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a) \(64\cdot25+35\cdot25+25=25\cdot\left(64+35+1\right)=2500\)
b) \(92\cdot42+32\cdot8+5\cdot16\)
\(=8\cdot21\cdot23+16\left(16+5\right)\)
\(=8\cdot21\cdot23+16\cdot21\)
\(=8\cdot21\cdot\left(23+2\right)\)
\(=8\cdot21\cdot25\)
\(=2\cdot21\cdot4\cdot25\)
\(=42\cdot100\)
\(=4200\)
c) \(\left(42\cdot43+43\cdot57+43\right)-360:4\)
\(=\left[43\cdot\left(42+57+1\right)\right]-360:4\)
\(=4300-90\)
\(=4210\)
a) (42 x 43 + 43 x 57 + 43) - 360 : 4
= 43 x ( 42 x 57) + 43 - 360 :4
= 43 x 99 + 43 - 90
= 4257 + 43 - 90
= 4300 - 90
= 4210
b) (372 - 194 x 4) + (981 : 9 - 13)
= (372 - 776) + (109 - 13)
= -404 + 96
= -308
c) 456 : 2 x 18 + 456 : 3 - 102
= 228 x 18 + 152 - 102
= 4104 + 152 - 102
= 4256 - 102
= 4154
a.58+42+32+58+72+42 b.133:7+154:7+413:7:4
=(58+42)+(58+42)+72+32 =133:7+154:7+413:4:7
=100+100+72+32 = 133:7+154:7+103,25 :7
=200+104 = (133+154+103,25):7
=304 = 390,25:7
= 55.75
\(=-19+360:\left(35-34+43\right)=-19+360:44=-\dfrac{119}{11}\)
Tìm x thuộc N biết:
X+245=43×11
=>x+245=473
=>x=228
X-382=159:3
=>x-382=53
=>x=53+382=438
7×X+2×X=918
=>(7+2).x=918
=>9x=918
=>x=918:9=102
3×(X-2)+150=240
=>3.(x-2)=240-150
=>3.(x-2)=90
=>x-2=90:3=30
=>x=30+2=32
(X+13):5=12
=>(x+13)=12.5
=>x+13=60
=>x=60-13
=>x=47
Bấm **** nha
360:(X-7)=90
X+245=43*11
X+245=473
x=473-245
X=228
X-382=159:3
X-382=53
X=382+53
X=435
7*X+2*X=918
(7+2)*X=918
9*X=918
X=918:9
X=102
3*(X-2)+150=240
3*(X-2)=240-150
3*(X-2)=90
X-2=90:3
X-2=30
X=30-2
X=28
(X+13):5=12
X+13=12*5
X+13=60
X=60-13
X=47
360:(X-7)=90
X-7=360:90
X-7=4
X=7+4
X=11
133:7+154:7+413:7
= 19 + 22 + 59
= 100
(42.43+43.57+43)-360:4
= (42.43+43.57+43 . 1 )-360:4
= [ 43 . ( 42 + 57 + 1 ) - 360 : 4
= [ 43 . 100 ] - 360 : 4
= 4300 - 360 : 4
= 4300 - 90
= 4210
133:7+154:7+413:7
= ( 133 + 154 + 413 ) : 7
= 700 : 7
=100