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`@` `\text {Ans}`
`\downarrow`
`b)`
\([(4x+28).3+55] \div 5=35\)
`=> (4x + 28) * 3 + 55 = 35 * 5`
`=> (4x + 28)*3 + 55 = 175`
`=> (4x + 28)*3 = 175 - 55`
`=> (4x + 28)*3 =120`
`=> 4x + 28 = 120 \div 3`
`=> 4x + 28 = 40`
`=> 4x = 40 - 28`
`=> 4x = 12`
`=> x = 12 \div 4`
`=>x = 3`
Vậy, `x = 3.`
=>[12x+84+55]=175
=>12x=175-84-55=120-84=36
=>x=36/12=3
[( 14 + 28 ) . 3 + 55 ] : 5 = 35
[ 42 . 3 + 55 ] : 5 = 35
= [ 126 + 55 ] : 5 = 35
= 181 : 5 = 35
= 36,2
[(4 : x + 28).3+55]:5=35
(4:x+28).3+55=35.5=175
(4:x+28).3=175-55=120
4:x+28=120:3=40
4:x=40-28=16
x=4:16
=>x=0,25
[(4x + 28).3 + 55] : 5 = 35
=> (4x + 28).3 + 55 = 175
=> (4x + 28).3 = 120
=> 4x + 28 = 40
=> 4x = 12
=> x = 3
vậy_
128 - 3 ( x + 4 ) = 23
3 ( x + 4 ) = 128 - 23
3 ( x + 4 ) = 105
x + 4 = 105 : 5
x + 4 = 35
x = 35 - 4
x = 31
128 - 3 ( x + 4 ) = 23
3 ( x + 4 ) = 128 - 23
3 ( x + 4 ) = 105
x + 4 = 105 : 5
x + 4 = 35
x = 35 - 4
x = 31
k mik nha
[(4x+28).3+55]:5=35
[(4x+28).3+55]=35.5
[(4x+28).3+55]=175
(4x+28).3=175-55
(4x+28).3=120
4x+28=120:3
4x+28=40
4x=40-28
4x=12
x=12:4
x=3
k cho mik nhoa bn nha!
a) \(128-3\left(x+4\right)=23\)
\(\Rightarrow3\left(x+4\right)=128-23\)
\(\Rightarrow3\left(x+4\right)=105\)
\(\Rightarrow x+4=35\)
\(\Rightarrow x=35-4\)
\(\Rightarrow x=31\)
b) \(\left[\left(4x+28\right)\cdot3+55\right]:5=35\)
\(\Rightarrow\left(4x+28\right)\cdot3+55=35\cdot5\)
\(\Rightarrow\left(4x+28\right)\cdot3+55=175\)
\(\Rightarrow\left(4x+28\right)\cdot3=120\)
\(\Rightarrow4x+28=40\)
\(\Rightarrow4x=12\)
\(\Rightarrow x=3\)
a, \(128-3\left(x+4\right)=23\)
\(=>3\left(x+4\right)=128-23\)
\(=>3\left(x+4\right)=105\)
\(=>x+4=105:3\)
\(=>x+4=35\)
\(=>x=35-4\)
\(=>x=31\)
b, \(\left[\left(4x+28\right).3+55\right]:5=35\)
\(=>\left(4x+28\right).3+55=35.5\)
\(=>\left(4x+28\right).3+55=175\)
\(=>\left(4x+28\right).3=175-55\)
\(=>\left(4x+28\right).3=120\)
\(=>4x+28=120:3\)
\(=>4x+28=40\)
\(=>4x=40-28\)
\(=>4x=12\)
\(=>x=12:4\)
\(=>x=3\)
\(#WendyDang\)
\(\left[\left(4x+28\right).3+55\right]:5=35\)
\(\Rightarrow\left(4x+28\right).3+55=35.5\)
\(\Rightarrow\left(4x+28\right).3+55=175\)
\(\Rightarrow\left(4x+28\right).3=175-55\)
\(\Rightarrow\left(4x+28\right).3=120\)
\(\Rightarrow4x+28=120:3\)
\(\Rightarrow4x+28=40\)
\(\Rightarrow4x=40-28\)
\(\Rightarrow4x=12\)
\(\Rightarrow x=12:4\)
\(\Rightarrow x=3\)
[ ( 4x + 28 ). 3 + 55 ] ÷ 5 = 35
( 4x + 28 ). 3 + 55 = 35.5
( 4x + 28 ). 3 + 55 = 175
( 4x + 28 ). 3 = 175 - 55
( 4x + 28 ). 3 = 120
4x + 28 = 120 : 3
4x + 28 = 40
4x = 40 - 28
4x = 12
x = 12 : 4
x = 3
[(14x+28)*3+55}:5=35
(14x+28)*3+55=35*5
(14x+28)*3+55=175
(14x+28)*3=175-55
(14x+28)*3=120
14x+28=120:3
14x+28=40
14x=40-28
14x=12
x=12:14
x=6/7