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18/5 + 1 = 18/5 + 5/5 = 23/5 = 161/7
1 + 30/7 = 7/7 + 30/7 = 37/7 = 185/7
vậy ta có: \(\frac{161}{7}\)< x < \(\frac{185}{7}\)
x = \(\frac{162}{7};\frac{163}{7};....;\frac{184}{7}\)
18/5 + 1 = 18/5 + 5/5 = 23/5 = 161/7
1 + 30/7 = 7/7 + 30/7 = 37/7 = 185/7
vậy ta có: $\frac{161}{7}$1617 < x < $\frac{185}{7}$1857
x = $\frac{162}{7};\frac{163}{7};....;\frac{184}{7}$1627 ;1637 ;....;1847
a: 3/7=18/42
5/6=35/42
b: 5/17=15/51
9/51=9/51
c: 3/8=9/24
5/6=20/24
g: 7/30=28/120
13/60=26/120
9/40=27/120
a: 5/6=25/30
9/30=9/30
b: 7/8=49/56
5/7=40/56
c: 2/9=4/18
5/18=5/18
d: 3/10=6/20
1/4=5/20
5/6=25/30
9/30=9/30
7/8=49/56
5/7=40/56
2/9=4/18
5/18=5/18
3/10=6/20
1/4=5/20
1.\(\dfrac{11}{18};\dfrac{7}{9};\dfrac{14}{15}\)
2.\(\dfrac{4}{9}+\dfrac{3}{7}=\dfrac{28}{63}+\dfrac{27}{63}=\dfrac{55}{63}\)
\(\dfrac{5}{6}-\dfrac{3}{8}=\dfrac{20}{24}-\dfrac{9}{24}=\dfrac{11}{24}\)
\(\dfrac{18}{25}\cdot\dfrac{15}{6}=\dfrac{18\cdot15}{25\cdot6}=\dfrac{270}{150}=\dfrac{9}{5}\)
\(\dfrac{30}{49}:\dfrac{6}{7}=\dfrac{30}{49}\cdot\dfrac{7}{6}=\dfrac{30\cdot7}{49\cdot6}=\dfrac{210}{294}=\dfrac{5}{7}\)
2:
a: =28/63+27/63=55/63
b: =20/24-9/24=11/24
c: =270/150=9/5
d: \(=\dfrac{30}{49}\cdot\dfrac{7}{6}=\dfrac{1}{7}\cdot5=\dfrac{5}{7}\)
\(\frac{18}{5}+1=\frac{23}{5}=\frac{23\cdot7}{5\cdot7}=\frac{161}{35}\)
\(\frac{30}{7}+1=\frac{37}{7}=\frac{37\cdot5}{7\cdot5}=\frac{185}{35}\)
=>161/35<x<185/35
=>x=162/35 ;163/35 ;..............184/35
18/5 + 1=23/5
1+30/7=37/7
Quy đòng tử 23/5 và 37/7 được 851/185 và 851/161
Vậy x = 851/184;851/183;.....;851/162