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M = \(\dfrac{5}{2.4}\) + \(\dfrac{5}{4.6}\)+ \(\dfrac{5}{6.8}\)+ ...+ \(\dfrac{5}{96.98}\)+ \(\dfrac{5}{98.100}\)
M = \(\dfrac{5}{2}\).( \(\dfrac{2}{2.4}\) + \(\dfrac{2}{4.6}\)+ \(\dfrac{2}{6.8}\)+...+ \(\dfrac{2}{96.98}\)+ \(\dfrac{2}{98.100}\))
M = \(\dfrac{5}{2}\).( \(\dfrac{1}{2}-\dfrac{1}{4}\)+ \(\dfrac{1}{4}-\dfrac{1}{6}\)+ \(\dfrac{1}{6}\) - \(\dfrac{1}{8}\)+...+ \(\dfrac{1}{96}\)-\(\dfrac{1}{98}\)+ \(\dfrac{1}{98}\)-\(\dfrac{1}{100}\))
M = \(\dfrac{5}{2}\).(\(\dfrac{1}{2}\) - \(\dfrac{1}{100}\))
M = \(\dfrac{49}{40}\)
\(x\) \(\times\) M - 1 = \(\dfrac{20}{29}\)
\(x\) \(\times\) \(\dfrac{49}{40}\) = \(\dfrac{20}{29}\) + 1
\(x\) \(\times\) \(\dfrac{49}{40}\) = \(\dfrac{49}{29}\)
\(x\) = \(\dfrac{49}{29}\) : \(\dfrac{49}{40}\)
\(x\) = \(\dfrac{40}{29}\)
a) 29 – [16 + 3.(51 – 49)]
b) 5.22 + 98:72
c) 311 : 39 – 147 : 72
d) 295 – (31 – 22.5)2
718 : 716 +22.33
A. 176+483+24+117
=176+24+483+117
=200+600
=800
B. Chịu
C. 25*50*4*20
=(25*4)*(50*20)
=100*1000
=100000
D. 24*19+29*24+18*24+24*33+24
=24 * (19+29+18+33)+24
=24*99+24
=2376+24
=2400
K mk nhé
a) 176+483+24+117=(176+24)+(483+117)=200+600=800
b) 32+33+34+...+78+79+80=(32+80)+(33+79)+...+(55+57)+56=112+112+...+112+56(có 24 số112)=112.24+56=2688+56=2744
c)25.50.4.20=(25.4).(50.20)=100.1000=100000
d)24.19+29.24+18.24+24.33+24=24.(19+29+18+33+1)=24.100=2400
Đáp án cần chọn là: D
Thay x=1589 ta được:
A=389–1589=389+(−1589)=−1200
a) \(0,5\)Và \(\frac{51}{100}\)
\(0,5=\frac{5}{10}=\frac{50}{100}\)
\(\frac{50}{100}< \frac{51}{100}\)
\(\Rightarrow0,5< \frac{51}{100}\)
b) ko rõ đề
c) \(\frac{15}{37}\)Và \(\frac{10}{29}\)
\(\Leftrightarrow\frac{435}{1073}>\frac{370}{1073}\)
\(\Rightarrow\frac{15}{37}>\frac{10}{29}\)
d) \(\frac{295}{118}\)Và \(\frac{280}{133}\)
\(\frac{39235}{15694}>\frac{33040}{15694}\)
\(\Rightarrow\frac{295}{118}>\frac{280}{133}\)
\(a)\) \(5^{13}:5^{10}-25.2^2=5^3-25.4=125-100=25\)
\(b)\) \(20:2^2+5^9:5^8=20:4+5^1=5+5=10\)
\(c)\) \(100:5^2+7.3^2=100:25+7.9=4+36=40\)
\(d)\) \(84:4+3^9:3^7+5^0=84:4+3^2+1=21+9+1=31\)
\(e)\)
\(29-\left[16+3.\left(51-49\right)\right]=29-\left[16+3.2\right]=29-\left[16+6\right]=29-22=7\)
\(f)\) \(5.2^2+98:7^2=5.4+98:49=20+2=22\)
\(g)\) \(3^{11}:3^9-147:7^2=3^2-147:49=9-3=6\)
\(295-\left(31-2^2.5\right)^2=295-\left(31-4.5\right)^2=295-\left(31-20\right)^2=295-11^2=295-121=174\)
\(7^{18}:7^{16}+2^2.3^2=7^2+4.9=49+36=85\)
a: \(5^{13}:5^{10}-25\cdot2^2\)
\(=5^3-25\cdot4\)
=125-100
=25
b: \(20:2^2+5^9:5^8\)
\(=20:4+5\)
=5+5
=10
n2 + n + 1589 không thể là số chính phương với mọi n được.
1589-{[224 : 4 . 6 ] + 29}
1589-{336 + 29 }
1589 - 365
1224
= 1589 - {[188:4.6]+29}
= 1589 - {[47.6]+29}
= 1589 - {282 + 29}
= 1589 - 311
= 1278