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Trả lời
a)964.3+496.4-496.6
=964.3+[496.(4-6)]
=964.3+(-992)
=2892+(-992)
=1900
b)2019.(2020+1)-2019.2020
=2019.2020.2019-2019.2020
=2019
c)436+324.(234-1)-234.324+324
=436+324.234-324-234.324+324
=436
d)472.(36-1)+35.8
=472.35+35.8
=35.(472+8)
=35.480
=16 800
Ko chắc nha, sai thì cho mk xl vì làm phiền bạn !
b)2019.(2020+1)-2019.2020
=2019.(2020+1-2020)
=2019.1
=2019
Đặt A= 1/4+1/12+1/36+1/108+1/324 +1/972
=1/4.(1+1/3+1/9+1/27+1/81+1/243)
=1/4(1+1/3 +1/3^2 +1/3^3 +1/3^4 +1/3^5)
gọi M=1+1/3+1/3^2+1/3^3+1/3^4+1/3^5
3M=3+1+1/3+1/3^2+1/3^3+1/3^4
3M-M=(3+1+1/3+1/3^2+1/3^3+1/3^4)-(1+1/3+1/3^2+1/3^3+1/3^4+1/3^5)
2M=3-1/3^5
M=3/2-1/3^5.2
A=1/4.(3/2-1/3^5.2)
A=3/8-1/1944=91/243
Vậy .......
Chúc bạn học tốt .....^-^
\(3^{2x+1}+9^x=324\)
\(3^{2x}.3+3^{2x}=324\)
\(3^{2x}.\left(3+1\right)=324\)
\(3^{2x}.4=324\)
\(3^{2x}=81\)
\(3^{2x}=3^4\)
\(\Rightarrow2x=4\)
\(\Rightarrow x=2\)
vậy \(x=2\)
32x+1 + 9x = 324
9x lớn nhất là 81 trong phép cộng trên
9x = 92 = 81
x = 2
\(\left(-2\right)^4.3^{x-1}=324\)
\(16.3^{x-1}=324\)
\(3^{x-1}=\frac{324}{16}\)
\(3^x:3=\frac{81}{4}\)
\(3^x=\frac{243}{4}\left(vl\right)\)
(-2)4.3x-1=324 => 16.3x-1 = 324 => 3x-1 = 324:16 => 3x-1 = 81/4 => 3x:3 = 81/4 => 3x = 81/4.3 => 3x =243/4 (tự tính tiếp nhé bạn) ...
\(\dfrac{-32}{-384}-1\)
\(=\dfrac{32}{384}-1\)
\(=\dfrac{32:32}{384:32}-1\)
\(=\dfrac{1}{12}-1\)
\(=\dfrac{1-12}{12}\)
\(=-\dfrac{11}{12}\)
Ta có:
\(\dfrac{1}{430}\)+\(\dfrac{1}{324}\)
=\(\dfrac{162}{69660}\)+\(\dfrac{215}{69660}\)
=\(\dfrac{162+215}{69660}\)
=\(\dfrac{377}{69660}\)
\(\dfrac{1}{430}+\dfrac{1}{324}\)
\(=\dfrac{162}{69660}+\dfrac{215}{69660}\)
\(=\dfrac{377}{69660}\)