\frac{3}{2}:\frac{5}{4}=\frac{3}{2}\times\frac{4}{5}=\frac{12}{20}=\frac{3}{5}\)
X x 18/5 = 7/10 + 3/5
X x 18/5 = 13/10
X = 13/10 : 18/5
X = 13/36
k cho mik với
18/5 + 1 = 18/5 + 5/5 = 23/5 = 161/7
1 + 30/7 = 7/7 + 30/7 = 37/7 = 185/7
vậy ta có: \(\frac{161}{7}\)< x < \(\frac{185}{7}\)
x = \(\frac{162}{7};\frac{163}{7};....;\frac{184}{7}\)
18/5 + 1 = 18/5 + 5/5 = 23/5 = 161/7
1 + 30/7 = 7/7 + 30/7 = 37/7 = 185/7
vậy ta có: $\frac{161}{7}$1617 < x < $\frac{185}{7}$1857
x = $\frac{162}{7};\frac{163}{7};....;\frac{184}{7}$1627 ;1637 ;....;1847