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\(\frac{2^7.6^{15}}{16^5.27^6}=\frac{2^7.\left(2.3\right)^{15}}{\left(2^4\right)^5.\left(3^3\right)^6}=\frac{2^7.2^{15}.3^{15}}{2^{20}.3^{18}}=\frac{2^{22}.3^{15}}{2^{20}.3^{18}}=\frac{2^2.1}{1.3^3}=\frac{4}{27}\)

\(\frac{2.2^{12}.3^6+2^2.2^9.3^9}{2^7.2^7.3^7.2^4.5.3^8}\)
\(=\frac{2^{13}.3^6+2^{11}.3^{^9}}{2^{18}.3^{15}.5}\)
\(=\frac{2^{11}.3^6\left(2^2+3^3\right)}{2^{11}.3^6.2^6.3^4.5}\)
\(=\frac{35}{2^6.3^4.5}\)


5 \(\frac{27}{5}\)+ \(\frac{27}{23}\)+ 0,5 \(-\)\(\frac{5}{27}\)+ \(\frac{16}{23}\)
\(\Rightarrow\) \(\frac{52}{5}\)+\(\frac{27}{23}+\frac{1}{2}-\frac{5}{27}+\frac{16}{23}\)
\(\approx\)12

\(4\dfrac{25}{16}+25\left(\dfrac{9}{16}:\dfrac{125}{64}:\dfrac{-27}{8}\right)\)
\(=\dfrac{89}{16}+25\left(\dfrac{36}{125}:\dfrac{-27}{8}\right)\)
\(=\dfrac{89}{16}+25.\dfrac{-32}{375}\)
\(=\dfrac{89}{16}+\dfrac{-32}{15}=\dfrac{823}{240}\)
Chúc bạn học tốt!
\(4\dfrac{25}{16}+25\left(\dfrac{9}{16}:\dfrac{125}{64}:-\dfrac{27}{8}\right)\)
= \(\dfrac{89}{16}+25\left(\dfrac{9}{16}.\dfrac{64}{125}:-\dfrac{27}{8}\right)\)
= \(\dfrac{89}{16}+25\left(\dfrac{36}{125}:-\dfrac{27}{8}\right)\)
= \(\dfrac{89}{16}+25\left(\dfrac{36}{125}.-\dfrac{8}{27}\right)\)
= \(\dfrac{89}{16}+25.-\dfrac{32}{375}\)
\(=\dfrac{89}{16}+-\dfrac{32}{15}\)
= \(\dfrac{823}{240}\)

\(5\frac{5}{27}+\frac{7}{25}+0,5+-\frac{5}{27}+\frac{16}{23}\)
\(=\frac{140}{27}+\frac{7}{25}+\frac{1}{2}+-\frac{5}{27}+\frac{16}{23}\)
\(=\frac{7447}{1150}\)
Kết quả lớn quá :v

\(B=\dfrac{2\cdot2^{12}\cdot3^6+2^2\cdot2^9\cdot3^9}{2^7\cdot2^7\cdot3^7+2^7\cdot2^3\cdot5\cdot3^8}\)
\(=\dfrac{2^{13}\cdot3^6+2^{11}\cdot3^9}{2^{14}\cdot3^7+2^{10}\cdot5\cdot3^8}\)
\(=\dfrac{2^{11}\cdot3^6\left(2^2+3^3\right)}{2^{10}\cdot3^7\left(2^4+5\cdot3\right)}=\dfrac{2}{3}\cdot\dfrac{31}{31}=\dfrac{2}{3}\)

\(\frac{2.8^4.27^2+4.6^9}{2^7.6^7+2^7.40.9^4}=\frac{2.2^{12}.3^6+2^2.2^9.3^9}{2^7.2^7.3^7+2^7.2^3.5.3^8}=\frac{2^{13}.3^6+2^{11}.3^9}{2^{14}.3^7+2^{10}.3^8.5}\)
=\(\frac{2^{11}.3^6\left(2^2+3^3\right)}{2^{10}.3^4\left(2^4+3.5\right)}=\frac{2.3^2.31}{31}=2.3^2=18\)
mjk sửa nè
\(\frac{2.8^4.27^2+4.6^9}{2^7.6^7+2^7.40.9^4}=\frac{2.2^{12}.3^6+2^2.2^9.3^9}{2^7.2^7.3^7+2^7.2^3.5.3^8}=\frac{2^{13}.3^6+2^{11}.3^9}{2^{14}.3^7+2^{10}.3^8.5}\)
=\(\frac{2^{11}.3^6\left(2^2+3^3\right)}{2^{10}.3^7\left(2^4+3.5\right)}=\frac{2.31}{3.31}=\frac{2}{3}\)
Ta có: \(16+\left(27-7\cdot6\right)-99\cdot7-27\cdot99\)
\(=16+27\left(1-99\right)-7\left(6+99\right)\)
\(=16+27\cdot\left(-98\right)-7\cdot105=-3365\)
\(16 + \left(\right. 27 - 7 \cdot 6 \left.\right) - 99 \cdot 7 - 27 \cdot 99\)
\(= 16 + 27 \left(\right. 1 - 99 \left.\right) - 7 \left(\right. 6 + 99 \left.\right)\)
\(= 16 + 27 \cdot \left(\right. - 98 \left.\right) - 7 \cdot 105 = - 3365\)
Chúc bạn ngày mới vui vẻ