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428+2*(x-3) = 28
2*(x-3) = 28-428
2*(x-3) = -400
x-3 = -400:2
x-3 = -200
x = -200+3
x = -197
Vậy x = -197
428+2.(x-3)=28
2.(x-3)=28-428
2.(x-3)= -400
(x-3)= -400:2
(x-3)= -200
x= -200+3
x= -197
2*(x-3)=28-428
2*(x-3)=-400
x-3 =-400:2
x-3=-200
x =-200+3
x=-197
Vậy x=-197
k mk nhá bn
a)x:13=41 c)1428:x=14
x=41x13=533 x=1428:14=102
d)8(x-3)=0
Suy ra: x-3=0 x=0+3=3
a, x : 13 = 41
x = 41 x 13
x = 533
b, 1428 : x = 14
x = 1428 : 14
x = 102
c, 8(x - 3) = 0
x - 3 = 0 x 8
x - 3 = 0
x = 0 + 3
x = 3
x-6-(48-24x2:6-3)=100
x-6-(48-8-3)=100
x-6-37=100
x-6=137
x=137+6=143
Vậy x=143
20-[7x(X-3)+4]=2
7x(X-3)+4=20-2
7x(X-3)+4=18
7x(X-3)=14
X-3=14:7
X-3=7
X=7+3=10
Vậy X=10
[(6.X-39):3].28=5628
(6.X-39):3=5628:28
(6.X-39):3=201
6.X-39=201.3=603
6.X=603+39
6.X=642
X=642:6=107
Vậy x=107
1) \(x-6-\left(48-24.2:6-3\right)=100\Rightarrow x-6-\left(48-8-3\right)=100\)
\(\Rightarrow x-6-37=100\Rightarrow x=100+37+6=143\)
2) \(20-\left[7\left(x-3\right)+4\right]=2\Rightarrow7\left(x-3\right)+4=20-2=18\)
\(\Rightarrow7\left(x-3\right)=18-4=14\Rightarrow x-3=14:7=2\Rightarrow x=2+3=5\)
3) \(\left[\left(6x-39\right):3\right].28=5628\Rightarrow\left(6x-39\right):3=5628:28=201\)
\(\Rightarrow6x-39=201.3=603\Rightarrow6x=603+39=642\Rightarrow x=642:6=107\)
(428-4x) .27=1728
<=> 428-4x = 1728 : 27
<=> 428-4x = 64
<=> 4x = 428 - 64
<=> 4x = 364
<=> x= 364 :4
<=> x= 91
Vậy x= 91
x.x2.x3=64
<=> x1+2+3 = 64
<=> x6 = 64
<=> x6= (+ - 2 )6
=> x = cộng trừ 2
Vậy x= cộng trừ 2
a, 3(x+2)-6(x-5)=2(5-2x)
3x+6-6x+30=10-4x
3x+6-6x+30-10+4x=0
3x-6x+4x+6+30-10=0
x+26=0
x= -26
b, (-2x)(-4x)+28=100
8x2 + 28=100
8x2 = 72
x2 = 9
=> x=3 hoặc x= -3
a/ 3(x+2) - 6(x-5) = 2(5-2x)
<-> 3x+6-6x+30 = 10-4x
<-> x = -26
b/ (-2x)(-4x) + 28 = 100
<-> 8x = 72
<-> x = 9
Giải:
a) x ⋮ 12
x ⋮ 21 ⇒x ∈ BC(12;21;28)
x ⋮ 28
12=22.3
21=3.7
28=22.7
⇒BCNN(12;21;28)=22.3.7=84
⇒BC(12;21;28)=B(84)={0;84;168;...}
Vậy x ∈ {0;84;168;...}
b) x : 2 (dư 1) ⇒x-1 ⋮ 2
x : 3 (dư 1) ⇒x-1 ⋮ 3
x : 4 (dư 1) ⇒x-1 ⋮ 4 ⇒x-1 ∈ BC(2;3;4;5)
x : 5 (dư 1) ⇒x-1 ⋮ 5
2=2
3=3
4=22
5=5
⇒BCNN(2;3;4;5)=22.3.5=60
⇒BC(2;3;4;5)=B(60)={0;60;120;180;...}
⇒x-1 ∈ {0;60;120;180;...}
⇒x ∈ {1;61;121;181;...}
Mà 100<x<150
⇒x=121
1428-428(x-3)=2.(100-28)
1428-428(x-3)=2.72
1428-428(x-3)=144
428(x-3)=1428-144
428(x-3)=1284
x-3=1284:428
x-3=3
x=3+3
x=6
\(1428-428\left(x-3\right)=2.72\)
\(1428-428\left(x-3\right)=144\)
\(428\left(x-3\right)=1284\)
\(x-3=3\)
\(x=6\)