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=1,3125
giúp tớ nhé ,tớ mới bị từ 290
ai giúp mình mình giúp lại
cảm ơn trước
\(125.5>5^n>5.25\)
=> \(5^3.5>5^n>5.5^2\)
=>\(5^4>5^n>5^3\)
=> \(4>n>3\)
=> \(n=2\)
Chúc bạn Hk tốt!!!
\(7x\left(2+x\right)-7x\left(x+3\right)=14\)
\(\Rightarrow7x\left[\left(2+x\right)-\left(x+3\right)\right]=14\)
\(\Rightarrow7x\left[2+x-x-3\right]=14\)
\(\Rightarrow7x.\left(-1\right)=14\)
\(\Rightarrow-7x=14\)
\(\Rightarrow x=14:-7\)
\(\Rightarrow x=-2\)
Vậy x = -2
_Chúc bạn học tốt_
a: \(=\dfrac{2^5\cdot3^5\cdot2^{12}\cdot2^{16}\cdot5^{16}}{2^{30}\cdot3^{10}\cdot5^{16}}=\dfrac{2^{33}\cdot3^5}{2^{30}\cdot3^{10}}=\dfrac{8}{243}\)
c: \(=\dfrac{4^7\cdot3^{12}\cdot5^4+3^{12}\cdot5^6\cdot4^7}{2^{14}\cdot3^{14}\cdot5^4+2^{14}\cdot3^{14}\cdot5^6}\)
\(=\dfrac{2^{14}\cdot3^{12}\cdot5^4\left(1+25\right)}{2^{14}\cdot3^{14}\cdot5^4\left(1+25\right)}=\dfrac{1}{9}\)
\(\dfrac{8^2\cdot5^4}{2^5\cdot25}=\dfrac{8\cdot8\cdot5^2\cdot5^2}{2^3\cdot2^2\cdot5^2}=\dfrac{2^3\cdot2^3\cdot5^2\cdot5^2}{2^3\cdot2^2\cdot5^2}=2\cdot5^2=2\cdot25=50\)
=>5.(52)x+1=(53)x
=>5.52x+2=53x
=>52x+2+1=53x
=>2x+2+1=3x
=>3=3x-2x
=>x.(3-2)=3
=>x=3
5.25^x+1=125^x
5(5^2)^x+1=(5^3)^x
5.5^2x+2=5^3x
5^2x+2+1=5^3x
suy ra 2x+3=3x
2x-3x=-3
-x=-3
x=3
\(\left(\dfrac{1}{2}\right)^3.\left(-2\right)^2-25\%+\dfrac{3}{5}.25-30\\ =\dfrac{1}{2}.\left(\dfrac{1}{2}\right)^2.\left(-2\right)^2-\dfrac{25}{100}+\dfrac{3}{5}.25-30\\ =\left(\dfrac{1}{2}\right).\left[\dfrac{1}{2}.\left(-2\right)\right]^2-\dfrac{1}{4}+15-30\\ =\dfrac{1}{2}.\left(-1\right)^2-\dfrac{1}{4}+15-30\\ =\dfrac{1}{2}-\dfrac{1}{4}+15-30\\ =\dfrac{1}{4}+15-30=\dfrac{61}{4}-30=-\dfrac{59}{4}\)
ĐKXĐ: \(x\ne0\)
\(\frac{7x}{10}=\frac{14}{x}\Rightarrow7x^2=140\Rightarrow x^2=20\Rightarrow\orbr{\begin{cases}x=2\sqrt{5}\\x=-2\sqrt{5}\end{cases}}\)
Vậy ............................... chúc bn hok tốt
\(\frac{7x}{5}+\frac{14}{x}\)
=>\(7x.x=5.14\)
=>\(7x^2=70\)
=>\(x^2=70:7=10\)
=>\(x=\sqrt{x}\)
\(-14:4,1=-7x:5.25\)
\(-7x:5.25=-\frac{140}{41}\)
\(-7x:5=-\frac{140}{41}:25\)
\(-7x:5=-\frac{140}{41}.\frac{1}{25}\)
\(-7x:5=-\frac{28}{205}\)
\(-7x=-\frac{28}{205}.5\)
\(-7x=-\frac{28}{41}\)
\(\Rightarrow x=-\frac{28}{41}:-7\)
\(x=-\frac{28}{41}.-\frac{1}{7}\)
\(x=\frac{4}{41}\)
Vậy x=4/41
Chúc bạn học tốt