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\(2x+\dfrac{7}{99}.\dfrac{8}{15}=\dfrac{106}{99}.\dfrac{8}{15}\)
=> \(2x+\dfrac{8}{15}.\dfrac{7}{99}-\dfrac{8}{15}.\dfrac{106}{99}=0\)
=> \(2x+\dfrac{8}{15}\left(\dfrac{7}{99}-\dfrac{106}{99}\right)=0\)
=> \(2x+\dfrac{8}{15}.\left(-1\right)=0\)
=> \(2x-\dfrac{8}{15}=0\)
=> \(2x=\dfrac{8}{15}\)
=> \(x=\dfrac{8}{15}:2=\dfrac{4}{15}\)
=1/11-1/13+1/13-1/15+1/15-..................+1/99-1/100
=1/11 -1/100
=89/1100
( 1+2+3+.... +99) x (13x15 -12 x 15- 15)
= ( 1+2+3+.... +99) x 0
=0
Số nhà đầu tiên là:
[900-2]/2-15=434
Số nhà đầu tiên là:
900-434=466
Tính luôn :
1/11 - 1/13 + 1/13 - 1/15 + 1/15 - 1/17 + ... + 1/97 - 1/99 + 1/99 - 1/101
= 1/11 - 1/101
= 90/1111
Ta có 2/11.13+2/13.15+ ...+2/97.99+2/99.101=1/11-1/13+1/13-1/15+......+1/99-1/100=1/11-1/100=89/1100 Nhớ k cho mình nha.
a)\(\frac{13}{15}+\frac{13}{35}+\frac{13}{63}+\frac{13}{99}\)
\(=\frac{13}{3.5}+\frac{13}{5.7}+\frac{13}{7.9}+\frac{13}{9.11}\)
\(=\frac{13}{2}\left(\frac{1}{3}-\frac{1}{5}+.....+\frac{1}{9}-\frac{1}{11}\right)\)
\(=\frac{13}{2}\left(\frac{1}{3}-\frac{1}{11}\right)\)
\(=\frac{13}{2}\cdot\frac{8}{33}\)
\(=\frac{52}{33}\)
a) Đặt A= 13/15 + 13/35 + 13/63 + 13/99
A = 13/2 ( 2/15 + 2/35 + 2/63 + 2/99)
A= 13/2 ( 2/ 3.5 + 2/5.7 + 2/7.9 + 2/9.11)
A= 13/2 ( 1/3 - 1/5 + 1/5 - 1/7 + 1/7 - 1/9 + 1/9 - 1/11)
A= 13/2 ( 1/3 - 1/11)
A= 13/2 . 8/33
A= 52/33
1/6 + 2/15 + 4/15 + 2/99 + 9/220 + 10/600
=( 1/6 + 1/60) + (2/15 + 4/15) + 2/99 + 9/220
=11/60 + 2/5 + 11/180
=7/12 + 11/180
=29/45
\(=\left(\frac{1}{6}+\frac{1}{60}\right)+\left(\frac{2}{15}+\frac{4}{15}\right)+\frac{2}{99}+\frac{9}{220}\)
\(=\frac{11}{60}+\frac{2}{5}+\frac{11}{180}=?\)
\(=\frac{7}{12}+\frac{11}{180}=?\)
\(=\frac{29}{45}.\)
15x99+15+15x300=15000
15 x 99 + 15 + 15 x 900
= 15 x ( 99 + 900 ) + 15
= 15 x ( 999 + 1 )
= 15 x 1000
= 15000.